General Organic Chemistry MCQ -1 (Advanced)

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This mock test of General Organic Chemistry MCQ -1 (Advanced) for JEE helps you for every JEE entrance exam. This contains 15 Multiple Choice Questions for JEE General Organic Chemistry MCQ -1 (Advanced) (mcq) to study with solutions a complete question bank. The solved questions answers in this General Organic Chemistry MCQ -1 (Advanced) quiz give you a good mix of easy questions and tough questions. JEE students definitely take this General Organic Chemistry MCQ -1 (Advanced) exercise for a better result in the exam. You can find other General Organic Chemistry MCQ -1 (Advanced) extra questions, long questions & short questions for JEE on EduRev as well by searching above.

QUESTION: 1

Which of the following statements are incorrect with respect to the allotropes of carbon?
I) Diamond is extremely hard while graphite is soft
II) Diamond is ionic but graphite is covalent
III) Diamond is a non-conductor but graphite is a good conductor of electricity
IV) Diamond has a layered structure while graphite has a network structure

A.
I and II
B.
I, II and IV
C.
I, III and IV
D.
II and IV

Solution: Here the correct answer is C as in the question we can see that there is S. I. R effect so the c 1 and c5 bond lengths are of the same length and longer than the c3 bond length.... M.

*Multiple options can be correct

QUESTION: 2

Choose the incorrect statement:

A.
Salicylic acid (o–Hydroxybenzoic acid) is much stronger than its m-,p-isomers and benzoic acid itself.
B.
Acidity of salicylic acid is due to steric inbibition of re3sonance, as – OH group forces – COOH out of the plane of ring
C.
The orbitals which are in the same plane take part in resonance
D.
All the resonating structures have real existence

Solution:

In salicylic acid, there is H-bonding in conjugate base.

*Multiple options can be correct

QUESTION: 3

In which of the following pairs the first one is the stronger base than second.

A.
CH₃CHOO, HCOO
B.
HO,NH
C.
CH₂=CH: , H – C = C
D.
CH₃NH₂, CH₃,OH

Solution:

*Multiple options can be correct

QUESTION: 4

Which statement among the followijng are corect?

A.
Hydration effect stabilises dimethyl ammonium ion more than trimethyl ammonium ion
B.
In chlorobenzene as there is no hydration effect so, trimethyl ammonium ion gets less stabillised than dimethyl ammonium ion
C.
RCONH₂ is feebly acidic with respect to RCOOH
D.
CH₃ > NH₂ > OH is the basicityh order

Solution:

*Multiple options can be correct

QUESTION: 5

Resonance structures of a molecule should have.

A.
Identical arrangement of atoms
B.
Nearly the same energy content
C.
The same number of paired electrons
D.
Identical bonding

Solution: Resonating structures must have identical arrangements of atoms, nearly same energy content and same number of unpaired electrons .

QUESTION: 6

The correct heat of hydrogenation order is (p) 1,3-Pentadiene (q) 1,3-Butadiene (r) 2,3-Dimethyl-1, 3-butadiene (s) Propadiene

A.
p > q > r > s
B.
s > q > p > r
C.
q > s > p > r
D.
none

Solution:

QUESTION: 7

An organic compound on analysis gave C = 48 gm, H = 8 gm and N = 56 gm. Volume of 1.0 g of the compound was found to be 200 ml at NTP. Molecular formula of the compound is

A.

C₄H₈N₄
B.

C₂H₄N₂
C.

C₁₂H₂₄N₁₂
D.

C₁₆H₃₂N₁₆

Solution:

*Multiple options can be correct

QUESTION: 8

The most stable resonating structure of following compound is O =

Solution:

Maximum charge separation stability increases

Then and is (D).

*Multiple options can be correct

QUESTION: 9

2.34 The correct resonation structre of 1, 3-butadiene is -

A.
B.
C.
D.
None of these

Solution:

*Multiple options can be correct

QUESTION: 10

The correct stable resonating structure of benzene is -

A.
B.
C.
D.
None of these

Solution:

QUESTION: 11

Which resonating sturcture is not correct

Solution:

QUESTION: 12

Match the following

p) m is more
(q) m is less
(r) Larger C– N compared to C – NO₂
(s) Larger C – N bond largteer compared to aniline

A.
(A) → s

(B) → r

(C) → p

(D) → q
B.
(A) → q

(B) → p

(C) → s

(D) → r
C.
(A) → r

(B) → p

(C) → q

(D) → s
D.
(A) → p

(B) → s

(C) → r

(D) → q

Solution:

Stearic inhibition of resonance cause no change in bond length.

QUESTION: 13

Match the pKa values with the given compounds

(p) 4
(q) 9
(r) 5
(s) 0.74

A.
(A) → s

(B) → r

(C) → q

(D) → p
B.
(A) → q

(B) → r

(C) → p

(D) → s
C.
(A) → q

(B) → p

(C) → r

(D) → s
D.
none of these

Solution:

Remember

NH is acidic instead of basic due to three resonating of Conjugate base. As Shown in the adjacent diagram

It shows that conjugate base is very stable. The basic site in phthalimide is 0 not be N atom. Again it is due to resonance stabilisation

QUESTION: 14

For the compound :

Give the number

A.
1 for presence of resonance only
B.
2 for presence of resonance and hyperconjugation only
C.
3 for presence of resonance, hyperconjugation and inductive effect
D.
4 for presence of resonance hyperconjugation, inductive effect and electromaric efffect