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QUESTION: 1

In the circuit shown in fig

i_{1 } = 5sin 3t A and i_{2 }= 3 cos 3t A.

v_{2} = ?

Solution:

=36 sin 3t + 45 cos 3t = 9(4sin 3t + 5cos 3t) V

QUESTION: 2

In the circuit shown in fig. if current i_{1} = 5 cos (500t - 20°) mA and i_{2} = 20 cos (500t - 20°) mA, the total energy stored in system at t = 0 is

Solution:

At t = 0, i_{1} = 4 cos (-20°) = 4.7 mA

i_{2} = 20 cos (-20°) = 18.8 mA,

= 151.3 μJ

QUESTION: 3

L_{eq =} ?

Solution:

QUESTION: 4

L_{eq }= ?

Solution:

QUESTION: 5

L_{eq }= ?

Solution:

QUESTION: 6

L_{eq} = ?

Solution:

QUESTION: 7

The equivalent inductance of a pair of a coupled inductor in various configuration are

(a) 7 H after series adding connection

(b) 1.8 H after series opposing connection

(c) 0.5 H after parallel connection with dotted terminal connected together.

The value of L_{1} L_{2 }, and M are

Solution:

⇒

QUESTION: 8

L_{eq} = ?

Solution:

QUESTION: 9

L_{eq} = ?

Solution:

QUESTION: 10

L_{eq} = ?

Solution:

QUESTION: 11

L_{eq} = ?

Solution:

Let I_{1} be the current through 4 H inductor and I_{2} and I_{3} be the current through 3 H, and 2 H inductor respectively

QUESTION: 12

Consider the circuit shown in fig.

The voltage V_{AG} of terminal AD is

Solution:

QUESTION: 13

Consider the circuit shown in fig

The voltage v_{BG} of terminal BD is

Solution:

QUESTION: 14

Consider the circuit shown in fig.

The voltage v_{GC} of terminal CD is

Solution:

QUESTION: 15

In the circuit of fig. the ω =2 rad/s. The resonance occurs when C is

Solution:

QUESTION: 16

In the circuit of fig, the voltage gain is zero at ω= 333.33 rad/s.

The value of C is

Solution:

QUESTION: 17

In the circuit of fig. at ω = 333.33 rad/s, the voltage gain v_{out} / v_{in} is zero. The value of C is

Solution:

The π equivalent circuit of coupled coil is shown in fig

Output is zero if

QUESTION: 18

The evenin equivalent at terminal ab for the network shown in fig. is

Solution:

Applying 1 V test source at ab terminal,

= 0.25 A

QUESTION: 19

In the circuit of fig. the maximum power delivered to RL is

Solution:

Impedance seen by R_{L} = 10 x 4^{2} = 160 Ω

For maximum poer R_{L} = 160Ω, Zo = 10Ω

= 250 W

QUESTION: 20

The average power delivered to the 8 Ω load in the circuit of fig. is

Solution:

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