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*Answer can only contain numeric values

QUESTION: 1

**Retro IIT-JEE Advanced (Compilation of Last 10 Years Questions)**

**IIT JEE (Main & Advanced) past year questions with solutions & answer key**

**Retro IIT JEE (Main and Advanced) have questions from previous/past (10 to 13 years) papers of IIT JEE (Main and Advanced) with solutions,**

**The following set of questions contain previous/past (10 to 13 years) questions of IIT JEE (Main and Advanced) of Chapter "Structure of Atom" with solutions **

**Q. In an atom, the total number of electrons having quantum numbers n = 4,| m _{l} | = 1 and ms = - 1/2 is**

**(2014 Adv., Integer Type)**

Solution:

|m_{l}| = 1thus, magnetic quantum number = + 1 and -1

n = 4 can have suborbits

Thus underlined electrons with (m, = - 1, + 1) and spin - (**1/2) **are six.

*Answer can only contain numeric values

QUESTION: 2

The atomic masses of He and Ne are 4 and 20 amu, respectively. The value of the de-Broglie wavelength of He gas at -73°C is "M" times that of the de-Broglie wavelength of Ne at 727°C. M is

**(2013 Adv., Integer Type)**

Solution:

QUESTION: 3

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is [a_{0} is Bohr radius]

**(2012, Single Option Correct Type)**

Solution:

According to Bohr's model

*Answer can only contain numeric values

QUESTION: 4

The maximum number of electrons that can have principal quantum number, n = 3 and spin quantum number, m_{s} = - 1 / 2 , is

**(2011, Integer Type)**

Solution:

When n = 3, l = 0,1,2, i.e. there are 3s, 3p and 3d orbitals. If all these orbitals are completely occupied as

Total 18 electrons, 9 electrons with s = and 9 with s =

**Alternatively**

In any nth orbit, there can be a maximum of 2n^{2} electrons. Hence, when n = 3, number of maximum electrons = 18. Out of these 18 electrons, 9 can have spin = and remaining nine with spin =

*Answer can only contain numeric values

QUESTION: 5

The work function of some metals is listed below. The number of metals which will show photoelectric effect when light of 300 nm wavelength falls on the metal is

**(2011, integer Type)**

Solution:

For photoelectric effect to occur, energy of incident photons must be greater than work function of metal. Hence, only Li, Na, K and Mg have work functions less than 4.14V.

QUESTION: 6

**Direction (Q. Nos. 6-8) This section contains a paragraph, wach describing theory, experiments, data etc. three Questions related to paragraph have been given.Each question have only one correct answer among the four given ptions (a),(b),(c),(d)**

The hydrogen-like species Li^{2+} is in a spherically symmetric state S_{1}, with one radial node. Upon absorbing light the ion undergoes transition to a state S_{2}. The state S_{2} has one radial node and its energy is equal to the ground state energy of the hydrogen atom.

**Q. The stateS _{1} is**

Solution:

S_{1} is spherically symmetrical state, i.e. it corre spo nd to a s-orbital. Also it has one radial node.

Number of radial nodes = n - I - I

n - 0 - 1 = 1

n = 2, i.e. S_{1} = 2s orbital.

QUESTION: 7

The hydrogen-like species Li^{2+} is in a spherically symmetric state S_{1}, with one radial node. Upon absorbing light the ion undergoes transition to a state S_{2}. The state S_{2} has one radial node and its energy is equal to the ground state energy of the hydrogen atom.

**Q. Energy of the state S _{1} in units of the hydrogen atom ground state energy is **

Solution:

Ground state energy of electron in H-atom (E_{H})

QUESTION: 8

The hydrogen-like species Li^{2+} is in a spherically symmetric state S_{1}, with one radial node. Upon absorbing light the ion undergoes transition to a state S_{2}. The state S_{2} has one radial node and its energy is equal to the ground state energy of the hydrogen atom.

**Q. The orbtial angular momentum quantum number of the state S _{2} is**

Solution:

QUESTION: 9

Match the entries in Column I with the correctly related quantum number(s) in Column II.

Solution:

(ii) To describe a one electron wave function, three quantum numbers n, I and m are needed. Further to abide by Pauli exclusion principle, spin quantum number (s) is also needed,

(iii) For shape, size and orientation, only n, I and m are needed.

(iv) Probability density can be determined if n, I and m are known

QUESTION: 10

According to Bohr’s theory

E_{n} = Total energy, K_{n} = Kinetic energy

V_{n} = Potential energy, r^{n} = Radius of nth orbit

Match the following

Solution:

QUESTION: 11

The number of radial nodes in 3s and 2p respectively are

**(2005, Single Option Correct Type)**

Solution:

The number of radial nodes is given by expression (n - l - 1).

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