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Test: Mole Concept, Volumetric & Redox - 2 - Chemistry MCQ


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30 Questions MCQ Test Physical Chemistry - Test: Mole Concept, Volumetric & Redox - 2

Test: Mole Concept, Volumetric & Redox - 2 for Chemistry 2024 is part of Physical Chemistry preparation. The Test: Mole Concept, Volumetric & Redox - 2 questions and answers have been prepared according to the Chemistry exam syllabus.The Test: Mole Concept, Volumetric & Redox - 2 MCQs are made for Chemistry 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Mole Concept, Volumetric & Redox - 2 below.
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Test: Mole Concept, Volumetric & Redox - 2 - Question 1

20 ml of xM HCl neutralizes completely 10 ml of 0.1M NaHCO3 and a further 5ml of 0.2M Na2CO3 solution to methyl orange end point. The value of x is:

Test: Mole Concept, Volumetric & Redox - 2 - Question 2

The equivalent weight of Fe3O4 in the reaction Fe3O4 + KMnO4 → Fe2O3 + MnO2 would be

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Test: Mole Concept, Volumetric & Redox - 2 - Question 3

0.3g of an oxalate salt was dissolved in 100 ml solution. The solution required 90 ml of N/20 KMnO4 for complete oxidation. The % of oxalateion in salt is:

Test: Mole Concept, Volumetric & Redox - 2 - Question 4

The number of moles of KMnO4 that will be needed to react with one mole of sulphite ion in acidic solution is:

Test: Mole Concept, Volumetric & Redox - 2 - Question 5

A certain compound has the molecular formula X4O6. If 10g of compound contains 5.62g of x, the atomic mass of x is approx:

Test: Mole Concept, Volumetric & Redox - 2 - Question 6

Starch paper is used to test for the presence of [NCERT 1979]

Test: Mole Concept, Volumetric & Redox - 2 - Question 7

When a solution of NaOH and Na2CO3 is titrated against standard HCl, the end point due to phenolphthalein is obtained after the reaction:

Test: Mole Concept, Volumetric & Redox - 2 - Question 8

Cu2+ + I → Cu+ + I2, I2 + Na2S2O3 → NaI + Na2S4O6

If the moles of Cu2+ in above reaction consumed is ‘a’ then equivalents of Na2S4O6 will be:

Test: Mole Concept, Volumetric & Redox - 2 - Question 9

In the above equation if moles required of S2O32– to titrate I2 was 2 then what were the moles of IO3 used:

IO3 + I + H+ → I2 + H2O, I2 + S2O32– → I + S4O62–

Test: Mole Concept, Volumetric & Redox - 2 - Question 10

Then factor Of FeS2 in the following reaction  FeS2 → Fe3+ + SO2 would be:

Test: Mole Concept, Volumetric & Redox - 2 - Question 11

Fe0.94O → Fe3+, equivalent weight of reactants will be:

Test: Mole Concept, Volumetric & Redox - 2 - Question 12

H3PO4 is a tribasic acid and one of its salt is NaH2PO4 . What volume of 1M NaOH solution should be added to 12g of NaH2PO4 to convert it into Na3PO4:

Test: Mole Concept, Volumetric & Redox - 2 - Question 13

Sulphuryl chloride SO2Cl2, reacts with H2O to give mixture of H2SO4 and HCl. Aqueous solution of 1mole of SO2Cl2 will be neutralized by:

Test: Mole Concept, Volumetric & Redox - 2 - Question 14

When Cr2O72– ion act as an oxidant in acidic medium, Cr3+ ion is formed. The number of moles of Sn2+ that are oxidized to Sn4+ by one mole of Cr2O72– ion would be:

Test: Mole Concept, Volumetric & Redox - 2 - Question 15

A 0.518g sample of limestone is dissolved in HCl and then calcium is precipitated as CaC2O4. After filtering and washing the precipitate it requires 60 ml of 0.25N KMnO4 solution acidified with H2SO4 to titrate it as MnO4Θ + H+ + C2O42– → Mn2+ +CO2 +2H2O. The % of CaO in sample is:

Test: Mole Concept, Volumetric & Redox - 2 - Question 16

Hydrogen peroxide in aqueous solution decomposes on warming to give oxygen acc. To the equation , 2H2O2 (aq.) →  2H2O (l) + O2 (g) . Under conditions where 1 mole of gas occupies 24dm3. 100cm3 of xM solution of H2O2 produces 3dm3 of O2. The x is:

Detailed Solution for Test: Mole Concept, Volumetric & Redox - 2 - Question 16

Test: Mole Concept, Volumetric & Redox - 2 - Question 17

What volume of O2 measured at standard conditions will be formed by the action of 100ml of 0.5N KMnO4 on H2O2 in an acid solution. The skeleton equation for the reaction is:

KMnO4 + H2SO4 + H2O2 → KHSO4 + MnSO4 + H2SO4 +H2O + O2

Test: Mole Concept, Volumetric & Redox - 2 - Question 18

The Equivalent weight of the salt KHC2O4.H2C2O4.4H2O used as reducing agent is:

Detailed Solution for Test: Mole Concept, Volumetric & Redox - 2 - Question 18

Correct Answer :- B

Explanation : equivalent weight for a reducing agent= molecular mass/ electron lost

 

In the redox reaction it can lose up to 4 electrons

and the molecular weight of KHC2O4. H2C2O4. 4H2O = 290g

so 

equ weight = 290/4 = 72.5 g

Test: Mole Concept, Volumetric & Redox - 2 - Question 19

If the eq. weight of a compound ‘A’ is MA/4 when it reacts with compound ‘B’ whose eq. weight is MB/5 then 4 mole of ‘A’ requires:

Test: Mole Concept, Volumetric & Redox - 2 - Question 20

Density of air is 0.001293 g/cc. Its vapour density is:

Test: Mole Concept, Volumetric & Redox - 2 - Question 21

In which Mode of expression, the concentration of a solution remain independent of temperature

Detailed Solution for Test: Mole Concept, Volumetric & Redox - 2 - Question 21

Molality is the mode of expression ,the concentration of the solution remains independent of temperature.

Test: Mole Concept, Volumetric & Redox - 2 - Question 22

A gaseous oxide contains 30.4% of nitrogen, one molecule of which contains one nitrogen atom. The density of the oxide relative to oxygen is:

Test: Mole Concept, Volumetric & Redox - 2 - Question 23

When KMnO4 acts as an oxidant and ultimately forms [MnO4]2–, MnO2, Mn2O3 and Mn2+, then number of electrons transferred in each case respectively is:

Test: Mole Concept, Volumetric & Redox - 2 - Question 24

Which of the following is a redox reaction:

Test: Mole Concept, Volumetric & Redox - 2 - Question 25

Which reaction is possible at anode:

Test: Mole Concept, Volumetric & Redox - 2 - Question 26

Which of the following reaction depicts the oxidizing behaviour of H2SO4:

Test: Mole Concept, Volumetric & Redox - 2 - Question 27

In the standardization of Na2S2O3 using K2Cr2O7 by iodometry, the equivalent weight of K2Cr2O7 is:

Test: Mole Concept, Volumetric & Redox - 2 - Question 28

The reaction;

is an example of 

Test: Mole Concept, Volumetric & Redox - 2 - Question 29

are two isotopes of chlorine. If average atomic mass is 35.5 then ratio of these two isotopes is:

Test: Mole Concept, Volumetric & Redox - 2 - Question 30

A gaseous mixture contains oxygen and nitrogen in the ratio of 1:4 by weight. Therefore, the ratio of their number of molecules is

Detailed Solution for Test: Mole Concept, Volumetric & Redox - 2 - Question 30

Take a hypothetical sample of 5.000 g of the mixture. That consists of 1.000 g O2 and 4.000 g N2.

(1.000 g O2) / (31.99886 g O2/mol) = 0.03125 mol O2

(4.000 g N2) / (28.01344 g N2/mol) = 0.14289 mol N2

The number of molecules is proportional to the number of moles, so the ratio of molecules is: 
(0.03125 mol O2) / (0.14289 mol N2) = 0.2187now you can check it from options ie answer is 7:32

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