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In the tension test of a bar the fractured surface shows a truncated cone, the material may be:
In the engineering stress-strain curve for mild steel, the Ultimate Tensile Strength (UTS) refers to
The engineering stress-strain curve for mild steel is
Ultimate tensile strength represents the maximum stress that a material can withstand without Fracture.
_______ is the capacity of material to absorb energy when it is elastically deformed and then upon unloading, to have this energy recovered.
Resilience: It is energy absorbed by a member in elastic region. It denotes the capacity of material to absorb energy when it is elastically deformed and then upon unloading, to release this energy.
Toughness: It is energy absorbed by member just before its fracture.
The shear modulus of a material is half of its Young’s modulus. What is the value of its Poisson’s ratio?
It is given that the shear modulus is half of Young's modulus and the relationship between shear modulus (G) and poisson's ratio (E) is given as follows:
A mild steel wire is 10 mm in diameter and 1 m long. If the wire is subjected to an axial tensile load 10 kN, find an extension of the road (Take E = 200 × 109 Pa) :
The formula for extension is given as follows where, P = load , L = length, A = area and E = 200 x 109 Pa. Substituting values of P,L,A and E.
The ratio of strengths of solid to hollow shafts, both having outside diameter D and hollow having inside diameter D/2, in torsion, is
A simply supported beam is subjected to a uniformly distributed load. Which one of the following statements is true?
For section AB
For equilibrium, ∑M0 = 0
A steel plate of side ‘a’ (2d) is enclosed in a closely fitting rigid support as shown. Assume friction between plate and support is zero. Determine the free expansion in x - direction of the plate due to heating by ΔT – (Poison ratio is μ & thermal co - eff. α)
σx = 0
σy = −αTE
εy = −αT
εx = −μεy = μαT = δa/a
ϵx = Free expansion due to temperature change + Expansion due to lateral strain
= a α Δ T + μ a α Δ T (due to y direction)
= a α Δ T (1 + μ)
For a cylindrical bar of 30 mm dia& 900 mm length, during a tension test, it is found that longitudinal strain is 4 times of lateral strain. The bulk modulus for the bar is (X) × 105 N/mm2 (if E = 3 × 105 N/mm2) The value if X is ___________
E = 3 × 105 N/mm2 & E = 3k (1 – 2μ).....(1)
From (1) we get K = E/3(1−2μ) [∴μ=0.25 given]
put μ=0.25 in equation 1,we get
A cantilever beam has the cross-section of an isosceles triangle and is loaded as shown in figure. If the moment of inertia of the cross-section Izz = 1/36m4, then the maximum bending stress is