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In reciprocal levelling, the error which is not completely eliminated, is due to
Match ListI with Listll and select the correct answer using the codes given below the lists:
ListI
A. Reciprocal levelling
B. Trigonometrical levelling
C. Hypsometry
D. Profile levelling
Listll
1. Involves measuring of horizontal distances and vertical angles in field
2. Involves the principle of boiling point of water variation with altitude
3. Involves observing elevations of a number of points along the centre line and their distance along it
4. Involves the principle of two peg test
The RL, of the point A which is on the floor is 100 m and back sight reading on A is 2.455 m. If the foresight reading on the point B which is one the ceiling is 2.745 m, the RL of point B will be
Since the staff at the elevated point B on the ceiling is held vertically inverted
RL of B = RL of A + B.S.on A + FS on B
= 100 + 2.455 + 2.745 = 105.20 m
The following consecutive readings were taken with a dumpy level:
0.635, 1.525, 2.395, 0.605, 0.805, 0.125
The instrument was shifted after the third and fifth readings. The readings 2.395 and 0.635 respectively represents
A level was set up at a point A and distance to the staff station B was 100 m. The net combined correction due to curvature and refraction as applied to the staff reading is
Net combined correction
= 0.0673 d^{2}. metres where d is in kms
An observer standing on the deck of a ship just sees the top of a lighthouse which is 30 m above the sea level. If the height of the observer’s eye is 10 m above the sea level, then the distance of the observer from the lighthouse will be nearly
If the staff intercept on a staff located at 100 m from the level for five division deviation of the bubble is 0.050 m and if the length of one division of the bubble is 2 mm, then the radius of curvature of the bubble tube is
The radius of curvature of bubble is given by,
Two points A and B are 1530 m apart across a river. The reciprocal levels measured are
The true difference in level between A and B would be
True difference in levels,
Error in collimation adjustment
When the level is at A, the reading on the staff at A is correct. While reading on the staff at B is incorrect. When the level is at B, the reading on the staff at B is correct while reading on the staff at A is incorrect.
Correct readings are
If the observed staff reading at a station is 800.925 m the correction due to refraction is 0.115 m and correction due to curvature is 0.805. Then the correct staff reading will be
True staff reading = obs. staff reading  curve corr. + refr. corr.
= 800.925  0.805 + 0.115
= 800.235 m
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