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Which of the following states the meaning of the idiom ‘Into the bargain’?
Direction: Find the correct relationship between the given quantities
Quantity I: Let E be the set of all integers with 6 in their unit place. The probability that a number chosen from the set {10, 11, 12, ........59} is a member of E is?
Quantity II: A boy speaks truth in 70% of cases while another boy speaks truth in 65% cases. The probability that they will contradict each other on stating the same fact is?
The favourable outcomes are {16, 26, 36, 46, 56} i.e. 5
Probability = 5/50 = 0.1
Quantity II: Boy 1 speaks truth in 70% cases so 70/100 =7/10 and
Boy 2: 65/100 = 13/20
Boy 2 does not speak truth in 35/100 cases i.e. 7/20
Probability= p (A')*p (B) +p (A)*p (B’)
[7*7/ (10*20)]+ [3*13/ (10*20)]
= 0.44
A square metallic sheet of an area of 1296 square cm is used for making the toys. For taking the metallic sheet from that square – four equal sized of the circular plates have been cut –off. If a fencing with the Silver thread is required to make the base of toys, how many rolls of the thread is required, if a roll contains 30 cm of the thread only?
⇒ Side= 36
Radius of each circular plate = ¼ of 36 = 9 cm
Circumference of each plate = 2 π 9 = 56.57 cm
Total Circumference = 4 *56.57 = 226.29 cm
No. of rolls = 226.29/30= 7.54 = 8 rolls
The wrong (misfit) number of the sequence 36, 81, 144, 225, 256, 441 is
6^{2} = 36
9^{2} = 81
12^{2} = 144
15^{2} = 225
18^{2} = 324 ≠ 256
21^{2} = 441
Thus the wrong number is 256
Hence Option D is correct
Direction: Read the pie chart given below and answer the following questions
The pie chart given shows the population of India in the 7 states considering there is no other states apart from these.
How much percent more is the population of UP than that of Odisha?
Now for percentage we have to calculate how much more population is in UP with respect to Odisha. So,
% more= (27⁰×100)/ 36⁰
= 75%
Direction: In the following question, choose the word opposite in meaning to the given word as your answer.
Drought
Drought (noun) means a prolonged period of abnormally low rainfall, leading to a shortage of water. Its opposite is ‘flood’, which means an overflow of a large amount of water beyond its normal limits.
Direction: Study the information carefully and answer the questions given below.
P is standing north of Q at a distance of 6m. R is standing toward east of P at a distance of 6m. R is to the north of S and distance between them is 6m. P is facing north direction, R is facing east, S is facing North and Q is facing towards west direction. All of them walk straight for 3m.
What is the distance between the final position of P and Q?
3√10m
Let T be the final position of P and L be the final position of Q.
Now LT = √(3^{2} + 9^{2}) = √(9 + 81) = √ 90 = 3√10m
In the following question, a statement has been given followed by two arguments numbered I and II. Based on the argument, you have to decide which of the following argument is strong and which is a weak argument.
Statement: Shiva trilogy written by Amish Tripathi is the best fiction book.
Arguments
I. Yes, None other fiction books have three parts.
II. No, the best fiction book is subjective and it always differs from person to person.
Best fiction book or novel is a subjective thing and differs from person to person. Hence, the second argument is strong.
A year after the deadliest Ebola outbreak ever in Africa, the virus has resurfaced in Congo this time around. It is not clear yet how the first victim—a man who has since died—caught the virus. But this outbreak is not the first in Congo; the country has suffered seven prior epidemics of the virus since 1976.
Which of the following is a conclusion that can be drawn from the above paragraph?
It has been said that the biggest ever Ebola epidemic in Africa struck last year. Hence, (A) is false.
The paragraph says that the first victim of the most recent Ebola outbreak in Congo is dead. Hence, (B) can be concluded from the paragraph.
It has nowhere been mentioned that Congo was not affected by last year’s epidemic. Hence (C) cannot be concluded.
Scientists have not yet figured out how the epidemic resurfaced this time, since the first victim is dead. Hence (D) cannot be concluded.
Direction: Following bar graphs shows time taken by different pipes to fill that particular percentage of tank which is described in tabular data. For Ex Pipe 1 fills the 10 % of tank in 6 mins.
Now, read the following data and answer the question carefully:
A Tank has three pipes; two of them are used to fil the tank while another one used to empty the tank namely: pipe 3, pipe 5 to fill the tank and a new third pipe for making the tank empty. When all three pipes are open, 7/18th part of the tank is filled in 1 hours. What is the ratio of the efficiency of Pipe3: Pipe 5: all three pipes working together.
part of work in one hour =
(P3+P5+Third pipE. X 1 = 7/18th part of work
⇒ 7/18th part of work = 1 hr
⇒ Total work done = 18/7 hr by all three pipes
Pipe 3 does 50% of work in 90 mins
100 % of work = 90/50 * 100 = 180 mins = 3 hr
Pipe 5 does 50% of work in 60 mins
100 % of work = 60/50 * 100 = 120 mins = 2 hr
Time Tw Efficiency
Pipe 3 = 3 hr Total work
Pipe5 = 2 hr Total work
All three = 18/7 hr Total work
hence efficiency ratio: 6: 9: 7
Find the unit normal vector of the cone of revolution z^{2} = 9x^{2 }+ 15y^{2} at a point (1,0,3)
Minimum of real value function f(x) = (x−1)^{2/5} occurs at x equal to
as f(x) is square of hence its min, value be 0 where at (x=1)
The transfer function of a system is 10/(s^{2 }+ 2s + 10). Find the nature of the given system.
ω_{n}^{2}/(s2+2ζω_{n}s+ω_{n}^{2}).
Hence, ω_{n}^{2 }= 10 ; 2 ζωn = 2 ⇒ ζ = 0.316
For 0 < ζ < 1, the system is said to be Underdamped.
In a transistor circuit , I_{CO} = I_{CBO} = 2μA , also it is given that α = 0.98
Then the value of I_{CEO} is _______(μA).
There are two energy levels E_{1} and E_{2}. E_{1} is E eV above the fermi level and E_{2} is E eV below the fermi level.
P_{1} = the probability of E_{1} being occupied by an electron.
P_{2} = the probability of E_{2} being empty.
Then, which of the following is correct?
where EF is Fermi level or Characteristics energy, for the crystal in eV. The fermi level represents the energy state with 50 percent probability of being filled if no forbidden band exists.
Therefore, P_{1} And P_{2} can be calculated by using Fermi Dirac probability function.
For P_{1}
Match List I (Regions of Bipolar Transistor in a Monolithic IC) with list II (Physical Properties)
List I
a) Emitter
b) Base
c) Collector
d) Substrate
List II
(1) Moderate resistivity
(2) Very high resistivity
(3) Large size
(4) Very high Conductivity
Select the correct answers from the following.
Emitter – High Doping and very high conductivity
Collector – Large Size
Substrate Very high resistivity
Base Moderate resistivity
Consider the circuit shown in the figure below
v(t) = 80e^{−1000t}V ;t>0
i(t) = 5e^{−1000t}mA ;t>0
the energy dissipated (in μ) by the resistor for 0 < t="" />< 0.6="" ms="" will="" be="" />
A practical voltage source consists of:
While analysing a twoport network, which of the following parameters are obtained when oneport variables are expressed in terms of the other port variables?
(V_{1},I_{1}) = f(V_{2},  I_{2})
The parameters so obtained are the Tparameters or the ABCDparameters.
These are used for the analysis of the power transmission line. The input and output ports are the sending and the receiving ends respectively.
Consider the following sentences regarding a periodic signal
a) A periodic signal always repeats itself after minimum fundamental time period T.
b) A periodic signal is exist from ∞ to +∞ and converse is also true.
c) A periodic signal exist from ∞ to +∞.
Which of the following is/are correct option?
B A periodic signal is only exist from ∞ to +∞ and converse is not true because any signal or anything practically always take birth from origin means from it increases. If it comes from positive to negative then it is a decaying signal not a periodic signal. Thus, option A is the correct answer.
The impulse response of a second order under damped system starting from rest is given by
C(t) = 12.5e^{8t}cos 6t
What are the responsive value of natural frequency and damping ratio of the system?
If x(t) = δ(2t/3), what will be its amplitude at t = 0?
δ(t) = 0, t ≠ 0
≠ 0, t = 0 (Very Large Infinite)
Since delta function represents an infinite amplitude spike at t = 0 having area = 1.
Hence, value of x(t) at t = 0 would be infinite
For the CE amplifier shown, calculate value of lower cutoff frequency F_{L} (in Hz) due to C_{2}
In the given figure, β = 100, the magnitude of voltage gain (V_{0}/V_{in}) will be ___
Voltage gain (A_{v}) = g_{m}R_{c}
Calculate the hysteresis width (in Volts) for an inverting Schmitt trigger with feedback fraction 0.5. Assume the supply voltage to be 1
Given: β = 0.5, Vcc = 10V
Hysteresis Voltage V_{H} = V_{UT}  V_{LT}
V_{UT} = +β x Vcc
V_{LT} = β x Vcc
V_{H} = 2 x β x Vcc
V_{H} = 2 x 0.5 x 10
V_{H} = 10V
For a given sampleandhold circuit, if the value of the hold capacitor is increased, then
For a capacitar,
Drap rate decreases as capacitar value is increased
For a capacitar,
Q = cv = i × t
⇒ t ∝ c
∴ Acquisition time increases as capacitar value increased
The amplitude of a random signal is uniformly distributed between 5 V and 5 V.
If the signal to quantization noise ratio required in uniformly quantizing the signal is 43.5 dB, the step size (in V) of the quantization is approximately
Which is close to 0.0667 Volts
The Potential (scalar) distribution in free space is given as V = 10y^{4} + 20x^{3}. if ε_{0} is permittivity of free space then the charge density ρ at the point (2,0) is
At paint (2,0)
ρ = 240ε_{0}
For a telephone line, β = 0.02rad/km. If frequency is 1 kHz. Calculate time taken to travel 3.14 km by the wave in
Consider an airfilled rectangular waveguide with inside dimensions 5 cm x 2cm. If the wave impedance is 222.24 Ω for TM_{11} mode of propagation. Then the operating frequency (in GHz)is given by
A 1MHz uniform plane wave propagates through fresh water for which σ = 0, μ_{r} = 1,ε_{r} = Calculate wavelength in meters.
but μ = μ_{0}μ_{r} and ε = ε_{0}ε_{r}Also Ω = 2π x 10^{6}
β = 0.185rad/m
λ = 2π/ β = 2π/0.185
λ = 33.963m
Which of the following is correct for 1110100 ÷ 1010?
Which of the following coding scheme is most suitable for coding the successive positions in 8position digital shaft encoder?
Hence option B is correct as it signify only 1bit change between two successive codes.
000→001 →011→010→ 110→111→101→111
12 signal each bandlimited to 5 KHz are to be transmitted over a single channel by freq. division multiplexing. If AMSSNB modulated guard band of 1 KHz is used, then the bandwidth of the multiplexed signal will be
There would be 11 guard band between 12 signal,
So, guard band width
Total band width = 60 + 11 = 71 KHz
ln INTEL 8085, suppose the peripheral mapped l/O has address length of M and memory mapped l/O address length of N. Then M+N =_______.
M = 8
Memory mapped l/O has address length
N = 16
M + N = 8 + 16 = 24
Find the bandwidth (in rad/s) of a parallel GLC resonant circuit whose transfer function is
On comparing the given T.F with the standard T.F,
Bandwidth = G/C = 2 rad/s.
A 70 kHz bandwidth is to accommodate 7 AM broadcast signals simultaneously. The maximum modulation frequency must each station be limited to _____ kHz. Assume that a guard band of 5 kHz is also present.
A carrier frequency modulated with a sinusoidal signal of frequency 4 kHz resulting in a maximum frequency deviation of 7kHz. The bandwidth of the modulated signal is
BW = 2(β + 1)f_{m}
Consider two real valued signals, x(t) bandlimited to [−500 Hz, 500Hz] and y(t) bandlimited to [−1kHz, 1kHz]. For z (t) = x(t). y(t), the Nyquist sampling frequency (in kHz) is __________
x(t) is band limited to [−500Hz, 500Hz] y(t )is band limited to [−1000Hz, 1000Hz]
z(t) = x (t).y(t)
Multiplication in time domain results convolution in frequency domain.
The range of convolution in frequency domain is [−1500Hz, 1500Hz]
So maximum frequency present in z(t) is 1500Hz Nyquist rate is 3000Hz or 3 kHz
The laplace transform of a signal x(t) is
then the value of ∅ in degrees is
Taking inverse laplace
We know that
Using above equation
So, on comparing θ = 30º
A sinusoidal oscillator is built using an amplifier of real gain A, infinite input impedance and the feedback(β) network as shown in the figure.
If Z = jX then Z_{0} is equal to
For zero phase shift
Z_{0} + 2 = 0 (As Z_{0} + 2Z is imaginary)
Z_{0} = – 2Z = – 2jX
Consider the three transistor current source in figure below. Assume all transistor are matched with finite gain and early voltage V_{A} = ∞. The expression for I_{0} is
The circuit is as follows
Two 4ray signal constellations are shown. It is given that ϕ_{1} and ϕ_{2} constitute an orthonormal basis for the two constellations. Assume that the four symbols in both the constellations are equiprobable. Let N_{0}/2 denote the power spectral density of white Gaussian noise.
The ratio of the average energy of Constellation 1 to the average energy of Constellation 2 is:
Average energy of constellation 1 is
Average energy of constellation 2 is
In an analogue cellular system, find the number of channels when total spectrum allocation (Bt) is 12.5 MHz per simplex band with guard band (Bguard) as 10 kHz having channel bandwidth (Bc) as 30 kHz.
Number of channels in a FDMA system be calculated as N = B_{t}B_{guard}/B_{c}
_{where}
_{N is number of channels}
_{Bt is total spectrum allocation}
_{Bguard is guard band}
_{Bc is channel bandwidth}
_{Calculating channels: N = BtBguard/Bc}
_{N= 12.5 x 106 2(103) / 30 x 103}
_{= 416 channels}
In synchronous TDM, there are four inputs and data rate of each input connection is 3 kbps. If 1 bit at a time is multiplexed, what is the duration of each frame?
Given, N = 4n = 1 bit f_{s} = 3kbps
bit rater_{b} = n.N.f_{s} = 1 x 4 x 3kbps = 12 kbps
A specimen of a Si has a resistivity of 200 Ωkcm , magnetic flux B = 0.3 Wb/m^{2} and d = w = 6mm. if the value of hall voltages and hall currents are 60mV and 10 μA. Then the value of μ_{p} is ______(cm^{2}/Vsec)
= 120 m^{3}/C
Therefore, μ = σR_{H}
=5 × 10^{4} × 360
=5 × 10^{4} × 120
= 600 cm^{2}/Vsec
Silicon is doped with boron to a concentration of 4 × 10^{17} atoms/cm^{3}. Assuming the intrinsic carrier concentration of silicon to be 1.5×10^{10}/cm^{3} and the value of kT/q to be 25 mV at 300 K
Compared to undoped silicon, the Fermi level of doped silicon?
E_{2} – E_{1} = kTln (N_{A}/n_{i})
N_{A} = 4 × 10^{17}
n_{i} = 1.5 × 10^{10}
E_{2} – E_{1} = 25 × 10^{3 }e ln 4 × 10^{17}/1.5×10^{10} = 0.427eV
Hence Fermi level goes down by 0.427 eV as silicon is doped with boron.
The transmission line shown in figure is 40 m long and has V_{g} = 15ÃO^{o} V_{rms}, Z_{o} = 30 + j 60W and V_{L} = 5 Ã–48^{o} V_{rms}. If the line is matched to the load, then the magnitude of sending – end current I_{in} is
Consider the following synchronous counter made up of JK, D and T flipflops.
Find the modulus value of the counter.
Consider characteristic equation of D FlipFlop : Q_{N+1} = D
Q_{N+1 }= Q_{2}….(ii)
Consider characteristics equation of TFlipflop: Q_{N+1} = T⊕Q_{N}
Q_{x+1} = Q_{1}⊕Q_{0}
Using equations (i), (ii) and (iii)
The number of used states = 5
∴ Modulus value of the counter = 5.
Consider the following kmap, P, Q, R are don’t cares. What should be the values of P, Q, R in order to get the minimized SOP expression?
SOP = yw + xy = y(x + w) so total is 4 variable
So. P, Q, R are all zero’s.
and if we put the p=0 and Q = 1, R = 1 then we get wy+xy here also 4 variable so and is D correct
An antenna consist of 4 identical Hertzian dipoles located along zaxis uniformly with λ/8 space apart.
The group pattern function is_________?
Hence option B is correct.
The maximum phase lag provided by the given lag compensator is?
Given network can be expressed as
Find the particular integral of
(D^{2} – 4D +4) y = e^{2x} sinx cosx
For a transmission line at frequency of 300 MHz. We have, first maxima occurs at 1/8 m from the load. Z_{L} = jR_{L} , Where R_{L} = k.R_{0} and R_{0} = characteristic impedance of line.
Then k = _________? (positive value of k)
Hence, we see that R is purely imaginary
As R is purely imaginary
R_{real} = 0
∴ k^{2} − 1 = 0
∴ k = ±1
∴ k = 1............positive value
A signal m(t) is shown
This signal is applied to both phase modulator (with k_{p} as phase constant) and frequency modulator (with K_{f} as frequency constant).
The ratio of k_{f}/k_{p} for same maximum phase deviation is _______?
In phase modulation maximum phase deviation = k_{p}∣m(t)I_{max}
Δϕ = 4.kp…(1)
In frequency modulation
Maximum phase deviation = 2πkf∫m(t)dt∣max
Given
The maximum phase deviation for both techniques is same
i.e., from (1) and (2)
Hence option B is correct.
Calculate the drift velocity of free electrons in a conductor of crosssection area of 10^{4} m^{2} and current of 400 A is flowing through it, assuming free electron density of conductor to be 9 × 10^{28} m^{3}.
Hence option A is correct
The inverse ztransform of the signal x(z) = log(1 + z^{–1}) z > 1 is?
Given,
x(z) = log(1 + z ^{− 1})
Differentiating w.r.t z we get
The input voltage V_{i/P} is 5 + 4sinωt. Assume diode is ideal. Then the average value of output voltage is?
It is a negative clamper circuit and capacitor blocked dc voltage. Hence only Vi/P = 4 sinωt
Hence waveforms are:
Hence avg V_{O/P} = 4 volt
Hence option D is correct.
A die is rolled ‘n’ times until 4 appears then the probability that die must rolled more than 5 times before getting a “4”,
probability of Getting ‘4’ on rolling a die is = ⅙
So, Probability of Not getting ‘4’ is = ⅚
To getting success (get4), die must be rolled more than 5 times
So,
S
P(x > 5) = 1 − P(x ≤ 5)
Getting success in st trial
So
For a pnp BJT with emitter doping concentration of 10^{17} / cm^{3}, Base doping of 5 x 10^{15} / cm^{3} and collector doping of 3 x 10^{14} /cm^{3}. Then under no external voltage V_{CE} is ___ volt?
The value of the Integral is (accurate upto 3 decimal place)
The integral is of the form
Putting the value of s = 3
The openloop transfer function unity feedback system is given by
The breakaway point of the root locus plot is given by
But s = −1.577 doesn't lie on the root locus
Hence s = −0.423 is the breakaway point.
An antenna a power input of 50 π watt and an efficiency of 90%.
The radiation intensity has been found to have a 6maximum value of 140W per solid angle.
The directivity of antenna is ____________.
Power across 20 Ω resistor is 10 watt. Then the power factor of the coil for the given connection is _____
For given code executed in 8085 μp After the PSW value is?
MVI A, 63H
ORA A
ANI 36 H
DAA
A = 63
ORA A: A = 63
Flags: P = 1
Z = 0
S = 0
AC = 0
C = 0
ANI: 63 AND 36
= 22 (0010 0010)
Flags: P = 1
Z = 0
S = 0
AC = 1
C = 0
DAA:
as AC = 1 add 6 (0110) to lower nibble
As C = 0 do not add 6 to upper nibble.
∴ ACC ⇒ 0010 0010
+ 0000 0110
0010 1000
= 28 H
Flags: cy = 0
P = 1
AC = 0
Z = 0
S = 0
21 docs263 tests

21 docs263 tests
