Test: Digital Communications - 1
15 Questions MCQ Test GATE ECE (Electronics) 2023 Mock Test Series | Test: Digital Communications - 1
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Consider Y= ax+b, a>0. If the density and distribution functions of x are F. (x) and fx (x), then Fy (y) is equal to
Consider a random process x(t). Which of the following can represent Rx. (r)?
It is required to transmit at 100 Kbit/s and a bandwidth of 2 MHz is used. The
minimum S/N ratio is ___________________
⇒ 
SNR when the system is uncoded is 4 dB, when it is coded is 2 dB then the coding gain is ________________ (dB)
Coding gain = SNR encoded - SNR. coded = 4.dB-2dB = 2dB
In the set up shown below, determine the number of bits required to encode each sample of x (t) such that bandwidth of signal y(t) is greater than 5 MHz.
Nyquist sampler is a sampler that samples a given signal at a rate twice the highest frequencies
fs = 2 fm, f5 = 2 x 350 kHz = 0.7MHz
Band width of output of PCM =
A sinusoidal signal whose peak-peak amplitude is 6 V is modulated using deltamodulator. At what rate should be sinusoidal signal sampled such that slope over load distortion is prevented with step size of 0.942 V?
2A = 6V ⇒ A = 3V
In order to overcome slope over load distortion in delta modulator
The probability of the five possible outcomes of an experiment are given as
Determine the informationrate, if there are 8 outcomes per second.
= 1.875 bits / sec; r=8 outcomes/sec
Information rate R=r.
=15bits / sec
Probability of picking 3 symbols are P0, P1 and P2 respectively. The maximum entropy is achieved, when P0, P1, P2 are
PO =P1 =P2 =P; PO + P1 + P2 = 1; 3P=1 ⇒ P= 1/3
Hartley's law can be defined as r = 2 Blog2 M . When compared to Shannon Hartley theorem, C, M are
Comparing C=B log 
; r = C; 
The probability of a bit decoded correctly at receiver is `p'. If n bits are sent, what is the probability that one bit is decoded correctly?
correct : p; error: 1-p
out of n bits, only one bit is decoded correctly=
A stationary random process x(t) has the following correlation function 
is constant) . Find the psd of random signal x(t).
PSD of input is expressed as
If random variable 'x' has Gaussian pdf with mean M, then y=2x has PDF andmean respectively
so y has pdf N(2m,402) which is Gaussian
If x has P.S.D Sxx (f), then y has P.S.D of ( Assume H(f) is the Fourier Transform
A Gaussian random variable 'x' has mean 1 and variance√2. If y = x2, then the mean of y is
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