In a two element series circuit, the applied voltage and the resulting current are v(t) = 60 + 66sin (10 t) V, i(t) = 2.3sin (10^{3}t + 68.3^{o}) A.The nature of the elements would be
RCcauses a positive phase shift in voltage
v_{o }(t) = ?
10 sin (t + 30°) = 10 cos (t  60°)
V_{o} = ?
The circuit is as shown in fig.
i_{1}( t) = ?
The circuit is as shown in fig
i_{2}(t) = ?
I_{x} = ?
V_{x} = ?
Let V_{o} be the voltage across current source
V_{o}(20 + j10)  (20 + j40) V_{x} = j600
Determine the complex power for hte given values in question.
P = 269 W, Q = 150 VAR (capacitive)
S = PjQ = 269j150 VA
Determine the complex power for hte given valuesin question.
Q = 2000 VAR, pf =09. (leading)
pf = cos θ = 0.9 ⇒ θ = 25.84°
Q = S sin θ ⇒
Determine the complex power for hte given values in question.
S = 60 VA, Q = 45 VAR (inductive)
Q = S sin θ ⇒
Determine the complex power for hte given values in question.
V_{rms} = 220 V, P = 1 kW, Z = 40Ω (inductive)
= 0.8264 or θ = 34.26°,
Determine the complex power for hte given values in question
V_{rms} = 21∠20°V, V_{rms} = 21∠20°V, I_{rms} = 8.5∠50°A
S = V_{rms} I*_{rms} = (21∠20°)(8.5∠50°)
= 61+j167.7VA
Determine the complex power for hte given values in question.
V_{rms} = 120∠30°V, Z = 40 + j80Ω
= 72 + j144 VA
In a two element series circuit, the applied voltage and the resulting current are v(t) = 60 + 66 sin (1000t) V, i(t) = 2.3sin (1000t + 68.3) 3 A. The nature of the elements would be
A relay coil is connected to a 210 V, 50 Hz supply. If it has resistance of 30Ω and an inductance of 0.5 H, the apparent power is
Z= 30 + j(0.5)(2π)(50) = 30 + j157,
Apparent power = 275.6 VA
In the circuit shown in fig. power factor is
= 4  j6 = 7.21∠  56.31°, pf = cos 56.31° = 0.555 leading
The power factor seen by the voltage source is
I_{1} = 1∠36.9°
pf = cos 36.9° = 0.8 leading
The average power supplied by the dependent source is
(2∠  90°)4.8 = I_{x} (4.8 + j1.92) + 0.6I_{x}(8)
I_{x} = 5∠0°, V_{a} = 0.6 x 5 x 8 = 24∠0°,
In the circuit of fig. the maximum power absorbed by Z_{L} is
The value of the load impedance, that would absorbs the maximum average power is
Use Code STAYHOME200 and get INR 200 additional OFF

Use Coupon Code 








