Civil Engineering (CE) Exam  >  Civil Engineering (CE) Tests  >  GATE Civil Engineering (CE) 2025 Mock Test Series  >  Test: Torsion of Shafts - 2 - Civil Engineering (CE) MCQ

Test: Torsion of Shafts - 2 - Civil Engineering (CE) MCQ


Test Description

10 Questions MCQ Test GATE Civil Engineering (CE) 2025 Mock Test Series - Test: Torsion of Shafts - 2

Test: Torsion of Shafts - 2 for Civil Engineering (CE) 2024 is part of GATE Civil Engineering (CE) 2025 Mock Test Series preparation. The Test: Torsion of Shafts - 2 questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The Test: Torsion of Shafts - 2 MCQs are made for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Torsion of Shafts - 2 below.
Solutions of Test: Torsion of Shafts - 2 questions in English are available as part of our GATE Civil Engineering (CE) 2025 Mock Test Series for Civil Engineering (CE) & Test: Torsion of Shafts - 2 solutions in Hindi for GATE Civil Engineering (CE) 2025 Mock Test Series course. Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free. Attempt Test: Torsion of Shafts - 2 | 10 questions in 30 minutes | Mock test for Civil Engineering (CE) preparation | Free important questions MCQ to study GATE Civil Engineering (CE) 2025 Mock Test Series for Civil Engineering (CE) Exam | Download free PDF with solutions
Test: Torsion of Shafts - 2 - Question 1

A shaft turns at 150 rpm under a torque of 150 Nm. Power transmitted is

Detailed Solution for Test: Torsion of Shafts - 2 - Question 1

Power transmitted is given by, 

= 750πW = 0.75πkw

Test: Torsion of Shafts - 2 - Question 2

The outside diameter of a hollow shaft is twice its inside diameter. The ratio of its torque carrying capacity to that a solid shaft of the same material and the same outside diameter is

Detailed Solution for Test: Torsion of Shafts - 2 - Question 2

The torque carrying capacity Tis given by 

Let outside diameter of hollow and solid shaft = 2d
∴ Inside diameter of hollow shaft =  d

 

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Torsion of Shafts - 2 - Question 3

A round shaft of diameter ‘d and length T fixed at both ends A and B is subjected to a twisting moment T at C, at a distance 114 from A. The torsional stresses in the parts AC and CB will be

Detailed Solution for Test: Torsion of Shafts - 2 - Question 3

Test: Torsion of Shafts - 2 - Question 4

A solid shaft of diameter D carries a twisting moment that develops maximum shear stress τ. if the shaft is replaced by a hollow one of outside diameter ‘D’ and inside diameter D/2, then the maximum shear stress will be

Detailed Solution for Test: Torsion of Shafts - 2 - Question 4

Test: Torsion of Shafts - 2 - Question 5

In a rectangular shaft subjected to torsion, the maximum shear occurs at

Detailed Solution for Test: Torsion of Shafts - 2 - Question 5

Test: Torsion of Shafts - 2 - Question 6

The ratio of the moment of resistance of a solid circular shaft of diameter D and a hollow shaft (external diameter D and internal diameter d) is given by

Detailed Solution for Test: Torsion of Shafts - 2 - Question 6

As we know

Test: Torsion of Shafts - 2 - Question 7

If a shaft of diameter d is subjected to a torque Tand a bending moment M, the maximum shear stress is

Test: Torsion of Shafts - 2 - Question 8

The diameter of shaft B is twice that of shaft A Both shafts have the same length and are of the same material, if both are subjected to same torque, then the ratio of the angle of twist of shaft' A to that of shaft B will be

Detailed Solution for Test: Torsion of Shafts - 2 - Question 8

Test: Torsion of Shafts - 2 - Question 9

If a shaft is turning at N r.p.m and the mean torque to which the shaft is subjected is T N-m, the power transmitted by the shaft in kW would be

Detailed Solution for Test: Torsion of Shafts - 2 - Question 9

Test: Torsion of Shafts - 2 - Question 10

A shaft of diameter 'd' and length L is subjected to twisting moment T, shear angle developed in shaft is 0.001 rad. Now the length of the shaft is doubled, but the diameter and torque remain the same what will be the shear angle?

Detailed Solution for Test: Torsion of Shafts - 2 - Question 10

In a shaft subjected to a torque TTT, the angle of twist θ\thetaθ is given by the formula:

θ=TLGJ\theta = \frac{T L}{G J}θ=GJTL​

where:

  • T is the applied torque,
  • L is the length of the shaft,
  • G is the modulus of rigidity of the material,
  • J is the polar moment of inertia, which for a circular shaft of diameter ddd is J=πd432J = \frac{\pi d^4}{32}J=32πd4​.

Since T, G, and d remain constant in both cases, the angle of twist θ\thetaθ is directly proportional to the length LLL.

In the initial case, the angle of twist is given as:

θ=0.001 rad\theta = 0.001 \, \text{rad}θ=0.001rad

When the length LLL is doubled, the new angle of twist θ′\theta'θ′ will be:

θ′=2⋅θ=2⋅0.001=0.002 rad\theta' = 2 \cdot \theta = 2 \cdot 0.001 = 0.002 \, \text{rad}θ′=2⋅θ=2⋅0.001=0.002rad

Thus, the new shear angle developed in the shaft will be 0.002 rad.

31 docs|280 tests
Information about Test: Torsion of Shafts - 2 Page
In this test you can find the Exam questions for Test: Torsion of Shafts - 2 solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Torsion of Shafts - 2, EduRev gives you an ample number of Online tests for practice

Top Courses for Civil Engineering (CE)

Download as PDF

Top Courses for Civil Engineering (CE)