MCQ (Previous Year Questions) - Biomolecules (Level 2)


8 Questions MCQ Test Chemistry for JEE Advanced | MCQ (Previous Year Questions) - Biomolecules (Level 2)


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Attempt MCQ (Previous Year Questions) - Biomolecules (Level 2) | 8 questions in 16 minutes | Mock test for JEE preparation | Free important questions MCQ to study Chemistry for JEE Advanced for JEE Exam | Download free PDF with solutions
QUESTION: 1

Which of the following pairs given positive Tollen’s test ?          [IIT 2004]

Solution: Aldehydes and α- hydroxy ketones give positive Tollen’s test. Glucose has an aldehydic group and fructose is an α hydroxy ketone.
QUESTION: 2

The two forms of D-glucopyranose obtained from the solution of D-glucose are called:        [IIT 2005]

Solution: The two forms of D glucopyranose are called ANOMERS since they differ at configuration at the first carbon.
QUESTION: 3

                 [IIT 2006]

Solution:
QUESTION: 4

Cellulose upon acetylation with excess acetic anhydride/H2SO4 (catalytic) gives cellulose triacetate whose
structure is                 [IIT 2007]

Solution:
QUESTION: 5

Among cellulose, poly (vinyl chloride), nylon and natural rubber, the polymer in which the intermolecular
force of attraction is weakest is :                 [IIT 2008]

Solution:
*Multiple options can be correct
QUESTION: 6

The correct statement(s) about the following sugars X and Y is (are)            [IIT 2009]

Solution: You can identify a sugar by looking for the anomeric carbon. (The anomeric C is the first stereocenter of the molecule.) If that stereocenter has an OH group coming off of it then it is a reducing sugar. Hence (B) is correct. As for (C) alpha bonds are formed when the OH on the carbon-1 is below the glucose ring. While beta bonds are formed when the OH is above the plane. Hence the stereochemistry of the two compounds show that Y has a Beta linkage. Hope it helps.
QUESTION: 7

The correct statement about the following disaccharide is               [IIT 2010]

Solution:
QUESTION: 8

The following carbohydrate is

Solution: It is bita glucose or bita pyranose so an aldohexose.
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