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QUESTION: 1

Bending moment distribution in a beam is shown in the figure beiow.

The shear force diagram will be given by

Solution:

It is a fixed beam carrying concentrated load at mid span. The shear force diagram will be given by (a).

QUESTION: 2

A simply supported beam is loaded as shown in the figure. The maximum shear force in the beam will be

Solution:

The reactions at the supports A and B respectively are

The SF diagram will be

The maximum shear force = 2 W.

QUESTION: 3

The shape of the bending moment diagram for a cantilever beam carrying a uniformly distributed load over its length is

Solution:

which is parabolic in nature.

QUESTION: 4

A simply supported beam is subjected to a distributed loading as shown in the diagram given

What is the maximum shear force in the beam?

Solution:

QUESTION: 5

The point of contraflexure is a point where

Solution:

At the point of contraflexure, bending moment changes sign.

QUESTION: 6

The ratio of reactions R_{A} and R_{B} of the simply supported beam (as shown) is

Solution:

QUESTION: 7

The bending moment in a simple supported beam can be calculated with the help of influence line drawn for the following types of load

Solution:

QUESTION: 8

In a simply supported beam of length ‘L’ with a triangular load varying from zero at one end to the maximum value at the other end, the maximum, bending moment is

Solution:

we get,

QUESTION: 9

For a simply supported beam of length L , the bending moment M is described as M = a (x - x^{3}/L^{2}), 0 ≤ x < L where a is a constant. The shear force will be zero at

Solution:

Shear force,

QUESTION: 10

Match List-I (Type 0f .be4 rp.with type of loading) with List-ll ( Maximum BM formula) and select the correct answer using the codes given beiowthe lists:

Solution:

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