Electronics and Communication Engineering (ECE) > GATE ECE (Electronics) 2023 Mock Test Series > Practice Test: Electronics Engineering (ECE)- 4
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Practice Test: Electronics Engineering (ECE)- 4
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65 Questions MCQ Test GATE ECE (Electronics) 2023 Mock Test Series | Practice Test: Electronics Engineering (ECE)- 4
Practice Test: Electronics Engineering (ECE)- 4 for Electronics and Communication Engineering (ECE) 2023 is part of GATE ECE (Electronics) 2023 Mock Test Series preparation. The Practice Test: Electronics Engineering (ECE)- 4 questions and answers have been
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Practice Test: Electronics Engineering (ECE)- 4 - Question 1
Choose the word or phrase which is nearest in meaning to the key word Lethargy
Practice Test: Electronics Engineering (ECE)- 4 - Question 2
The following question comprise two words that have a certain relationship between them followed by four pairs of words. Select the pair that has same relationship as the original pair of words.
Break : Piece
Practice Test: Electronics Engineering (ECE)- 4 - Question 3
Replace the phrase printed in bold to make it grammatically correct ?
"Even though many companies" are now penetrating rural India, it would help to give India a real chance of witnessing a double digit GDP growth.
"Even though many companies" are now penetrating rural India, it would help to give India a real chance of witnessing a double digit GDP growth.
Practice Test: Electronics Engineering (ECE)- 4 - Question 4
Improve the sentence with suitable options by replacing the underlined word.
He is still in vigorous health although he is on the "right" side of sixty.
Practice Test: Electronics Engineering (ECE)- 4 - Question 5
Complete the given sentence by choosing the correct phrase.
You cannot succeed unless
You cannot succeed unless
Practice Test: Electronics Engineering (ECE)- 4 - Question 6
Chirag decided to give 12% of his salary to his younger brother as a pocket money. But he gave 1260 Rs which was 60% of what he had decided earlier. How much is Chirag’s salary?
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 6
Let x be Chirag’s salary:
x = 17500 Rs
x = 17500 Rs
Practice Test: Electronics Engineering (ECE)- 4 - Question 7
Two pipes can fill a tank in 15 minutes and 25 minutes respectively. Both the pipes are opened together and after some time, the first pipe is closed and the tank is completely full in 15 minutes. For how many minutes is the first pipe opened?
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 7
t = 6 min.
t = 6 min.
Practice Test: Electronics Engineering (ECE)- 4 - Question 8
A and B are required to solve a problem independently. If 1/2 and 1/3 are their respectively probabilities of solving the problem, then the probability that atleast one of them solves the problem.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 8
Probability that atleast one of them solves the problem = P
Practice Test: Electronics Engineering (ECE)- 4 - Question 9
What is the probability that a leap year has 53 Sundays and 52 Mondays?
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 9
In leap year there are 366 days.
There are 52 weeks + 2 days
1. - Mon. + Tue.
2. - Tue. + Wed.
3. - Wed. + Thu.
4. - Thu. + Fri.
5. - Fri. + Sat.
6. - Sat. + Sun. = 53 Sundays + 52 Mondays
7. - Sun. + Mon.
Probability =1/7
There are 52 weeks + 2 days
1. - Mon. + Tue.
2. - Tue. + Wed.
3. - Wed. + Thu.
4. - Thu. + Fri.
5. - Fri. + Sat.
6. - Sat. + Sun. = 53 Sundays + 52 Mondays
7. - Sun. + Mon.
Probability =1/7
Practice Test: Electronics Engineering (ECE)- 4 - Question 10
A certain sum of money is invested for one year at a certain rate of simple interest. If the rate of interest is 3% higher, then the interest earned will be 25% more than the interest earned earlier. What is the earlier rate of interest ?
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 10
r = 12% per annum
r = 12% per annum
Practice Test: Electronics Engineering (ECE)- 4 - Question 11
The circuit shown below is driven by a sinusoidal input 
The steady state output 
is
The steady state output is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 11
Practice Test: Electronics Engineering (ECE)- 4 - Question 12
Determine the value of load resistance 
,so that it receive maximum power from the circuit.
,so that it receive maximum power from the circuit.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 12
Practice Test: Electronics Engineering (ECE)- 4 - Question 13
A plant has the following transfer function, 
For an unit step input determine the time required so that response will settle in 2% of its final value.
For an unit step input determine the time required so that response will settle in 2% of its final value.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 13
Practice Test: Electronics Engineering (ECE)- 4 - Question 14
The open loop transfer function of an unity feedback control system is G(S) = 
What is the range of K so that closed loop system becomes stable ?
What is the range of K so that closed loop system becomes stable ?
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 14
Characteristics equation
= K + S(S+1) (S + 5) = 0
Rough-array
So for stable system K > 0 and
30 – k > 0
k < 30
so 0 < k < 30
= K + S(S+1) (S + 5) = 0
Rough-array
So for stable system K > 0 and
30 – k > 0
k < 30
so 0 < k < 30
Practice Test: Electronics Engineering (ECE)- 4 - Question 15
Determine the peak inverse voltage that appear across the diode in the given circuit.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 15
During positive half cycle capacitor get charge and during negative half cycle the equivalent circuit is shown as
During positive half cycle capacitor get charge and during negative half cycle the equivalent circuit is shown as
Practice Test: Electronics Engineering (ECE)- 4 - Question 16
Determine the power dissipated across the load resistance RL in the given circuit, assume diode is ideal.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 16
= 125 mw
= 125 mw
Practice Test: Electronics Engineering (ECE)- 4 - Question 17
What is the load current 
in the circuit shown below:
in the circuit shown below:
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 17
= – 10mA
= – 10mA
Practice Test: Electronics Engineering (ECE)- 4 - Question 18
How many standard resistor are required to design a 3 bit flash type ADC?
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 18
= 8
= 8
Practice Test: Electronics Engineering (ECE)- 4 - Question 19
Determine the size of ROM required to implement a full-substractor.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 19
For full-substractor, the number of input variable is 3 and output function are 2 So size of ROM,
Practice Test: Electronics Engineering (ECE)- 4 - Question 20
Determine the even part of the signal x(f) where x(t) = 4 Sin t
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 20
x(t) = 4 sint
Since the above signal is an odd signal therefore, its even part is zero.
Since the above signal is an odd signal therefore, its even part is zero.
Practice Test: Electronics Engineering (ECE)- 4 - Question 21
An LTI system is characterized by difference equation y (n) = y (n-1) + x (n). The impulse response of the system is :
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 21
y(n) = y(n – 1) + x(n)
Practice Test: Electronics Engineering (ECE)- 4 - Question 22
Consider the signal 
Let 
denotes the Fourier transform of the signal, the value of 
is
Let denotes the Fourier transform of the signal, the value of is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 22
Practice Test: Electronics Engineering (ECE)- 4 - Question 23
In the given circuit, the forward threshold voltage of the diode is 0.7 and maximum power dissipation across the diode is 21mW. Determine the value of resistance R for safe operation.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 23
Practice Test: Electronics Engineering (ECE)- 4 - Question 24
When a bypass capacitor is connected across the emitter and resistance of a common-emitter BJT amplifier:
Practice Test: Electronics Engineering (ECE)- 4 - Question 25
An amplifier using an op-amp with a slew rate 1 
has a gain of 20 dB. If the peak value of sinusoidal input signal is 1 V then determine the maximum frequency of the input signal that can be amplify without any distortion.
has a gain of 20 dB. If the peak value of sinusoidal input signal is 1 V then determine the maximum frequency of the input signal that can be amplify without any distortion.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 25
For distortion less output,
Practice Test: Electronics Engineering (ECE)- 4 - Question 26
The skin depth of copper at a frequency of 6GHz is 1
the skin depth at a frequency of 24 GHz would be :
the skin depth at a frequency of 24 GHz would be :
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 26
Practice Test: Electronics Engineering (ECE)- 4 - Question 27
An air filled rectangular waveguide with dimension 
where b < a < 2b is to be constructed to operate at 3GHz in dominant mode. The design frequency is at least 20% higher than the cut-off frequency of dominant mode and also at least 20% below, cut off frequency of next higher mode, determine the phase velocity.
where b < a < 2b is to be constructed to operate at 3GHz in dominant mode. The design frequency is at least 20% higher than the cut-off frequency of dominant mode and also at least 20% below, cut off frequency of next higher mode, determine the phase velocity.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 27
Practice Test: Electronics Engineering (ECE)- 4 - Question 28
For FM broadcasting, the frequency deviation is 15 KHz, determine the percentage modulation of the signal.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 28
= 15/75 = 20%
= 15/75 = 20%
Practice Test: Electronics Engineering (ECE)- 4 - Question 29
Auto correlation function of a random signal with zero mean is given as 
The rms value of the AC component of the signal will be
The rms value of the AC component of the signal will be
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 29
Practice Test: Electronics Engineering (ECE)- 4 - Question 30
An angle modulated signal is given as, 
considering s(t) is an FM signal and message signal m(t) is 10 
then determine the value of 
considering s(t) is an FM signal and message signal m(t) is 10 then determine the value of
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 30
dx is equal to
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 31
Practice Test: Electronics Engineering (ECE)- 4 - Question 32
Evaluate 
where C represents a circle Z - 4 = 2,
where C represents a circle Z - 4 = 2,
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 32
Practice Test: Electronics Engineering (ECE)- 4 - Question 33
From his 9 friends (4 boys and 5 girls), Mohan wanted to invite friends for picnic. If there have to be exactly 3 girls in invites, then the number of ways in which he can invite them are,
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 33
Three girls can be selected from 5 girls in 
ways. As number of boys to be invited is not given, hence out of 4 boys he can invite them in 
ways, so total of 
ways. As number of boys to be invited is not given, hence out of 4 boys he can invite them in ways, so total of
Practice Test: Electronics Engineering (ECE)- 4 - Question 34
A dice is rolled 5 times. The probability that 4 will show up exactly 3 times is:
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 34
Probability of getting four is,
Practice Test: Electronics Engineering (ECE)- 4 - Question 35
Consider a vector A given by :
at point is (1, -1, 1) is
at point is (1, -1, 1) is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 35
= 2 – 6 + 1
= –3
= 2 – 6 + 1
= –3
Practice Test: Electronics Engineering (ECE)- 4 - Question 36
Determine 
in the given circuit below
in the given circuit below
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 36
= –4 volt
= –4 volt
Practice Test: Electronics Engineering (ECE)- 4 - Question 37
The Y-parameter of the circuit shown below :
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 37
Practice Test: Electronics Engineering (ECE)- 4 - Question 38
In the circuit shown below, the switch is closed at t=0, determine 
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 38
Practice Test: Electronics Engineering (ECE)- 4 - Question 39
A signal 
is sampled at the rate of 15 Hz and applied to ideal rectangular LPF with cut-off frequency of 10Hz, then the output of filter contains
is sampled at the rate of 15 Hz and applied to ideal rectangular LPF with cut-off frequency of 10Hz, then the output of filter contains
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 39
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 40
Practice Test: Electronics Engineering (ECE)- 4 - Question 41
The ROC of z transform of signal 
is
is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 41
Since there is no any common ROC so, z-transform does not exist.
Since there is no any common ROC so, z-transform does not exist.
Practice Test: Electronics Engineering (ECE)- 4 - Question 42
The system matrix of a continuous time system is described in the state variable form is,
The system is stable for
The system is stable for
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 42
For stable system all the elements in the first column of Routh-array should be positive. In the given option, option (c) satisfy the criteria i.e.,
For stable system all the elements in the first column of Routh-array should be positive. In the given option, option (c) satisfy the criteria i.e.,
Practice Test: Electronics Engineering (ECE)- 4 - Question 43
The maximum permissible distance between two samples of a 10 kHz signal
Practice Test: Electronics Engineering (ECE)- 4 - Question 44
The open-loop transfer function of unity feedback control system is 
The system is stable for.
The system is stable for.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 44
Characteristic equation K + S(S + a) (S + b) = 0
For stability K > 0
and, ab (a + b) – K > 0
K < ab (a + b)
So, 0 < K < ab (a + b)
For stability K > 0
and, ab (a + b) – K > 0
K < ab (a + b)
So, 0 < K < ab (a + b)
Practice Test: Electronics Engineering (ECE)- 4 - Question 45
In the given logic diagram the propagation delays of both the gates are 20 nsec each. The output y is at logic ‘1’ from a long time and at t = 0, the input x change from 0 to 1, so the output goes momentary to logic 0,determine the time required by the output to again maintain its level at logic 1.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 45
So output again becomes 1 after 40 nsec.
So output again becomes 1 after 40 nsec.
Practice Test: Electronics Engineering (ECE)- 4 - Question 46
For the power amplifier circuit shown below, the maximum power dissipated by both output transistor is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 46
The maximum power dissipated by both output transistor is maximum
Practice Test: Electronics Engineering (ECE)- 4 - Question 47
In the circuit A = 1, B = 1, 
what will be the output 
and 
when the clock input (CK) is applied ?
what will be the output and when the clock input (CK) is applied ?
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 47
Practice Test: Electronics Engineering (ECE)- 4 - Question 48
In the given circuit, the feedback factor is :
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 48
Practice Test: Electronics Engineering (ECE)- 4 - Question 49
The current through the resistor R in the given circuit.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 49
Practice Test: Electronics Engineering (ECE)- 4 - Question 50
Determine the operating point of the BJT, in the given circuit.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 50
= 7.85 – 4.3
= 3.55 V
= 7.85 – 4.3
= 3.55 V
Practice Test: Electronics Engineering (ECE)- 4 - Question 51
In the circuit shown in the given figure, assume that the capacitor C is almost shorted for the frequency range of interest of the input signal. Under this condition, the voltage gain of the amplifier will be approximately.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 51
It is common collector configuration (emitter follower) so voltage gain is almost equal to 1, in the given option 
Practice Test: Electronics Engineering (ECE)- 4 - Question 52
For a Si transistor connected as shown in the fig 
= 0.7V. Given that the reverse saturation current of the junction at room temperature is 200 nA, the IC is given by
= 0.7V. Given that the reverse saturation current of the junction at room temperature is 200 nA, the IC is given by
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 52
Since base is connected to collector of the transistor, therefore it works as a diode
Practice Test: Electronics Engineering (ECE)- 4 - Question 53
The Fermi-level of a material is 3eV, then the velocity of electron at Fermi-level is :
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 53
Practice Test: Electronics Engineering (ECE)- 4 - Question 54
Magnetic flux density in certain medium with permeability 
is given by 
. 
is given by,
is given by . is given by,
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 54
The current-density
Practice Test: Electronics Engineering (ECE)- 4 - Question 55
Given field, 
It can be said that A is
It can be said that A is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 55
So given field is conservative
So given field is conservative
Practice Test: Electronics Engineering (ECE)- 4 - Question 56
Two lossless lines are connected as shown in figure below. The input impedance 
seen across the terminal AB is
seen across the terminal AB is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 56
Practice Test: Electronics Engineering (ECE)- 4 - Question 57
An angle-modulated signal is expressed by, 
Determine the range of maximum frequency swing
Determine the range of maximum frequency swing
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 57
= 2 × 75
= 150 KHz
= 2 × 75
= 150 KHz
Practice Test: Electronics Engineering (ECE)- 4 - Question 58
A binary source generates digits 1 and 0 randomly with equal probability. Then the probability three 1 and four 0 with respect to 7 digits generated by the source is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 58
= 35/128
= 35/128
Practice Test: Electronics Engineering (ECE)- 4 - Question 59
Consider the octal signal point constellation in figure shown below. The adjacent signal point in the 8-PSK are separated by a distance 1 unit. Then the radius r of the circle is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 59
r is the radius of circle, by cosine theorem
Practice Test: Electronics Engineering (ECE)- 4 - Question 60
Consider the audio signal with spectral components limited to the frequency band of 300 to 3300 Hz. A PCM signal is generated with a sampling rate of 8000 samples/sec. The required output signal to quantizing noise ratio is 30 dB. The minimum number of bits per sample needed is :
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 60
(SNR) in dB = 1.76 + 20 log L
Where L is the number of levels
So minimum number of levels are 26, and minimum number of bits are 5.
Where L is the number of levels
So minimum number of levels are 26, and minimum number of bits are 5.
Practice Test: Electronics Engineering (ECE)- 4 - Question 61
X is a binary memory less source with P(x=0) = 0.3. This source is transmitted over a binary symmetric channel with crossover probability P = 0.1. Assume that the source is directly connected to the channel, i.e. no coding is employed. Then the error probability at the destination is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 61
Probability of error is given as
Practice Test: Electronics Engineering (ECE)- 4 - Question 62
Given a > 0, we wish to calculate the reciprocal value 
by Newton – Raphson method for f(x)=0 for a=7 and starting with 
= 0.2, the first two iterations would be :
by Newton – Raphson method for f(x)=0 for a=7 and starting with = 0.2, the first two iterations would be :
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 62
Practice Test: Electronics Engineering (ECE)- 4 - Question 63
Consider the system of equations
ax + 3y + z = 5
2x – y + 2az = 3
x + 4y + az = 6
The value of a for which the above equations posses an unique solution.
ax + 3y + z = 5
2x – y + 2az = 3
x + 4y + az = 6
The value of a for which the above equations posses an unique solution.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 63
Determinant of matrix A,
a{– a –8a} –3{2a – 2a} + 1 {1 + 4}
a{– a –8a} –3{2a – 2a} + 1 {1 + 4}
Practice Test: Electronics Engineering (ECE)- 4 - Question 64
Cayley-Hamilton Theorem states that a square matrix satisfies its own characteristic equation. Consider a matrix A = 
the value of 
is
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 64
Practice Test: Electronics Engineering (ECE)- 4 - Question 65
is increasing in the interval given below, choose the correct option.
Detailed Solution for Practice Test: Electronics Engineering (ECE)- 4 - Question 65
x(x – 3) –2 (x – 3) = 0
(x – 3) (x – 2) = 0
So, x = 2, 3
According to curve wave method for increasing function
x(x – 3) –2 (x – 3) = 0
(x – 3) (x – 2) = 0
So, x = 2, 3
According to curve wave method for increasing function
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