# Test: Plastic Analysis - 1

## 10 Questions MCQ Test GATE Civil Engineering (CE) 2023 Mock Test Series | Test: Plastic Analysis - 1

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Attempt Test: Plastic Analysis - 1 | 10 questions in 30 minutes | Mock test for Civil Engineering (CE) preparation | Free important questions MCQ to study GATE Civil Engineering (CE) 2023 Mock Test Series for Civil Engineering (CE) Exam | Download free PDF with solutions
QUESTION: 1

Solution:
QUESTION: 2

Solution:
QUESTION: 3

### In a plastic analysis of structures, the segment between any two successive plastic hinges is assumed to deform as

Solution:

The initial slopes and deflections of the beam do not affect the virtual work equations. Thus the displacement diagram can be simplified to consists of straight and undefiected lines i.e. rigid deformation.

QUESTION: 4

Which one of the following is the correct maximum shear capacity of a prismatic beam under plastic design of steel structures?

Solution:

The maximum shear capacity is 0.55 AWFY.

QUESTION: 5

Match List-I (Loaded prismatic beam of uniform Mp) with List-II (Plastic Load) and select the correct answer using the code given below the lists:  Solution:  QUESTION: 6

Match List-I (Shape of structural) with List-II (Shape factor) and select the correct answer using the codes given below the lists:  Solution:
QUESTION: 7

If a uniform beam shown in the figure below has the plastic moment capacity Mp for span AB and 0.9 Mp for span BC, what is the correct virtual work equation? Solution:

Total number of plastic hinges needed for complete collapse of the beam may be given as,
Number of plastic hinges,
= r + 1 = (3 - 2) + 1 = 2 QUESTION: 8

What is the number of plastic hinges formed if an indeterminate beam with redundancy R is to become determinate?

Solution:

The number of plastic hinges required to make an indeterminate beam determinate is R where R is the degree of redundancy. However, for the complete collapse of the beam (R + 1) plastic hinges will be required.

QUESTION: 9

The cross-sectional area and plastic section modulus of the given section are respectively Solution:

Total area, A = 5 x 60 + 5 x 60
= 600 mm2 The centroids of half areas on either side of axis Therefore plastic section modulus QUESTION: 10

A load P is applied at the middle of a simply supported beam of span L. If the beam is made of ductile material, and Mp is the plastic moment, what is the ultimate value of P?

Solution:

The simply supported beam is a determinate one, hence one plastic hinge will be required for its complete collapse. This plastic hinge will be, formed under the load. Hence the maximum bending moment can at the most reach to the plastic moment Mp.
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