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QUESTION: 1

A parallel resonant circuit has a resistance of 2 kΩ and half power frequencies of 86 kHz and 90 kHz.1. The value of capacitor is

Solution:

BW = ω_{2} - ω_{1} = 2π(90 - 86)k = 8π krad/s

= 19.89 nF

QUESTION: 2

A parallel resonant circuit has a resistance of 2 kΩ and half power frequencies of 86 kHz and 90 kHz.The value of inductor is

Solution:

= 0.16 mH

QUESTION: 3

A parallel resonant circuit has a resistance of 2 kΩ and half power frequencies of 86 kHz and 90 kHz.The quality factor is

Solution:

QUESTION: 4

A parallel resonant circuit has a midband admittance of 25 x 10^{-3} S, quality factor of 80 and a resonant frequency of 200 krad/s.The value of R is

Solution:

Ay mid-band frequency Z = R, Y = 1/R

QUESTION: 5

A parallel resonant circuit has a midband admittance of 25 x 10^{-3} S, quality factor of 80 and a resonant frequency of 200 krad/s.The value of C is

Solution:

= 10 μF

QUESTION: 6

A parallel RLC circuit has R =1 kΩ and C = 1 μF. Thequality factor at resonance is 200. The value of inductor is

Solution:

⇒ L = 25 μH

QUESTION: 7

A parallel circuit has R =1 k , C = 50 μF and L = 10mH. The quality factor at resonance is

Solution:

QUESTION: 8

A series resonant circuit has an inductor L = 10 mH.The resonant frequency ω_{o} = 106 rad/s and bandwidth is BW = 10^{3} rad/s. The value of R and C will be

Solution:

= 100pF

QUESTION: 9

A series resonant circuit has L = 1 mH and C = 10μF. The required R for the BW 15 9 . Hz is

Solution:

⇒

QUESTION: 10

For the RLC parallel resonant circuit when R = 8 kΩ , L = 40 mH and C = 0.25 μF, the quality factor Q is

Solution:

QUESTION: 11

The maximum voltage across capacitor would be

Solution:

Thevenin equivalent seen by L - C combination

Open Circuit : v_{1} = 0, v∝ = 3V

QUESTION: 12

For the circuit shown in fig. resonant frequency f_{o} is

Solution:

Applying 1 A at input port V_{1} = 10 V

voltage across 1 A source

Z_{in} = V_{test}

At resonance Im {Z_{in}} = 0

⇒ ⇒

QUESTION: 13

For the circuit shown in fig. the resonant frequency f_{o} is

Solution:

At resonance Im {Y} = 0

QUESTION: 14

The network function of circuit shown in fig. is

Solution:

QUESTION: 15

Solution:

QUESTION: 16

Solution:

QUESTION: 17

The value of input frequency is required to cause again equal to 1.5. The value is

Solution:

For any value of ω, R,C gain ≤ 1.

Thus (D) is correct option.

QUESTION: 18

In the circuit of fig. phase shift equal to -45^{0} is required at frequency ω =20 rad/s . The value of R is

Solution:

phase shift = - tan^{-1} ωCR = -450°

ωCR = 1,

20 x 1 x 10^{-6} R = 1 ⇒ R = 50KΩ

QUESTION: 19

For the circuit of fig., Vs is the source voltage and the response is the resistance voltage Vo, R = 30Ω and L = 2H. Suppose the input frequency is adjusted until the gain is equal to 0.6. The value of the frequency is

Solution:

QUESTION: 20

Bode diagram of the network function V_{o} /V_{s }for the circuit of fig. is

Solution:

-20 dB/decade line starting from ω = 5.56 rad/s

20 dB/decade line starting from ω = 16.67 rad/s

Hence -20 dB/decade line for 5.56 < ω < 16.67 parallel to ω axis to ω >16.67

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