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Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - GATE MCQ


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30 Questions MCQ Test - Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I)

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Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 1

The total expenditure of a family, on different activities in a month, is shown in the piechart. the extra money spent on education as compared to transport (in percent) is ____.

 

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 1

Let total monhly earining = Rs. 100
Monthly spent on education = (15/100) x 100 = Rs. 15
Monthly spent on transport = (10/100) x 10 = Rs. 10
% money extra spent on education as compard to transportation
= ((15-10)/10) x 100 = 50%

Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 2

The unit’s place in 26591749110016 is ________.

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 2

≌ 26591749(110016)
≌ Unit place of 9even = 1
∴ Cyclicity of 9 is (9, 1), (9, 1), (9, 1)
So answer will be 1.

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Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 3

The sum of two positive numebrs is 100. After subtracting 5 from each number, the product of the resulting numbers is 0. One of the original numbers is ______.

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 3

If the product of two positive numbers should be zero, one of the number must be zero.
After subtracting 5 if a positive number should become zero, that number should be 5.
If one number is 5 and the sum is 100 then the other number must be 95.
Let the two positive numbers be x and y.
∴ x + y = 100 ...(i)
(x – 5) (y – 5) = 0 ...(ii)
⇒ x = 5 or y = 5
If x = 5 then y = 95
If y = 5 then x = 95
∴ One of the number is 95 since 5 is not in any of the options.

Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 4

Five friends P, Q, R, S and T went camping. At night, they had to sleep in a row inside the tent. P, Q and T refused to sleep next to R since he snored loudly. P and S wanted to avoid Q as he usually hugged people in sleep.
Assuming everyone was satisfied with the sleeping arrangements, what is the order in which they slept?

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 4

Option (a) satisfies the given conditions in the paragraph.

Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 5

The american psychologist Howard Gardner expounds that human intelligence can be sub-categorised into multiple kinds, in such away that individuals differ with respect to their relative competence in each kind. Based on this theory, modern educationists insist on prescribing multi-dimensional curriculum and evaluation parameters that enable development and assessment of multiple intelligences.
Which of the following statements can be inferred from the given text?

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 5

Based on this theory, modern educationists insist on prescribing multi-dimensional curriculum and evaluation parameters
This line clearly reflects the inference from the paragraph.

Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 6

Insert seven numbers between 2 and 34, such that the resulting sequence including 2 and 34 is an arithmetic progression. The sum of these inserted seven numbers is ________.

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 6

2, a , (a + d ), (a + 2d ), ...... (a + 6d ), 34
∴ Total number of terms of AP (n) = 9
Let sum of seven inserted numbers = S
∴ S = (7/2)[a+(a+6d0] = 7[a + 3d]
Tn = 34
Also, a – 2 = (a + d – a)
⇒ a – d = 2
Similarly a – 2 = 34 – (a + 6d)
⇒ a – 2 = 34 – a – 6d
⇒ 2a = 36 – 6d = 36 – 6(a – 2)
⇒ 2a = 36 – 6a + 12
⇒ 8a = 48
⇒ a = 6
∴ d = a – 2 = 6 – 2 = 4
∴ S = 7(a + 3d ) = 7(6 + 3 × 4) = 126

Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 7

It is a common criticism that most of the academicians live in their _____, so, they are not aware of the real life challenges.

Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 8

Select the work that fits the analogy:
Fuse : Fusion :: Use : ______

Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 9

His number for reading is insatiable. He reads indiscriminately. He is most certainly a/an ________ reader.

Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 10

If 0, 1, 2, ..., 7, 8, 9 are coded as O, P, Q, ..., V, W, X, then 45 will be coded as _______.

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 10


∴ 45 is coded as ‘ST ’.

Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 11

The data for an agricultural field for a specific month are given below:
Pan Evaporation = 100 mm
Effective Rainfall = 20 mm (after deducting losses due to runoff and deep percolation)
Crop Coefficient = 0.4
Irrigation Efficiency = 0.5
The amount of irrigation water (in mm) to be applied to the field in that month, is

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 11

Water required by crop = 100 × 0.4 mm = 40 mm
Effective rainfall = 20 mm
Additional water requried = 20 mm
Amount of water required after accounting irrigation efficiency = 20/0.5 = 40mm

Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 12

Uniform flow with velocity U makes an angle θ with the y-axis, as shown in the figure

The velocity potential (φ), is

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 12

Velocity in x-depth, ux = u sin θ
Velocity in y -depth, uy = u cos θ

Integrating it φ =–uxx + f (y ) + c
= –(u sin θ) x + f (y) + c ...(i)

Integrating it φ =–uy y + f (x) + c
= –(u cos θ) y + f (x) + c ...(ii)
By equation (i) and (ii),
φ = −u ( x sinθ +y cos θ)
If we take 
Then φ = u ( x sin θ + y cos θ)
So, φ = ± u ( x sinθ + y cos θ)

Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 13

An amount of 35.67 mg HCl is added to distilled water and the total solution volume is made to one litre. The atomic weights of H and Cl are 1 and 35.5, respectively.
Neglecting the dissociation of water, the pH of the solution, is

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 13

HCl → H+ + Cl
1 mole of HCL gives 1 mole H+ ions
36.5 gm of HCl gives 1 gm of H+ ions
35.67 mg = (1/36.5) x 35.67 = 0.977 mg of H+

pH = –log10[H+] = –log10[9.77 × 10–4]
= –log109.77 + 4 log1010
= 4 – 0.989 = 3.01

Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 14

In a soil investigation work at a site, Standard Penetration Test (SPT) was conducted at every 1.5 m interval up to 30 m depth. At 3 m depth, the observed number of hammer blows for three successive 150 mm penetrations were 8, 6 and 9, respectively. The SPTN-value at 3 m depth, is

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 14

No. of blows for each 150 mm penetration 8, 6 and 9.
We will not consider first 150 mm number of blows.
Hence, for last 300 mm, number of blows are 15.
Hence, observed SPT number = 15.

Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 15

In the following partial differential equation, θ is a function of t and z, and D and K are functions of θ

The above equation is

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 15

∵ 1st term of given D. Equation contains product of dependent variable with it’s derivative, so it is non-linear and also we have 2nd order derivative so it’s order is two i.e., 2nd order non linear equation.

Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 16

Consider the planar truss shown in the figure (not drawn to the scale)

Neglecting self-weight of the members, the number of zero-force members in the truss under the action of the load P, is

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 16


As ΔAB = 0, hence FAB = 0
Total number of zero force member = 8

*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 17

A planar elastic structure is subjected to uniformly distributed load, as shown in the figure (not drawn to the scale)

Neglecting self-weight, the maximum bending moment generated in the structure (in kNm, round off to the nearest integer), is ___________ .


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 17



As horizontal thrust is zero so it behaves like a beam (curved beam)

*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 18

A fully submerged infinite sandy slope has an inclination of 30° with the horizontal. The saturated unit weight and effective angle of internal friction of sand are 18 kN/m3 and 38°, respectively. The unit weight of water is 10 kN/m3. Assume that the seepage is parallel to the slope. Against shear failure of the slope, the factor of safety (round off to two decimal places) is _______.


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 18


= 0.601

Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 19

The value of   is

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 19

It is in  from so by L-Hospital Rule

Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 20

A reinforcing steel bar, partially embedded in concrete, is subjected to a tensile force P. The figure that appropriately represents the distribution of the magnitude of bond stress (represented as hatched region), along the embedded length of the bar, is

Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 21

Velocity of flow is proportional to the first power of hydraulic gradient in Darcy’s law. The law is applicable to

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 21

Darcy’s law is valid for laminar flow condition in porous media.

*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 22

The probability that a 50 year flood may NOT occur at all during 25 years life of a project (round off to two decimal places), is _______.


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 22


q =1 – P = 0.98
∴ Probability of non-occurance of an event is given by,
Assurance = qn
= (0.98)25
= 0.603

Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 23

In a two-dimensional stress analysis, the state of stress at a point P is

The necessary and sufficient condition for existence of the state of pure shear at the point P, is

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 23


In pure shear condition
σx = 0, σy = 0, τxy = τ


For this condition
(c) is correct
σxx + σyy = 0

Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 24

The true value of ln(2) is 0.69. If the value of ln(2) is obtained by linear interpolation between ln(1) and ln(6), the percentage of absolute error (round off to the nearest integer), is

Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 24

True value In 2 = 0.69 = T

Divided differentiation

Approx:
ln 2 = f [x0] + (x – x0) f [x0, x1]
= 0 + (2 – 1) 0.358
= 0.358 = A

*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 25

In an urban area, a median is provided to separate the opposing streams of traffic. As per IRC : 86-1983, the desirable minimum width (in m, expressed as integer) of the median, is __________.


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 25

As per IRC : 86-1983
Desirable minimum width of median in urban roads = 5 m
And minimum width = 1.2 m

*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 26

In a drained tri-axial compression test, a sample of sand fails at deviator stress of 150 kPa under confining pressure of 50 kPa. The angle of internal friction (in degree, round off to the nearest integer) of the sample, is ________.


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 26

Sand (C = 0); σd = 150; σ3 = 50; σ1 = 200


φ = 36.87°
So, the angle of internal friction to the nearest integer is 37°.

Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 27

During chlorination process, aqueous (aq) chlorine reacts rapidly with water to from Cl,  HOCl, and H+ as shown below

The most active disinfectant in the chlorination process from amongst the following, is

*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 28

A 4 m wide rectangular channel carries 6 m3/s of water. The Manning’s ‘n’ of the open channel is 0.02. Considering g = 9.81 m/s2, the critical velocity of flow (in m/s, round off to two decimal places) in the channel, is ________.


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 28

Critical depth (YC

Critical velocity (VC)=  = 2.45 m/s

Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 29

The Los Angeles test for stone aggregates is used to examine

*Answer can only contain numeric values
Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 30

A river has a flow of 1000 million litres per day (MLD), BOD5 of 5 mg/litre and Dissolved Oxygen (DO) level of 8 mg/litre before receiving the wastewater discharge at a location.
For the existing environmental conditions, the saturation DO level is 10 mg/litre in the river. Wastewater discharge of 100 MLD with the BOD5 of 200 mg/litre and DO level of 2 mg/litre falls at that location. Assuming complete mixing of wastewater and river water, the immediate DO deficit (in mg/litre, round off to two decimal places), is _________.


Detailed Solution for Practice Test: Gate Civil Engineering(CE) 2020 Paper: (Session I) - Question 30


= 7.45 mg/l
DO = DOsat – DOmix = 10 – 7.45 = 2.545 mg/l

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