The current flowing through the 3 Ω resistor R_{1} is _____ A.
Apply nodal at A:
Magnitude wise: 2 A
An opamp has a voltage gain of 100 dB at dc and a unity gain frequency of 5 MHz. The lower 3dB cut off frequency is _______ Hz.
100 dB voltage gain
20 log (Gain) = 100
Gain = 10^{5}
GBW = 5 MHz
Low frequency 3dB =
= 50 Hz.
An opamp with slew rate 1 V/μ is used in the circuit below input step voltage V_{i} = V sin (10^{5}t) is given, the maximum value of V such that no raise time distortion occurs at the output is _____V.
The output V_{o} = 3V sin (ω_{0}t)
For no distortion to occur
3Vω_{0} ≤ SR
The circuit shows an analog voltmeter of very high input impedance that uses an inexpensive moving coilmeter. The voltmeter measures the voltage ‘V’ applied between the opamp’s positiveinput terminal and ground. Assuming that the moving coil produces fullscale deflection when the current passing through it is 100 μA, the value of R (in kΩ) to obtain fullscale reading at +10 V is
V_{A} = V (virtual ground)
Circuit shows an opamp circuit used for generating the square waveform.
If the output frequency required in 1 kHz. then the possible values of R_{1 }and R_{2} can be respectively
Frequency of oscillation
If R_{1} = 2k
R_{2} = 0.859 × 2
= 1.7 k
Option 1 is correct.
The circuit shows the series voltage regulator.
If reference voltage V_{ref} is 2V and R_{1} = 3K, R_{2} = 1K, β = 99 for both transistors. Then the value of current I_{0} in microamperes is _____ μA.
V_{} = V_{+} = 2V
= 2 mA
I_{1} = (1 + β) (1 + β) I_{0}
2 mA = 10^{4} I_{0
}
I_{0} = 0.2 uA
The circuit shows an – opamp in Schmidt Trigger configuration. If the hysteresis width is 3V. Then the value of R_{1} and R_{2} is
For the amplifier circuit shown, the opamp can deliver a maximum current of 100 mA and is powered by ±15 V supply. If the input to the amplifier is a triangular waveform as shown. The peak value of the output waveform is ______.
The circuit is noninverting.
Amplifier:
= 11V
However the current flowing through load when V_{0} = 11 V is
Which is more than the current opamp can supply.
Thus peak value is limited by the maximum current:
50 Ω ≪ 110 kΩ
All the current flows through 50 Ω resistor.
V_{0} = (100 mA) (50 Ω)
= 5 V
An opamp circuit is shown in the figure. If V_{in} is an AC source of frequency ω.
Consider the following statements:
a) For ω Circuit is an integrator
(b) For ω circuit is an Amplifier
Circuit acts like an Integrator
Circuit acts an Inverting Amplifier
The given conditions in question is opposite Hence None of a and b is correct
The average power delivered by the 3 V source is ________ mW.
V_{} = V_{+} = 3 V [Virtual ground]
Current through 1 k resistor
I = 1 mA
Voltage across 1k resistor from voltage division
Voltage across
V_{o} = 15 V
KVL at V_{+} node:
3 – I'(8) = V_{o}
3 – I'(8) = 15
3 – 15 = I'(8)
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