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GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Electrical Engineering (EE) MCQ


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30 Questions MCQ Test - GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23)

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) below.
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GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 1

Directions: In the given question, the figures contain certain characters. You are required to consider the characters in each figure and follow a similar pattern to find the missing character.

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 1

(4 x 5)2 – (3 x 1)2 = 391
And
(15 x 3)2 – (8 x 5)2 = 425
Similarly,
(8 x 7)2 – (10 x 3)2 = 2236
Thus, the required term is 2236.

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 2

Some amount of acid is taken out of a 54 L vessel full of acid and then an equal amount of water is added to it. The process is repeated once more. As a result, the vessel now contains 24 L pure acid. How much of the acid was taken out initially?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 2
54(1-x/54)2 = 24

or 24/54 = (1 - x/54)2

Therefore, x = 18L

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GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 3

Directions: The following verbal analogy has two parts. One part is complete while the other one is incomplete. Complete the portion that is incomplete by selecting the right choice from the given options.

Son : Nuclear : : ______ : Extended

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 3
A son is part of a nuclear family, and a cousin is part of an extended family.
GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 4

A sum of money compounded annually becomes Rs. 625 in 2 years and Rs. 675 in 3 years. The rate of interest per annum is

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 4
For a difference of 1 year, CI can be computed as SI. Hence From the 2nd year to the 3rd year, interest earned = (675-650) = Rs.50 on Rs.625

Hence, the rate of interest = 50/625x100 = 8% per annum

Alternative method :

Since the values are for consecutive years,

which is the interest component

1/25 = 4%

2/25 = 8%

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 5

Directions: Choose the sentence that best combines the given sentences.

The federal government has diversity of jobs and geographic locations. The federal government offers flexibility in job opportunities that is unmatched in the private sector.

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 5
The subordinator 'because' in choice 3 establishes the logical causal relationship between the subordinate and main clause. Choices 1 and 2 do not make sense. Choice 4 has faulty construction.
GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 6

A jar contains a mixture of two liquids A and B in the ratio 4 : 1. When 10 liter of the mixture is replaced with liquid B, the ratio becomes 2 : 3. The volume of liquid A present in the jar earlier was ______ liters.


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 6
Given

Jar contains a mixture of two liquids A and B in the ratio 4 : 1

Volume of liquid A =4x liters

Volume of liquid B= x liters

∴ Total volume of mixture = 4x + x = 5x liters

∴ 10 liter of the mixture is removed.

∴ Volume of liquid A removed =(4/5)x10 liters = 8 liters

Volume of liquid B removed = (1/5)x10 liters = 2 liters

Again, 10 liter of liquid B is added in place of 10 liters liquid

∴ Volume of liquid A in new mixture = (4x-8) liters

Volume of liquid B in new mixture =(x-2+10) liters = (x+8) liters

According to the question,

⇒3(4x - 8) = 2(x+8)

⇒12x - 24 = 2x + 16

⇒10x = 40

⇒x = 4

∴ Volume of A in earlier mixture = 4x4 liters = 16 liters

Hence, the volume of present in the jar earlier was 16 liters.

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 7

Directions: In the following Venn diagram, rectangle represents number of poets, triangle represents number of novelists and circle represents number of dramatists. Answer the following question.

How many people are novelists but not dramatists?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 7
The sum total of numbers which lies in triangle but outside the circle represents the number of people who are novelists but who are not dramatists.

Hence, the required number is (4 + 3 + 2) = '9'.

Hence, option (2) is the correct option.

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 8

A husband and wife appeared in an interview for two vacancies in the same organisation. The probability of husband’s selection is 1/7 and that of wife’s is 1/5. What is the probability that both of them will be selected?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 8
A : Husband selected, B : Wife selected

Both selected

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 9

Ramu is planning to get wireless internet service at his house. Two service providers A and B offer different rates as shown in the table below.

If Ramu plans on using 25 hours of internet service per month, which of the following statements is true?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 9
When used for 25 hours per month, provider A will cost $20 + 7.5 x $1 (for the hourly charge above the free hours).

This equals $27.50.

Provider B will cost $20 + 5 x $1.50 (for the hourly charge above the free hours).

This equals $20 + $7.50 = $27.50 as well.

So, choice (3) is the correct answer.

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 10

Read the argument given below and then answer the questions.

Chinese manufacturers of everything from tricycles to truck winches, said on Wednesday at the opening of Asia’s biggest trade fair, that their orders were starting to recover from a steep plunge over the winter but that demand from Europe and particularly the United States remained anemic. The economy had grown at an annual pace of “around 6 percent” in the first quarter. That would be the slowest pace since quarterly records began in 1992, indicating that strong consumer spending and heavy government investments had failed to offset a nose dive in exports.

The above passage assumes :

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 10
Options (A) and (B) are incorrect as there no specification if the figures are certainly in line with the expectations of the economists, as well as, we don’t know about other economies in the passage. Options (C) is uncertain and inappropriate assumptions respectively. However it is evident from the passage that the nose dive in exports has led Export-dependent countries experience heavy losses, which is also noticeable in the faint signs of the uptick in China Trade. So, option (D) is the correct assumption.
GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 11

If v = 2xy, the analytic function f (z) = u + iv is

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 11

by Milne’s Method f’(z) = g(z,0) + ih(z,0) = 2z + i0 = 2z

On integrating f(z) = z2 + c

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 12

For a system of linear equations having 2 variables, the coefficient matrix A is defined as,

Then the determinant of [A] is _________.


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 12
For a square matrix, AX = λX

From the observations,

⇒ λ1 = 6 and

⇒ λ2 = 1 and

By property of Eigen value,

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 13

The real part of is ___.(Answer up to the nearest integer)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 13

Real part =

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 14

In the circuit shown V0 = VOA for switch SW in position A and V0 = VOB for SW in position B. Assume that the OPAMP is ideal, the value of is ________


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 14

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 15

The forward-path transfer function of a ufb system is .

For the system to be stable, the range of K is

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 15
Closed loop transfer function.

The system can only marginally stable.

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 16

A certain alternator has the following data: speed rated, Phase resistance negligible. Under short circuit, field current needed for rated armature current = 1A. Slope of the linear region of the OCC = 100V per field amp. Full load leakage reactance drop = 25V .

The field current equivalent of armature mmf is ___________ A.


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 16
The problem is related to the potier triangle. Consider the figure shown below

Let AB=1 A of field current. Corresponding to this current the open circuit voltage is 100 V. Draw BC perpendicular to AB of value 100 V. Then AC gives the linear part of occ. On the line AC locate the point D such thatDF= leakage reactance drop =25 V

By similar triangle property in triangles ABC and

AF = (1/4) AB = 1/4 of field current and supplies the leakage reactance drop.

Field current equivalent of armature reaction mmf = FB = 1-1/4 = 0.75A.

Hence, the field current equivalent of armature mmf is 0.75 A.

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 17

Consider the given circuit and waveform for the input voltage. The diode in circuit has cutting voltage Vc = 0.

The waveform of output voltage vo is

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 17
During positive cycle when vi < 8 V, both diode are OFF vo = vi. For vi > 8 V,

vo = 8 V, D1 is ON. During negative cycle when |vi| < 6 V, both diode are OFF,

Vo = vi. For |vi | > 6 V, D2 is on vo = -6 V.

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 18

Consider circuit shown in below figure.

The duration of conduction of Auxiliary Thyristor (TA) is _______ μs .


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 18
Given : Vs = 100 V, C = 1 pF , L = 10 , Io = 1 A ,

Let, the duration of conduction be tc,

Then it must satisfy where

Therefore,

Hence, the duration of conduction of Auxiliary Thyristor (TA) is 0.314 μs.

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 19

In the following circuit, flip flop is cleared initially. If input clock frequency is fi, the frequency at output will be

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 19
Here T is,

So, output will toggle at each clock pulse.

The output sequence is 010101010…..

Frequency of output is fi/2

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 20

A material has a conductivity of 10-2 mho/m and a relative permittivity of 10. The frequency at which the conduction current in the medium, is equal to the displacement current is ______. (Answer should be in MHz)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 20
Given :σ = 102 mho/m

εr = 10

Now, magnitude of displacement current density for sinusoidal fields is given as,

And magnitude of conduction current density,

As per given data, equation (i) = (ii),

But

f = 18 x 106 Hz = 18MHz

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 21

A single-phase half controlled converter shown in the figure is feeding power to highly inductive load. The converter is operating at a firing angle of 60o.

If the firing pulses are suddenly removed, the steady state voltage (V0) waveform of the converter will become

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 21

Here, the inductor makes T1 and T3 in 'ON' because current passing through T1 and T3 is more than the holding current.

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 22

For the ideal Op-Amp circuit shown in figure below, the maximum phase shift of output voltage Vo (in degree’s) is (Assume C-R network provide maximum phase shift of 60 degree)

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 22
Given circuit is as shown below

KCL at node

Vo’ = -Ii x R

Vo’ has 土1800 phase shift and the RC network provides 60o phase shift.

∴ Phase shift of V0 = 1800 + 600 = 2400

∴ Phase shift of V0 = (-1800) + 600 = -1200

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 23

In the following chopper, the duty ratio of switch S is 0.4. If the inductor and capacitor are sufficiently large to ensure continuous inductor current and ripple-free capacitor voltage, the charging current (in ampere) of the 5 V battery, under steady-state, is: (Answer up to the nearest integer)


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 23
Given DC-DC converter is a Buck converter with a duty cycle ratio δ = 0.4

Since the connected load is the battery the output current is given as

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 24

Consider the given integral, Then I equals

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 24
Given

As

By inverse Fourier transform

Definition of

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 25

In which category do the errors introduced by an instrument fall?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 25
Systematic errors may be instrumental error, environmental error or observational errors. Blunders are final source of errors and these errors are caused by faulty recording or due to a wrong value while recording a measurement, or misreading a scale or forgetting a digit while reading a scale.
GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 26

Consider 3x8 decoder circuit as shown in below figure,

The above configuration indicates,

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 26
Given

From the above figure,

Truth table for above circuit is,

K-map of function F1 in SOP form is, K-map of function F2 in SOP form is,

Output F1 is the sum of full adder and F2 is the carry of full adder.

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 27

In the following RC circuit, the value of Vc (0) = 10 V. The value of Vc (t) is

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 27

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 28

The MOD value of counter shown in below circuit is __________.


Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 28
Given

From the above figure,

The number of different state is 8.

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 29

In a core-type single-phase transformer, the steel-core is assembled by staggering butt-joints in adjacent layers of laminations vide figures. The purpose served is said to be:

1. Avoiding continuous air-gap

2. Preventing loss of mechanical strength

3. Reducing eddy-current loss

Which of the above statements are true?

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 29
The staggering of butt joints avoid continuous air gap as the flux can take path from neighbouring layer at the joints.

At the same time, staggering maintains mechanical strength of the core.

Air gap also avoid magnetic saturation of the core. Staggering of butt joints does not affect eddy currents. Eddy currents are reduced by laminations.

GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 30

Determine the counting sequence of the following counter

Detailed Solution for GATE Mock Test: Electrical Engineering (EE)- 8 (01-02-23) - Question 30
Given

From above circuit,

Similarly,

Truth Table :

In the above diagram, both preset and clear input is given. Therefore, from the above truth table, counter will stuck in state 100.

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