Test: Buoyancy & Floatation - 1 - Mechanical Engineering MCQ

# Test: Buoyancy & Floatation - 1 - Mechanical Engineering MCQ

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## 15 Questions MCQ Test Fluid Mechanics for Mechanical Engineering - Test: Buoyancy & Floatation - 1

Test: Buoyancy & Floatation - 1 for Mechanical Engineering 2024 is part of Fluid Mechanics for Mechanical Engineering preparation. The Test: Buoyancy & Floatation - 1 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Buoyancy & Floatation - 1 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Buoyancy & Floatation - 1 below.
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Test: Buoyancy & Floatation - 1 - Question 1

### A solid sphere of radius R and average mass density ρi is completely submerged in a tank filled with a liquid of mass density ρw with ρi > ρw- The sphere is held in place by string attached to the bottom of tank. The tension in the string is

Detailed Solution for Test: Buoyancy & Floatation - 1 - Question 1

Weight of sphere

Buoyant force,

since

The tension in the string, T, compensates the difference between the weight and the buoyant force and hence W = T + Fb

so,

Test: Buoyancy & Floatation - 1 - Question 2

### If B = Center of buoyancy, G = Center of gravity and M= Metacenter, of afloating body, the body will be in stable equilibrium if

Detailed Solution for Test: Buoyancy & Floatation - 1 - Question 2

For a floating body
Metacentre above centre of gravity→ Stable Equilibrium
Metacentre coincides centre of gravity→ Neutral Equilibrium
Metacentre below centre of gravity→ Unstable Equilibrium
For a submerged body
Centre of buoyancy above centre of gravity→ Stable Equilibrium
Centre of buoyancy coincides centre of gravity→ Neutral Equilibrium
Centre of buoyancy below centre of gravity→ Unstable Equilibrium

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Test: Buoyancy & Floatation - 1 - Question 3

### A siphon is used to drain water from a large tank shown in the figure. Assume that the level of water is maintained constant. Ignore frictional effect due to viscosity and losses at entry and exit. At the exit of the siphon, the velocity of water is

Detailed Solution for Test: Buoyancy & Floatation - 1 - Question 3

Apply the Bernoullis equation between ‘O’ and ‘R’.

Hence, the correct option is (b).

Test: Buoyancy & Floatation - 1 - Question 4

A metal block is thrown into deep lake. As it sinks deeper in water, the buoyant force acting on it

Detailed Solution for Test: Buoyancy & Floatation - 1 - Question 4

Buoyant force equals the weight of water which has been displaced by an object.
Since, irrespective of the metal block position, the volume displaced by metal is same, hence, buoyant force remains the same.

Test: Buoyancy & Floatation - 1 - Question 5

When a block of ice floating on water in a container melts, the level of water in the container

Detailed Solution for Test: Buoyancy & Floatation - 1 - Question 5

*Answer can only contain numeric values
Test: Buoyancy & Floatation - 1 - Question 6

An ideal water jet with volume flow rate of 0.05 m3/s strikes a flat plate placed normal to its path and exerts a force of 1000 N. Considering the density of water as 1000 kg/m3, the diameter (in mm) of the water jet is _____

Detailed Solution for Test: Buoyancy & Floatation - 1 - Question 6

d = 56.4 mm.

Test: Buoyancy & Floatation - 1 - Question 7

When a ship enters sea from a river one can expect it

Test: Buoyancy & Floatation - 1 - Question 8

A large metacentric height in a vessel

Test: Buoyancy & Floatation - 1 - Question 9

For warship, metacentric height of a ship should vary between

*Answer can only contain numeric values
Test: Buoyancy & Floatation - 1 - Question 10

A sprue in a sand mould has a top diameter of 20 mm and height of 200 mm. The velocity of the molten metal at entry of the sprue is 0.5 m/s. Assume acceleration due to gravity as 9.8 m/s2 and neglect all losses. If the mould is well ventilated the velocity (upto 3 decimal points accuracy) of the molten metal at the bottom of the sprue is ____m/s.

Detailed Solution for Test: Buoyancy & Floatation - 1 - Question 10

Velocity of the molten metal at entry of the sprue V1 = 0.5 m/s

Height h1 = 200 mm

Height h2 = 0

Applying bernaulli’s equation between (1) and (2).

Hence, the correct answer is (2.042).

Test: Buoyancy & Floatation - 1 - Question 11

The metacentric height of a passenger ship is kept water lower than that of a naval or a cargo ship. This is because

Detailed Solution for Test: Buoyancy & Floatation - 1 - Question 11

Test: Buoyancy & Floatation - 1 - Question 12

The buoyant force is

Detailed Solution for Test: Buoyancy & Floatation - 1 - Question 12

A body submerged in a fluid experiences an upward thrust due to fluid pressure. This force is called buoyant force and a body immersed in a fluid is buoyed or lifted up a force equal to the weight of the fluid displaced by the body. The body apparently loses as much of its weight as the weight of the fluid displaced by it.

Test: Buoyancy & Floatation - 1 - Question 13

The metacenter is

Detailed Solution for Test: Buoyancy & Floatation - 1 - Question 13

Metacenter is the point of inter section of normal axis of the body with the new line of action of buoyant force when body is tilted.

Test: Buoyancy & Floatation - 1 - Question 14

A tank open at the top with a water level of 1 cm, as shown in the figure, has a hole at a height of 0.5 m. A free jet leaves horizontally from the smooth hole. The distance X (in m) where the jet strikes the floor is

Detailed Solution for Test: Buoyancy & Floatation - 1 - Question 14

Height h = 0.5 m

Acceleration due to gravity g = 9.81 m/s2

velocity of free jet can be calculated using

If t is the time taken for the liquid to travel from the opening to the ground , then we have

t = 0.319 m/s

Distance travelled in time t will be

x = Vt = 3.3132 × 0.319

x = 1.05 m/s

Hence, the correct option is (b)

Test: Buoyancy & Floatation - 1 - Question 15

Three parallel pipes connected at the two ends have flowrates Q1, Q2, and Q3, respectively, and the corresponding frictional head losses are hL1, hL2, and hL3 respectively. The correct expressions for total flow rate (Q) and frictional head loss across the two ends (hL) are

Detailed Solution for Test: Buoyancy & Floatation - 1 - Question 15

Total flow rate, Q = Q1 + Q2 + Q3 and frictional head loss,

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## Fluid Mechanics for Mechanical Engineering

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