JEE Exam  >  JEE Tests  >  JEE Main 2016 April 3 Paper & Solutions - JEE MCQ

JEE Main 2016 April 3 Paper & Solutions - JEE MCQ


Test Description

30 Questions MCQ Test - JEE Main 2016 April 3 Paper & Solutions

JEE Main 2016 April 3 Paper & Solutions for JEE 2024 is part of JEE preparation. The JEE Main 2016 April 3 Paper & Solutions questions and answers have been prepared according to the JEE exam syllabus.The JEE Main 2016 April 3 Paper & Solutions MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Main 2016 April 3 Paper & Solutions below.
Solutions of JEE Main 2016 April 3 Paper & Solutions questions in English are available as part of our course for JEE & JEE Main 2016 April 3 Paper & Solutions solutions in Hindi for JEE course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt JEE Main 2016 April 3 Paper & Solutions | 90 questions in 180 minutes | Mock test for JEE preparation | Free important questions MCQ to study for JEE Exam | Download free PDF with solutions
JEE Main 2016 April 3 Paper & Solutions - Question 1

A student measures the time period of 100 oscillations of a simple pendulum four times. The data set is 90 s, 91 s, 95 s and 92 s. If the minimum division in the measuring clock is 1 s, then the reported mean time should be :

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 1


Mean deviation = 
L. C. = 1 s.
∴ Required value = 92 ± 2 s

*Multiple options can be correct
JEE Main 2016 April 3 Paper & Solutions - Question 2

A particle of mass m is moving along the side of a square of side ‘a’, with a uniform speed v in the x-y plane as shown in the figure :

Which of the following statements is false for the angular momentum L about the origin? 

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 2

Along CD, ⊥ distance from line of motion =
∴ Magnitude of angular momentum =
Hence (2) is incorrect. 
In option (4) the direction of is incorrect. 

1 Crore+ students have signed up on EduRev. Have you? Download the App
JEE Main 2016 April 3 Paper & Solutions - Question 3

A point particle of mass m, moves along the uniformly rough track PQR as shown in the figure. The coefficient of friction, between the particle and the rough track equals m. The particle is released, from rest, from the point P and it comes to rest at a point R. The energies, lost by the ball, over the parts, PQ and QR, of the track, are equal to each other, and no energy is lost when particle changes direction from PQ to QR.
The values of the coefficient of friction m and the distance x (= QR), are, respectively close to : 

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 3

From work energy theorem and given condition

∴ 

∴ 

JEE Main 2016 April 3 Paper & Solutions - Question 4

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times. Assume that the potential energy lost each time he lowers the mass is dissipated. How much fat will he use up considering the work done only when the weight is lifted up? Fat supplies 3.8 x 107 J of energy per kg which is converted to mechanical energy with a 20% efficiency rate. Take g = 9.8 ms-2 :

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 4

0.2 x 3.8 x 107 x m = 10 x g x 1 x 1000
m =  = 1.289 x 10-2 Kg
= 12.89 x 10-3 Kg

JEE Main 2016 April 3 Paper & Solutions - Question 5

A roller is made by joining together two cones at their vertices O. It is kept on two rails AB and CD which are placed asymmetrically (see figure), with its axis perpendicular to CD and its centre O at the centre of line joining AB and CD (see figure). It is given a light push so that it starts rolling with its centre O moving parallel to CD in the direction shown. As it moves, the roller will tend to:

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 5

If we take ‘r’ as the distance of IAOR from the axis of rotation, then ‘r’ decreases on left side as the object moves forward.
So, for left v = ωr' < ωr (for right point)
So, the roller will turn to the left as it moves forward.

JEE Main 2016 April 3 Paper & Solutions - Question 6

A satellite is revolving in a circular orbit at a height ‘h’ from the earth’s surface (radius of earth R; h <<R). The minimum increase in its orbital velocity required, so that the satellite could escape from the earth’s gravitational field, is close to : (Neglect the effect of atmosphere).

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 6

Orbital velocity v = 
Velocity required to escape

∴ Increase in velocity

JEE Main 2016 April 3 Paper & Solutions - Question 7

A pendulum clock loses 12 s a day if the temperature is 40°C and gains 4s a day if the temperature is 20°C. The temperature at which the clock will show correct time, and the co-efficient of linear expansion (α) of the metal of the pendulum shaft are respectively:

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 7

Time period of pendulum,



Thus, the coefficient of linear expansion in pendulum clock = 1.85 x 10-5/C

JEE Main 2016 April 3 Paper & Solutions - Question 8

An ideal gas undergoes a quasi static, reversible process in which its molar heat capacity Cremains constant. If during this process the relation of pressure P and volume V is given by PVn = constant, then n is given by (Here CP and CV are molar specific heat at constant pressure and constant volume, respectively) :

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 8

JEE Main 2016 April 3 Paper & Solutions - Question 9

‘n’ moles of an ideal gas undergoes a process A → B as shown in the figure. The maximum temperature of the gas during the process will be :

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 9

Equation of line AB



(For maximum temperature) 

(Condition for maximum temperature)

JEE Main 2016 April 3 Paper & Solutions - Question 10

A particle performs simple harmonic motion with amplitude A. Its speed is trebled at the instant that it is at a distance 2A/3 from equilibrium position. The new amplitude of the motion is :

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 10

2 = k
Total initial energy = 1/2 kA2
at x = 2A/3, potential energy = 
Kinetic energy at

If speed is tripled, new Kinetic energy = 
∴ New total energy = 
If next amplitude = A';  then 

JEE Main 2016 April 3 Paper & Solutions - Question 11

A uniform string of length 20 m is suspended from a rigid support. A short wave pulse in introduced at its lowest end. It starts moving up the string. The time taken to reach the support is:
(take g = 10 ms-2)

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 11


JEE Main 2016 April 3 Paper & Solutions - Question 12

The region between two concentric spheres of radii ‘a’ and ‘b’, respectively (see figure), has volume charge density ρ = A/r, where A is a constant and r is the distance from the centre. At the centre of the spheres is a point charge Q. The value of A such that the electric field in the region between the spheres will be constant, is :

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 12

Charge in the shaded region = 
Total field at P = 

For field to be independent of r : Q = 2πAa2

JEE Main 2016 April 3 Paper & Solutions - Question 13

A combination of capacitors is set up as shown in the figure. The magnitude of the electric field due to a point charge Q (having a charge equal to the sum of the charges on the 4 μF and 9 μF capacitors), at a point distant 30 m from it, would equal:

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 13


Charges on 3 μF = 3 μF x δV = 24 μC 
∴ Charge on 4 μF = Charge on 12 μF = 24 μC
Charge of 3 μF = 3 μF ´ 2V = 6 μC
Charge of 9 μF = 9 μF ´ 2V = 18 mC
Charge on 4 μF + Charge on 9 μF = (24 + 18) μF = 42 μC
∴ Electric field at 30 m = 9 x 103 

JEE Main 2016 April 3 Paper & Solutions - Question 14

The temperature dependence of resistances of Cu and undoped Si in the temperature range 300-400 K, is best described by :

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 14

JEE Main 2016 April 3 Paper & Solutions - Question 15

Two identical wires A and B, each of length  ‘’, carry the same current I. Wire A is bent into a circle of radius R and wire B is bent to form a square of side ‘a’. If BA and BB are the values of magnetic field at the centres of the circle and square respectively, then the ratio BA / Bis:

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 15




JEE Main 2016 April 3 Paper & Solutions - Question 16

Hysteresis loops for two magnetic materials A and B are given below :
These materials are used to make magnets for electric generators, transformer core and electromagnet core.
Then it is proper to use :

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 16

Conceptual (Requires low retentivity and low coercivity)

JEE Main 2016 April 3 Paper & Solutions - Question 17

An arc lamp requires a direct current of 10 A at 80 V to function. It is connected to a 220 V (rms), 50 Hz AC supply, the series inductor needed for it to work is close to:

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 17





∴ 

JEE Main 2016 April 3 Paper & Solutions - Question 18

Arrange the following electromagnetic radiations per quantum in the order of increasing energy :
A : Blue light  
B : Yellow light  
C : X-ray  
D : Radiowave

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 18

JEE Main 2016 April 3 Paper & Solutions - Question 19

An observer looks at a distant tree of height 10 m with a telescope of magnifying power of 20. To the observer the tree appears :

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 19

JEE Main 2016 April 3 Paper & Solutions - Question 20

The box of a pin hole camera, of length L, has a hole of radius a. It is assumed that when the hole is illuminated by a parallel beam of light of wavelength λ the spread of the spot (obtained on the opposite wall of the camera) is the sum of its geometrical spread and the spread due to diffraction. The spot would then have its minimum size (say bmin) when :

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 20





[By substituting for a from (ii) in (i)] 
∴ The radius of the spot = 

JEE Main 2016 April 3 Paper & Solutions - Question 21

Radiation of wavelength λ, is incident on a photocell. The fastest emitted electron has speed v. If the wavelength is changed to 3λ/4, the speed of the fastest emitted electron will be:

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 21

.... (i)
 ...... (ii)
(ii) - (i) gives


.... (iv)
combining (iii) & (iv)

JEE Main 2016 April 3 Paper & Solutions - Question 22

Half-lives of two radioactive elements A and B are 20 minutes and 40 minutes, respectively. Initially, the samples have equal number of nuclei. After 80 minutes, the ratio of decayed numbers of A and B nuclei will be :

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 22

80 minutes = 4 half-lives of A = 2 half-lives of B
Let the initial number of nuclei in each sample be N
NA after 80 minutes = N/2⇒ Number of A nuclides decayed = 15/16N
NB after 80 minutes = N/2⇒ Number of B nuclides decayed = 3/4N
Required ratio = 

JEE Main 2016 April 3 Paper & Solutions - Question 23

If a, b, c, d are inputs to a gate and x is its output, then, as per the following time graph, the gate is :

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 23

x is 1 when at least one of the inputs is 1. Hence x is an OR-Gate.

JEE Main 2016 April 3 Paper & Solutions - Question 24

A screw gauge with a pitch of 0.5 mm and a circular scale with 50 divisions is used to measure the thickness of a thin sheet of Aluminium. Before starting the measurement, it is found that when the two jaws of the screw gauge and brought in contact, the 45th division coincides with the main scale line and that the zero of the main scale is barely visible. What is the thickness of the sheet if the main scale reading is 0.5 mm and the 25th division coincides with the main scale line?

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 24

L.C. = 
-ve zero error = - 5 x L.C. = -0.005 mm
∴ Measured value
= main scale reading + screw gauge reading - zero error 
= 0.5 mm + {25 x 0.001 - (-0.05)} mm  = 0.80 mm

JEE Main 2016 April 3 Paper & Solutions - Question 25

Choose the correct statement :

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 25

JEE Main 2016 April 3 Paper & Solutions - Question 26

A pipe open at both ends has a fundamental frequency f in air. The pipe is dipped vertically in water so that half of it is in water. The fundamental frequency of the air column is now :

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 26

JEE Main 2016 April 3 Paper & Solutions - Question 27

A galvanometer having a coil resistance of 100 Ω gives a full scale deflection, when a current of 1 mA is passed through it. The value of the resistance, which can convert this galvanometer into ammeter giving a full scale deflection for a current of 10 A is :

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 27

Maximum voltage that can be applied across the galvanometer coil = 100 Ω x 10-3 A = 0.1 V.
If RS is the shunt resistance :
RS x 10 A = 0.1 V
⇒ RS = 0.01 Ω

JEE Main 2016 April 3 Paper & Solutions - Question 28

In an experiment for determination of refractive index of glass of a prism by i - δ, plot, it was found that a ray incident at angle 35°, suffers a deviation of 40° and that it emerges at angle 79°. In that case which of the following is closest to the maximum possible value of the refractive index?

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 28


δ =  i + e - A
40 = 35 + 79 - A
40 = 114 - A
A = 114 - 40 = 74 = r1+ r2 
From this we get,
μ = 1.5
∴ δmin < 40°

JEE Main 2016 April 3 Paper & Solutions - Question 29

Identify the semiconductor devices whose characteristics are given below, in the order (a), (b), (c), (d):

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 29

Graph (a) is for a simple diode.
Graph(b) is showing the V Break down used for zener diode.
Graph (c) is for solar cell which shows cut-off voltage and open circuit current
Graph (d) shows the variation of resistance h and hence current with intensity of light.

JEE Main 2016 April 3 Paper & Solutions - Question 30

For a common emitter configuration, if a and b have their usual meanings, the incorrect relationship between a and b is:

Detailed Solution for JEE Main 2016 April 3 Paper & Solutions - Question 30

View more questions
Information about JEE Main 2016 April 3 Paper & Solutions Page
In this test you can find the Exam questions for JEE Main 2016 April 3 Paper & Solutions solved & explained in the simplest way possible. Besides giving Questions and answers for JEE Main 2016 April 3 Paper & Solutions, EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

Download as PDF

Top Courses for JEE