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This mock test of Test: RCC for GATE helps you for every GATE entrance exam.
This contains 25 Multiple Choice Questions for GATE Test: RCC (mcq) to study with solutions a complete question bank.
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QUESTION: 1

Assuming the concrete is uncracked, compute Bending stress in extreme fibres of Beam for Bending moment 5kN-m & axial load 200 kN use M25, Fe45

Solution:

QUESTION: 2

In above question, determine cracking moment in kNm.

Solution:

For Cracking of section -

QUESTION: 3

Slab supported on wall on two opposite edges as given in figure. Thickness of wall is 250mm & thickness of slab is 175mm. Consider M20, Fe415 & effective cover 25mm. Find moment of Resistance of slab per meter width using LSM

Solution:

QUESTION: 4

The maximum area of tension reinforcement in beams shall not exceed

Solution:

If tensile reinforcement of beam should exceed 4% of total gross area then some crack will be developed in concrete.

QUESTION: 5

A simply supported beam having effective length 8m subjected to a live load 6 kN/m the size of Beam is given below. Width of support is 300mm. Use M20/Fe415 use LSM. Find spacing for 2-legged 8mm φ - vertical stirrups. Use τ_{c} = 0.20 N/mm^{2 }

Solution:

*Answer can only contain numeric values

QUESTION: 6

In the previous question calculate bend stress. (in N/mm^{2})

(**Important** - Enter only the numerical value in the answer)

Solution:

QUESTION: 7

For a pretensioned beam, Young’s modulus of steel and concrete are 200 GPa and 35.35 GPa, respectively If the ultimate shrinkage strain and ultimate creep coefficient are 200 microns and 1.6 respectively, what is the level of sustained stress in concrete at the level of steel if the loss due to creep is three times the loss due to

shrinkage?

Solution:

QUESTION: 8

In a post tensioned pre-stressed concrete Beam. The end block zone is in between the end of the beam

and the section where

Solution:

QUESTION: 9

Find ultimate axial load carrying capacity of circular column having diameter 500mm. Consider clear cover 50mm. Column having 12Nos-20mm φ longitudinal Reinforcement & 8mm φ spiral Reinforcement.

Use M20/Fe415.

Solution:

QUESTION: 10

In above question find pitch of spiral Reinforcement

Solution:

QUESTION: 11

A simply supported post-tensioned prestressed concrete beam of span L is prestressed by a straight tendon

at a uniform eccentricity ‘e’ below the centroidal axis. If the magnitude of prestressing force is P and

flexural rigidity of beam is EI, maximum deflection of the beam is

Solution:

QUESTION: 12

For maximum hogging bending moment at suppot in a continuous RC beam, live load should be placed on

Solution:

QUESTION: 13

A box girder is subjected to loads as shown in the figure below. The critical section for shear in the bottom slab will occur at

Solution:

Since, the bottom slab will experience tension hence the critical section occurs at the face of wall.

QUESTION: 14

An isolated T-beam is used as a walkway. The beam is simply supported with an effective span of 6 m. The effective width of flange, for the cross-section shown in the figure is

Solution:

QUESTION: 15

Shrinkage deflection in case of rectangular beams and slabs can be eliminated by putting

Solution:

Deflection due to shrinkage is caused due to differential shrinkage which is caused by

unsymmetrically placed reinforcement in beam. Hence, to avoid such deflection compression steel equal to tensile steel must be placed.

QUESTION: 16

The limits of percentage ‘p’ of the longitudinal reinforcement in a column is

Solution:

Minimum reinforcement in Column → 0.8%

Maximum reinforcement in Column → 6%

QUESTION: 17

A reinforced cantilever beam of span 7m, has a cross-sectional area of 250 mm X 500 mm (effective)

if checked for lateral stability and deflection, the beam will

Solution:

Hence the beam will fail in

deflection

(b) Check for lateral stability :

For cantilever beam clear distance between the free end of cantilever and lateral restraint shall not

Hence beam will fail in lateral stability.

Beam will fail in both deflection & lateral stability

QUESTION: 18

In an RCC beam of breadth ‘b’ and overall depth exceeding 750 mm, side face reinforcement required and allowable area of maximum tension reinforcement shall be respectively.

Solution:

*Answer can only contain numeric values

QUESTION: 19

Effective cover – 40 mm

Effective depth – 560 mm

Width of beam – 300 mm

Grade of concrete – M20

Grade of Steel – Fe 415

Take m = 13, σ_{cbc} = 7 N/m^{2}, σ_{st} = 230 N/mm^{2}.

Find moment of resistance of beam using working stress method __________

(**Important** - Enter only the numerical value in the answer)

Solution:

QUESTION: 20

The equivalent bending moment for the beam having loading as follows is

BM = 300 kNm

SF = 120 kN

Torsional moment = 72 kNm

Use M 25/ Fe 415,

b = 400 mm,

d = 450 mm.

Effective cover = 50 mm

Solution:

QUESTION: 21

**Linked Question 21 & 22**

In the design of beams for unit limit state of collapse in flexure (as per IS : 456 : 2000), let the maximum strain in concrete be limited to 0.0025 (in place of 0.0035). For this situation, consider a rectangular beam section with breadth as 300 mm, effective depth as 450 mm, Area of tension steel as 1500 mm^{2}, and characteristic

strength of concrete and steel as 30 Mpa and 250 Mpa respectively.

**Q.** The depth of neutral axis for the balanced failure is

Solution:

QUESTION: 22

At the limiting state of collapse in flexure the force acting on the compression zone of the section is

Solution:

QUESTION: 23

If characteristic compressive strength of concrete fck is defined as strength below which not more than 95% of the test result are expected to fall, the expression of f_{ck} in term of mean strength f_{m} and standard deviation σ would be

Solution:

QUESTION: 24

The minimum and maximum percentage of tensile steel in following beam section is given as

Solution:

Minimum A_{st}

QUESTION: 25

Find Area of tensile steel for following section. If required consider section as doubly

Reinforced

If span of beam is 5m & external load is 20 kN/m. Use LSM. Beam is simply supported

Solution:

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