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Gate Mock Test Civil Engineering (CE)- 3 - Civil Engineering (CE)


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65 Questions MCQ Test GATE Civil Engineering (CE) 2023 Mock Test Series - Gate Mock Test Civil Engineering (CE)- 3

Gate Mock Test Civil Engineering (CE)- 3 for Civil Engineering (CE) 2023 is part of GATE Civil Engineering (CE) 2023 Mock Test Series preparation. The Gate Mock Test Civil Engineering (CE)- 3 questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The Gate Mock Test Civil Engineering (CE)- 3 MCQs are made for Civil Engineering (CE) 2023 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Gate Mock Test Civil Engineering (CE)- 3 below.
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Gate Mock Test Civil Engineering (CE)- 3 - Question 1

Directions: Choose the appropriate option for the blank to make the sentence grammatically correct.

________________, it seems clear, he will continue to play for the country.

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 1
He is so great a player that the selectors cannot drop him. Since no negation precedes 'drop' here, the negation has to come in the form of negative 'too'.
Gate Mock Test Civil Engineering (CE)- 3 - Question 2

The mirror image of the above text about the x-axis is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 2

( ∴ Mirror image of any text about a line is symmetrical about the line)

Gate Mock Test Civil Engineering (CE)- 3 - Question 3

Directions: Select the option that bears the same relationship as that of the given pair.

POLO : MALLET

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 3
Polo is a game played with help of a mallet (meaning a long handled hammer with flexible handle). Similarly, golf is a game played with the help of a club (meaning a heavy stick).
Gate Mock Test Civil Engineering (CE)- 3 - Question 4

If ⊕ and ⊙ are two operators on numbers p and q such that p ⊙ q = p - q, and p ⊕

q = p × q, then (9 ⊙(6 ⊕ 7)) ⊙ (7 ⊕ (6 ⊙ 5)) is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 4
(9 ⊙(6 ⊕ 7)) ⊙ (7 ⊕ (6 ⊙ 5))

= (9 - (6 × 9)) - (7 × (6 - 5))

= (9 - 42) - (7 × 1)

= -33 - 7

= -40

Gate Mock Test Civil Engineering (CE)- 3 - Question 5

What is the value of ?

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 5
The given fraction is equal to = (a + b + c)

Where a = 8/7, b = 7/8, c = 9/7

a + b + c = 8/7 + 7/8 + 9/7 = = 185/56

Gate Mock Test Civil Engineering (CE)- 3 - Question 6

On a planar field, you traveled 3 units East from point O. Next you traveled 4 units South to arrive at point P. Then you traveled from P in the North-East direction such that you arrived at a point that is 6 units East of point O. Next, you traveled in the North-West direction so that you arrive at point Q that is 8 units North of point P. The distance of point Q to point O, in the same units, should be ______.

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 6
From right angled triangle ORQ,

OQ2 = OR2 + RQ2

= 32 + 42

= 9 + 16 = 25

Gate Mock Test Civil Engineering (CE)- 3 - Question 7

A, B and C borrow Rs. 29,200 in all at 4% simple interest and pay back equal amounts in full settlement of their respective debts after 5, 10 and 15 years, respectively. Find the sum borrowed by C.

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 7
Suppose A, B and C borrow Rs. x, Rs. y and Rs. z, respectively.

x + y + z = 29,200 .........(i)

Amount paid back by A = Rs. x + x(4)(5/100) = Rs. 6x/5

Amount paid back by B = Rs. y + y(4)(10/100) = Rs. 7y/5

Amount paid back by C = Rs. z + z(4)(15/100) = Rs. 8z/5

6x/5 = 7y/5 = 8z/5

i.e. 6x = 7y = 8z .........(ii)

Solving (i) and (ii) simultaneously, we get

x = 11,200, y = 9,600, z = 8,400

Hence, A, B and C borrow Rs. 11,200, Rs. 9,600 and Rs. 8,400, respectively.

Gate Mock Test Civil Engineering (CE)- 3 - Question 8

1. Some football players play cricket.

2. All cricket players play hockey.

Among the options given below, the statement that logically follows from the two statements 1 and 2 above, is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 8
F → Football players

C → Cricket players

H → Hockey players

∴ Some football players play hockey

Gate Mock Test Civil Engineering (CE)- 3 - Question 9

Answer these questions based on the pipeline diagram given:

The following sketch shows the pipelines carrying material from one location to another. Each location has a demand for material. The demand at B is 800, at C is 800, at D is 1400, and at E is 400. Each arrow indicates the direction of material flow through the pipeline. The flow from B to C is 600. The quantity of material flow is such that the demands at all these location are exactly met. The capacity of each pipeline is 2000.

The quantity moved from A to E is _____.

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 9
The capacity of each pipeline is 2000.

According to the demand and the flow quantity, the block diagram is shown below:

We have, DB = 800, DC = 800, DD = 1400, DE = 400, fBC = 600

The flow quantity shown in figure.

Thus, quantity moved from A to E is 2000.

Gate Mock Test Civil Engineering (CE)- 3 - Question 10

In an equivalent triangle PQR, side PQ is divided into four equal parts, side QR is divided into six equal parts and side PR is divided into eight equal parts. The length of each subdivided part in cm is an integer.

The minimum possible area of the triangle PQR, in cm2, is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 10
Let the length of side of an equilateral triangle be 24 cm. (L.C.M of 4, 6, 8 = 24)

To have minimum area of triangle PQR, (length of each sub divided part is an integer)

Area of an equilateral triangle = √3/4 a2 (where a is the length of the side)

Gate Mock Test Civil Engineering (CE)- 3 - Question 11

For the differential equation with y(0) = 1, the general solution is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 11
D + 5 = 0

D = -5

The general solution is:

y = ce-5t

From y(0) = 1, we get

C = 1

The general solution is:

y = e-5t

Gate Mock Test Civil Engineering (CE)- 3 - Question 12

Which of the following statements are the advantages of surface vibrators?

Surface vibrators are best suited

1. for one way reinforced slabs and road surfaces

2. when depth of the concrete to be vibrated exceeds 250 mm

3. where immersion vibrations are impracticable

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 12
Surface vibrators are placed directly on the concrete mass. These are best suited for the compaction of shallow elements and should not be used when depth of concrete to be vibrated is more than 250 mm.
Gate Mock Test Civil Engineering (CE)- 3 - Question 13

is equal to

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 13
Let form.

By L' Hospital rule, I form.

Again apply L' Hospital rule.

Gate Mock Test Civil Engineering (CE)- 3 - Question 14

The main function of surge tanks is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 14
When the water is suddenly released in penstocks, there may be a problem of water hammer. To avoid this, surge tanks are employed, which decrease the pressure of water, thereby preventing water hammer.
Gate Mock Test Civil Engineering (CE)- 3 - Question 15

A point load of 800 kN is applied on the surface of thick layer of saturated clay. Using Boussin's elastic analysis, the estimated vertical stress at a depth of 2 m and a radial distance of 1.0 m from the point of application of the load is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 15

Gate Mock Test Civil Engineering (CE)- 3 - Question 16

For a B.G.(Broad Gauge) track, the value of maximum velocity is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 16
For a B.G. track, the value of maximum velocity is .

For an N.G.(Narrow Gauge) track, the value of maximum velocity is

Gate Mock Test Civil Engineering (CE)- 3 - Question 17

A long structural column (Length = L) with both ends hinged is acted upon by an axial compressive load P. The differential equation governing the bending of column is given by , where y is the structural lateral deflection and EI is the flexural rigidity. The first critical load on column responsible for its buckling is given by

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 17
Length of column = L

End condition: Both ends hinged

Compressive load = P

Flexural rigidity = EI

Critical load on column, Pc = π2EI/L2

Gate Mock Test Civil Engineering (CE)- 3 - Question 18

The correct expression for the modulus of elasticity for short-term loading is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 18
Correct expression for the modulus of elasticity for short-term loading is It is based on neglection of the effect of creep. Here, Ec is short-term static modulus of elasticity in N/mm2 and fck is the characteristic compressive strength of cubes in N/mm2. The above expression is updated as per IS : 456-2000.
Gate Mock Test Civil Engineering (CE)- 3 - Question 19

For linear elastic systems, the type of displacement function for the strain energy is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 19

E∝ε2 which represents quadratic equation.

Gate Mock Test Civil Engineering (CE)- 3 - Question 20

The velocity components of a plane flow are x/k1 - y/k2 , 0 in the directions x, y, z, respectively. If k1 , k2 ≠ 0 are constant times, the correct expression for the flow to be incompressible is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 20

Consider the expression for the incompressible flow.

Gate Mock Test Civil Engineering (CE)- 3 - Question 21

In structural analysis, Muller Breslau principle is used for

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 21
In structural analysis, Muller Breslau principle is used for drawing influence line diagram for any force function by means of deflected diagram.
Gate Mock Test Civil Engineering (CE)- 3 - Question 22

To make certain that the backfill material is more previous than the soil to be drained, the relationship used is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 22
The filter material should be coarse enough to allow easy passage for percolating water which can move easily without any buildup of water pressure in the filter.

For the filter to provide full drainage,

kfilter ≥ 25kprotectedsoil

where k is the permeability and it is proportional to square of particles size.

So, D15filter ≥ D15protected soil

Gate Mock Test Civil Engineering (CE)- 3 - Question 23

Which of the following organisms exhibits very nearly the characteristics of an ideal pathogenic indicator?

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 23
Escherichia coli

it is the ideal pathogenic indicator used for the bacterial analysis of water is exhibited by the organism

Fecal indicator A group of organisms that indicates the presence of fecal contamination, such as the bacterial groups thermotolerant coliforms or E. coli.

Hence, it is a type of bacteria that normally lives in your intestines. It's also found in the gut of some animals. Most types of E. coli are harmless and even help keep your digestive tract healthy. But some strains can cause diarrhea if you eat contaminated food or drink fouled water.

Entamoeba histolytica:

it is an anaerobic parasitic amoebozoan, part of the genus Entamoeba. Predominantly infecting humans and other primates causing amoebiasis, E. histolytica is estimated to infect about 35-50 million people worldwide.

Salmonella Typhi (S. Typhi):

bacteria which infect the intestinal tract and the blood. The disease is referred to as typhoid fever. S. Paratyphi A, B, and C bacteria cause a similar illness which is included under the typhoid heading

Vibro comma(Vibrio cholera):

it is a species of Gram-negative, facultative anaerobe, and comma-shaped bacteria. The bacteria naturally live in brackish or saltwater where they attach themselves easily to the chitin-containing shells of crabs, shrimps, and other shellfish.

Gate Mock Test Civil Engineering (CE)- 3 - Question 24

Figure given below shows a smooth vertical-gravity retaining wall with cohesionless soil backfill having an angle of internal friction Φ. In the graphical representation of Rankine's active earth pressure for the retaining wall shown in figure, length OP represents

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 24
Rankine's active earth pressure method is graphical method to determine the active earth pressure of the soil.

OP does not cut the Mohr's circle tangential, so OP represents the vertical stress at the base.

Gate Mock Test Civil Engineering (CE)- 3 - Question 25

The results of analysis of a raw water sample are given below.

From the data given above, it can be inferred that water needs removal of

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 25
Fluoride should be less than 1.5 mg/L, hardness between 75 – 115 mg/L as CaCO3, iron 0.3 mg/L and MPN 1 per 100 mL (presence of pathogenic bacteria).

Hence, water needs removal of fluoride, harness iron and followed by disinfection to reduce MPN to 1 per 100 mL.

Gate Mock Test Civil Engineering (CE)- 3 - Question 26

Two identical concrete piles having the plane dimenstions 50 cm x 50 cm are driven into a homogeneous sandy layer as shown in the figures. Consider the bearing capacity factor Nq for Φ = 30o as 24.

If QP1 and QP2 represent the ultimate point bearing resistance of the piles under dry and submerged conditions, respectively, which one of the following statements is correct?

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 26

The point bearing resistance of piles in sandy soils

Qp = Ab .σv.Nq

As the area at base (Ab) and Nq are same for both the piles given,

Qp∞σv

For dry sand condition,

Gate Mock Test Civil Engineering (CE)- 3 - Question 27

The dispersion of pollutants in atmosphere is maximum when

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 27
Unstable environment means ELR > ALR.

(EIR = Environment Lapse Rate, ALR = Adiabatic Lapse Rate)

A rising air parcel will continue to go up and dispersion of pollutant will be rapid due to vertical mixing of air with pollutants

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 28

For the function f(x) = x2e-x, the maximum occurs when x is equal to ____. (Answer up to the nearest integer)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 28

Now for the maxima and minima, f’(x) = 0

Now f”(0) = 2 and f”(2) = -2e-2 < 0.="" thus,="" x="2" is="" the="" point="" of="" />

Gate Mock Test Civil Engineering (CE)- 3 - Question 29

When a retaining wall moves away from the back-fill, the pressure exerted on the wall is termed as

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 29
When a retaining wall moves away from the backfill, the pressure exerted on the wall is termed as active earth pressure. When a retaining wall moves towards the backfill, the pressure exerted on the wall is termed as passive earth pressure.

Swelling pressure is the pressure exerted by the soil on the overlying structure if free swelling of the soil is restrained by the placement of a structure over the soil. Pore water pressure is the pressure exerted due to the pore water. It is equal to the product of the depth at which pore water pressure is required and unit weight of water.

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 30

In a circular tapering bar of length 120 mm, diameter varies from 20 mm to 45 mm. If a tensile load of 20 kN is applied axially, find the total deflection (in mm) of the bar. (Take E = 85 MPa) (Answer up to the nearest integer)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 30

Here, D1 = 20 mm = 0.020 m, D2 = 45 mm = 0.045 m,

P = 20 kN = 20000 N and L = 120 mm = 0.120 m

Total deflection is

= 0.039 m

= 39 mm

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 31

An aircraft is flying in level flight at a speed of 200 km/hr through air (Density, ρ = 1.2 kg/m3 and viscosity, m = 1.6 × 10-5 N-s/m2). The lift co-efficient at this speed is 0.4 and the drag co-efficient is 0.0065. The mass of the aircraft is 800 kg. The effective lift area (in m2) of the aircraft is

(Answer up to one decimal place)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 31

Aircraft generates the lift equal to the weight of the aircraft, so at the equilibrium condition.

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 32

Consider a fully developed flow of water in a pipe. The velocity of flow is 2 m/s and dynamic viscosity is 1.5 Pa/s. If the value of manning friction factor is 0.25, then diameter of the pipe is __________ mm. (Answer up to the nearest integer)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 32
manning friction factor is

As Reynolds number, Re < 2300,="" the="" flow="" is="" />

D = 0.192 m

= 192 mm

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 33

A roundabout is provided with an average entry width of 8.4 m, width of weaving section as 14 m, and length of the weaving section between channelising islands as 35 m. The crossing traffic and total traffic on the weaving section are 1000 and 2000 PCU per hour respectively. The capacity of the roundabout (in PCU per hour) is (Answer up to two decimal places)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 33
Capacity of a rotatory

Where, w = width of weaving section = 14 m

L = length of weaving section = 35 m

e1 = entry width = 8.4

p = weaving proportion

= crossing traffic ÷ total traffic

= 1000 ÷ 2000

= 0.5

Putting all these values, we get

C = 3733.33 PCU per hour

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 34

A conical bar having density of 25 g/cm3 elongates due to its own weight. If the length of the bar is 6 m and the largest diameter of the bar is 2 m, then the total elongation is ____________ μ m. (Assume E = 80 Gpa, g = 9.81 m/s2) (Answer up to two decimal places)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 34

= 18.39375 μm

= 18.39 μm

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 35

The consumptive use of water for a crop during a particular stage of growth is 2.0 mm/day. The maximum depth of available water in the root zone is 60 mm. Irrigation is required when the amount of available water is 50% of the maximum available water in the root zone. Frequency of irrigation (in days) should be (Answer up to the nearest integer)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 35
Cu = 2.0 mm/day

Net available moisture level = 0.5 x 60 = 30 mm

Frequency of irrigation = 30/2 = 15 days

Gate Mock Test Civil Engineering (CE)- 3 - Question 36

The following observations are made while testing aggregate for its suitability in pavement construction:

i. Mass of oven-dry aggregate in air = 1000 g

ii. Mass of saturated surface-dry aggregate in air = 1025 g

iii. Mass of saturated surface-dry aggregate under water = 625 g

Based on the above observations, the correct statement is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 36
Mass of oven dry aggregate wa = 1000g

Mass of water in saturated surface dry aggregate = ww

So, wa + ww = 1025

⇒ ww = 25g

Mass of saturated surface dry aggregate under water = 625 g

⇒ wa - va ρw = 625g(va vol of aggregate)

volume of void (Vv) = vol of water = vw = ww/pw = 25CC

Bulk density of aggregate

=

Bulk specific gravity of aggregate

=

water absorption =

Gate Mock Test Civil Engineering (CE)- 3 - Question 37

The system of equations x − 4y + 7z = 14, 3x + 8y − 2z = 13, 7x − 8y + 26z = 5 has

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 37

Thus system is inconsistent i.e. has no solution.

Gate Mock Test Civil Engineering (CE)- 3 - Question 38

In a simply supported beam subjected to uniformly distributed load throughout the length, at which points is the stress due to (i) flexure and (ii) shear equal to zero selectively?

1. At the support section and neutral fibre

2. At mid-span section and neutral fibre

3. At mid-span section and top fibre

4. At support section and bottom fibre

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 38

Bending stress or flexure stress is given by f = My/l. It means that flexure stress is zero at neutral fibre (y = 0) for any magnitude of bending moment. Shear stress is zero at a section where shear force is zero. At the top and bottom fibres also, shear stress is zero for any magnitude of shear force. As seen from the diagrams, flexure and shear are both zero at mid-span and support sections.

Gate Mock Test Civil Engineering (CE)- 3 - Question 39

Consider the following devices as likely to concern with water hammer phenomenon in their design/operation:

1. Hydraulic ram

2. Hydraulic accumulator

3. Penstock

4. Draft tube

Which of the above devices is/are so concerned?

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 39
Correct Answer: 1, 3 and 4 only
Gate Mock Test Civil Engineering (CE)- 3 - Question 40

Group I contains three broad classes of irrigation supply canal outlets. Group II presents hydraulic performance attributes.

The correct match of the items in Group I with the items in Group II is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 40
Non-modular outlet : These are the outlets whose discharge depends on the difference in water levels in the distributing channel and the water course. The discharge of such outlets, therefore, varies with the variation of the water levels in the distributing channel and the water course.

Semi-modular outlet : These are the outlets whose discharge varies with the variation of the water level in the distribution channel but it is independent of the water level in the water course, so long as the minimum working head required for their working is available.

Modular outlet : These are the outlets whose discharge is independent of the water levels in the distributing channel and the water course, within reasonable working limits. In other words modular outlets maintain a constant discharge irrespective of variation of the water levels in the distributing channel and the water course.

Gate Mock Test Civil Engineering (CE)- 3 - Question 41

A saturated undisturbed sample from a clay strata has moisture content of 22.22% and specific weight of 2.7. Assuming γω = 10 kN/m3, the void ratio and the saturated unit weight of the clay, respectively are

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 41

Gate Mock Test Civil Engineering (CE)- 3 - Question 42

Which among the following are the dominating microorganisms in an activated sludge process reactor?

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 42
The activated sludge process is used to treat waste streams that are high in organics. The species of microorganism that dominates a system depends on aerobic heterotrophs because the process is strictly aerobic with few exceptions. Aerobic heterotrophic bacteria are main activated organisms. Heterotrophic bacteria obtain energy from carbonaceous organic matter in influent waste water for the synthesis of new cells.
Gate Mock Test Civil Engineering (CE)- 3 - Question 43

The correct match of Column I with Column II is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 43
Coriolis effect - Rotation of earth

Fumigation - Inversion

Ozone layer - Dobson

Maximum mixing depth - Lapse rate and vertical temperature profile

Gate Mock Test Civil Engineering (CE)- 3 - Question 44

If the plastic moment capacity of a prismatic beam shown below is Mp , then the collapse load P of the beam is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 44

Consider the following force diagram

Degree of static indeterminacy is Ds = 0

Therefore, number of plastic hinges is,

N = Ds + 1

= 0 + 1

= 1

Now, from principal of virtual work

Solve the above expression.

Gate Mock Test Civil Engineering (CE)- 3 - Question 45

Column I gives a list of test methods for evaluating properties of concrete and Column II gives the list of properties.

The correct match of the test with the property is

Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 45
(A) Resonant frequency test used to determine dynamic modulus of elasticity (vibration technique using ultrasonic wave) whereas destructive test like cube test, etc., measures the static modulus of elasticity.

(B) Rebound hammer test used for compressive strength of concrete and a non-destructive test but in general rebound hammer test provides strength of concrete at the surface of the sample.

(C) Split cylinder test used to determine the direct tensile strength of the concrete.

(D) Compacting factor test is one of the most reliable method to determine work ability of the concrete

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 46

A timber pile of length 8 m and diameter of 0.2 m is driven with a 20 kN drop hammer, falling freely from a height of 1.5 m. The total penetration of the pile in the last 5 blows is 40 mm. Use the engineering news record expression. Assume a factor of safety of 6 and empirical factor (allowing reduction in the theoretical set, due to energy losses) of 2.5 cm. The safe load carrying capacity of the pile (in kN), is ______(Answer up to two decimal places)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 46
Engineering news record expression

s = Penetration of pile per hammer blow

= 40 mm/8 = 8 mm = 0.008 m

C = 2.5 cm = 0.025 m

Then, safe load carrying capacity:

= 909.09/6 = 151.51 kN

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 47

Find the value of , where [.] denotes g.i.f.


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 47
Let

⇒ [I] = 4

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 48

Consider a fluid with density 100 kg/m3 and viscosity 0.5 N-s/m2 flowing through a tube of 20 cm diameter without any turbulency. The value of maximum velocity (in m/s) is (Answer up to the nearest integer)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 48
For no turbulency, Reynolds number must be critical.

Rec = 2000

U = 50 m/s

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 49

Chlorine gas used for disinfection combines with water to form hypochlorous acid (HOCl). HOCl ionises to form hypochlorite (OCl-) in a reversible reaction: HOCI ⇔ H+ + OCl- (k= 2.7 × 10-8 at 20 °C), the equilibrium of which is governed by pH. The sum of HOCI and OCl- is known as free chlorine residual and HOCI is more effective disinfectant. The 90% fraction of HOCl in the free chlorine residual is available at a pH value of (Answer up to one decimal place)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 49

= 6.6

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 50

For anisotropic material, the total number of independent elastic constants is _____. (Answer up to the nearest integer)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 50
For anisotropic material, at one point, the properties are different in different directions.

To find the required property, 21 elastic constants are needed.

So, the total number of independent elastic constants is 21.

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 51

Examine the test arrangement and the soil properties given below.

The maximum pressure (in kPa) that can be applied with a factor of safety of 3 through the concrete block, ensuring no bearing capacity failure in soil using Terzaghi's bearing capacity equation without considering the shape factor, depth factor and inclination factor is

(Answer up to two decimal places)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 51

Applied through concrete block and no bearing capacity failure. Shape factor, depth factor and inclination factor are neglected.

Allowable bearing capacity = 160/3 = 53.33 kN/m2

So, for each footing = 53.33/2 26.67 kN/m2

= 26.67 kPa

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 52

Velocity vector of a flow field is given as . The magnitude of vorticity vector at (1, - 2, 2) is (Answer up to the nearest integer)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 52

is the velocity vector

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 53

The Froude number of flow in a rectangular channel is 0.8. If the depth of flow is 1.5 m, then the critical depth (in m) is

(Answer up to three decimal places)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 53
Froude number Fr = v/√gy and for rectangular channel q = v . y

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 54

A cylindrical shaft of diameter 12 cm is subjected to a bending moment of 3 kNm and a twisting moment of 5.5 kNm. If the yield stress of the shaft material is 480 MPa, then the factor of safety of the shaft corresponding to the maximum shearing stress theory of failure is (Answer up to the nearest integer)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 54
Here, d = 0.12 m, M = 3000 Nm

T = 5500 Nm , σyt = 480 N/mm2

Equivalent torque is

Maximum shear stress developed in the shaft is

Permissible shear stress is

Factor of safety is

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 55

One hour triangular unit hydrograph of a watershed has the peak discharge of 60 m3/sec.cm at 10 hours and time base of 30 hours. The Φ index is 0.4 cm per hour and base flow is 15 m3m/sec.

If there is rainfall of 5.4 cm in 1 hour, then the ordinate of the flood hydrograph (in m3/sec) at 15th hour is_______(Answer up to the nearest integer)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 55
Rainfall excess = Rainfall - Φ index

= 5.4 - 0.4

= 5 cm

Base flow = 15 cubic cm/sec

Ordinate at 15th hour =

= 240 m3/s

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 56

For M25 concrete with creep coefficient of 1.5, the long-term static modulus of elasticity (expressed in MPa) as per the provisions of IS:456-2000 is ________. (Answer up to the nearest integer)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 56
Long term elasticity =

= 5000 x 5

= 25000

Creep coefficient (θ) = 1.5

Long term elasticity = = 10,000

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 57

For the soil strata shown in figure, the water table is lowered by drainage by 2 m and if the top 2 m thick silty sand stratum remains saturated by capillary action even after lowering of water table, then the increase in effective vertical pressure (in kN/m2) at mid-height of the clay layer will be (Answer up to the nearest integer)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 57
In the capillary zone, pore pressure is negative. The total stress will not change due to lowering of water table because the stratum is still saturated.

Thus, the increase in effective vertical pressure will be only due to pore pressure.

Thus increase in effective stream, hrw = 2 × 10 = 20 kN/m2

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 58

The figure shows the geometry of a strip footing supporting the load bearing walls of a three-storeyed building and the properties of clay layer.

If the elastic modulus and the Poisson ratio of the clay layer respectively are 50 × 103 kPa and 0.4 and if the influence factor for the strip footing is 1.75, then the elastic settlement (in mm) of the footing will be (Answer up to two decimal places)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 58
Elastic settlement is given by

Where,

= 1.41 mm

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 59

A 12 mm thick plate is connected to two 8 mm plates, on either side through a 16 mm diameter power driven field rivet as shown in the figure below. Assuming permissible shear stress as 90 MPa and permissible bearing stress as 270 MPa in the rivet, the rivet value (in kN) of the joint is (Answer up to three decimal places)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 59
Double shear-

Diameter of the rivet = 16 mm

Rivet value is the least of value either failure of rivet in shear or in bearing.

In shear (double):

= 2 × (π/4) × (16 + 1.5)2 × 90 N

= 43.295 kN

In bearing:

= 12 × (16 + 1.5) × 270 N

= 56.7 kN

So, rivet value = 43.295 kN

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 60

A road is designed in such a manner that the speed on a horizontal curve with an elevation of 8% is 110 km/hr. The minimum radius of the curve (in m) that is required for a vehicle to move safely, if the coefficient of friction is 0.10, is (Answer up to one decimal place)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 60
The minimum radius of the curve required for safe vehicular movement is the ruling gradient.

The expression for the ruling gradient is:

Substitute the values in the above expression:

= 529.3 m

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 61

The state of two dimensional stress acting on a concrete lamina consists of a direct tensile stress,σx = 1.5 N/mm2, and shear stress て = 1.20 N/mm2, which cause cracking of concrete. The tensile strength of the concrete, in N/mm2, is (Answer up to two decimal places)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 61
Direct tensile stress, = 1.5 N/mm2,

shear stress = 1.20 N/mm2

σmax = 2.17 N/mm2

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 62

An open ended steel barrel of 1 m height and 1 m diameter is filled with saturated fine sand having the coefficient of permeability of 10−2 m/s. The barrel stands on a saturated bed of gravel. The time required (in seconds) for the water level in the barrel to drop by 0.75 m is

(Answer up to the nearest integer)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 62
k = 10-2 m/s

Time required for water level drop by 0.75

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 63

A pre-tensioned concrete member of section 200 mm x 250 mm contains tendons of area 500 mm2 at the centre of gravity of the section. The pre-stress in tendons is 1000 N/mm2. Assuming modular ratio as 10, the stress (in N/mm2) in concrete is (Answer up to two decimal places)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 63
B = 200, D = 250, Ast = 500 mm2

Ps = 1000 N/mm2, m = 10, Pc = ?

Pre-tension acts on centre of gravity of the section

P = Ast.Ps = 1000 x 500 N

= 500 kN

Now, strain in concrete = strain in steel

Now, strain in concrete = 10.10/EC

Stress in steel =

= 101.01 N/mm2 (loss)

Final stress = 1000 - 101.01 = 899 N/mm2

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 64

The mean distance between two jets in an air stream is 100 m. The density of the air stream in veh/km is (Answer up to the nearest integer)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 64
Calculate the density of the air stream.

ρair = 1000/s

= 1000/100

= 10 veh/km

*Answer can only contain numeric values
Gate Mock Test Civil Engineering (CE)- 3 - Question 65

A horizontal flow primary clarifier treats waste water in which 10%, 60% and 30% of particles have settling velocities of 0.1 mm/s, 0.2 mm/s, 0.2 mm/s, and 1.0 mm/s respectively. What would be the total percentage of particles removed if clarifier operates at a Surface Overflow Rate (SOR) of 43.2 m3/m2.d?

(Answer up to the nearest integer)


Detailed Solution for Gate Mock Test Civil Engineering (CE)- 3 - Question 65

Surface overflow rate

Settling velocity more than 0.5 mm/s will be removed 100% and rest is proportional to their settling velocity.

∴ Total percentage of particle removal

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