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This mock test of Strength Of Materials 2 for Civil Engineering (CE) helps you for every Civil Engineering (CE) entrance exam.
This contains 10 Multiple Choice Questions for Civil Engineering (CE) Strength Of Materials 2 (mcq) to study with solutions a complete question bank.
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QUESTION: 1

The shear stress at the centre of a circular shaft under torsion is

Solution:

The simple torsion equation is written as

This states that the shearing stress varies directly as the distance ‘r' from the axis of the shaft and the following is the stress distribution

Hence the maximum shear stress occurs on the outer surface of the shaft where r = R and at the centre the shear stress is zero.

QUESTION: 2

Match List-I with List-II and select the correct answer using the code given below the lists.

**List-I **(Loaded Beam)

A.

B.

C.

**List-II **(Maximum Bending moment)

1.

2.

3.

4.

Solution:

A-3, B-1, C-4

Beam A is cantilever so maximum bending moment occurs at the fixed support

Beam B is simply supported so maximum bending moment occurs at midspan

Beam C is cantilever so maximum bending moment occurs at fixed support

M_{C}=

QUESTION: 3

A solid circular shaft of diameter d is subjected to a combined effect of bending moment M and torque T. The relation is used for designing the shaft using which one of this material property

Solution:

S_{sy} = Torsional yield strength

QUESTION: 4

A solid steel shaft is surrounded by a copper shaft, such that, I_{steel }= 1/2 I_{copper}. If G_{copper }= 1/2 G_{steel}, what is the ratio of T_{s}/T_{c} if the composite shaft is subjected to a twisting moment?

Solution:

Both shaft will rotate through same degree.

Hence

QUESTION: 5

Couple M is applied at C on a simply supported beam AB. The maximum shear force on AC will be

Solution:

R_{1} + R_{2} = 0

∑M_{A} = 0

⇒ R_{2} × 3 = -M

So maximum shear force = M/3

QUESTION: 6

A hollow steel shaft of external diameter 100 mm and internal diameter 50 mm is to be replaced by a solid allow shaft. Assuming the same value of polar modulus for both, the diameter of the solid allows shaft will be-

Solution:

Polar modulus,

Let the diameter of solid shaft is ‘d’

*Answer can only contain numeric values

QUESTION: 7

For a loaded cantilever beam of uniform cross-section, the bending moment (in N-mm) along the length is M(x) = 5x^{2} + 10x, where x is the distance (in mm) measured from the free end of the beam. The magnitude of shear force (in N) in the cross-section at x = 10 mm is ________.

Solution:

M = 5x^{2} + 10x

Shear Force = dM/dx = 10x + 10

Shear force at X = 10 mm

= 10 x 10 + 10 = 110 N

QUESTION: 8

S.F.D for the beam is:

Solution:

QUESTION: 9

The equation for the deflected shape of a beam carrying a U.D.L and simply supported at ends is given below The load carrying capacity of the beam is

Solution:

Using the equation of deflection:

W = 40 kN/m

*Answer can only contain numeric values

QUESTION: 10

For the given figure, calculate the bending moment (in kN-m) at 2 m from the left end?

Solution:

∑F_{V} = 0

R_{A} + R_{B} = 3 + 2 × 2

R_{A} + R_{B} = 7 kN

∑F_{H} = 0

H_{A} = 0

∑Mz = 0

R_{A} × 4 – 3 × 3 - 2 × 2 × 1= 0

R_{A} = 3.25 kN

R_{B} = 3.75 kN

BM_{D} = R_{A }× 2 - 3 × 1

BM_{D} = 3.25 × 2 - 3 = 3.5 kN

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