For the Wienbridge oscillator circuit shown below, the condition for bridge balance is
At oscillator frequency
i.e. gain of noninverting amplifier
⇒ R_{B} = 2R_{A}
Find the value of inductance in (mH) in the oscillator shown below to achieve a frequency of oscillation = 100 KHz is
For the circuit shown in the figure the value of R to get oscillation of 100 kHz is ________ KΩ.
The given oscillator is Colpitts’s oscillator
The condition for oscillation is
Aβ=1
A = R_{2}/R_{1}
β=C_{2}/C_{1 }
The figure shows a phaseshift oscillator circuit with voltage follower buffer stages.
The value of R_{2}/R required for sustained oscillations is _____.
[Assume ideal opamps and neglect loading effect].
Transfer function of first RC network
RC networks are identical and no loading effect
The amplifier A_{3} is connected in inverting mode
The loop gain is
Substitute real part of denominator to zero
At this frequency
The value of R in oscillator circuit shown in a given circuit below is chosen such that it oscillates at an angular frequency of ω. The value of ω and the required value of R will respectively be
Hartley oscillator
Amp with +ve F.B
Loop again AB = 1 + j0
At oscillation
∠AB = 0 (no reactance X_{L} = X_{C})
At frequency of oscillation look lies resistive Network
For ideal op amp
Use voltage division Rule
R + 1 = 21
R = 20 kΩ
R = 2 × 10^{4}Ω
The frequency of oscillation of the circuit in kilohertz is ______ kHz.
The given circuit is wein bridge oscillator.
R_{3} = R_{4} = 159 KΩ
C_{1} = C_{2} = 1 nF
= 10^{3} HZ
= 1 KHZ
For the transistor oscillator circuit given below the frequency of oscillation is 8.5 kHz. The value of the collector resistor approximately is
In a transistor phase shift oscillator the oscillation frequency
R, C are the resistor and the capacitor in phase shift circuit
R_{C} is collector capacitance
⇒ R_{C} = 2R = 10 kΩ
The oscillation frequency if the belowshown oscillator is 1 kHz then the value of ‘L’ is ______ mH
The given oscillator is Hartley oscillator, where the oscillation frequency.
= 253.3 mH
L_{eq} = L + 5 mA
⇒ L = 253.3 – 5
= 248. 3 mH
For the circuit shown the value of R_{1} and R_{2} such that the circuit generates oscillations of frequency 274 Hz is [Assume the time constant of the feedback RC network is 0.01 sec]
Given figure is of Astable multivibrator,
Time constant is given by
β = feedback factor
τ = time constant of feedback loop:
Option 3 satisfies the condition
The frequency of oscillation of the circuit shown below is ________ Hz.
The given oscillator is Wienbridge oscillator with R = 5 kΩ, C = 1 μF
⇒ frequency of oscillation f = 1/2πRC
= 31.8 Hz
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