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Test: Frequency Response


20 Questions MCQ Test GATE Electrical Engineering (EE) 2023 Mock Test Series | Test: Frequency Response


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Attempt Test: Frequency Response | 20 questions in 60 minutes | Mock test for Railways preparation | Free important questions MCQ to study GATE Electrical Engineering (EE) 2023 Mock Test Series for Railways Exam | Download free PDF with solutions
QUESTION: 1

A parallel resonant circuit has a resistance of 2 kΩ and half power frequencies of 86 kHz and 90 kHz.1. The value of capacitor is

Solution:

BW = ω2 - ω1 = 2π(90 - 86)k = 8π krad/s
  
 = 19.89 nF

QUESTION: 2

A parallel resonant circuit has a resistance of 2 kΩ and half power frequencies of 86 kHz and 90 kHz.The value of inductor is

Solution:

 

 = 0.16 mH

QUESTION: 3

A parallel resonant circuit has a resistance of 2 kΩ and half power frequencies of 86 kHz and 90 kHz.The quality factor is

Solution:

QUESTION: 4

A parallel resonant circuit has a midband admittance of 25 x 10-3 S, quality factor of 80 and a resonant frequency of 200 krad/s.The value of R is
Solution:

Ay mid-band frequency Z = R, Y = 1/R

QUESTION: 5

A parallel resonant circuit has a midband admittance of 25 x 10-3 S, quality factor of 80 and a resonant frequency of 200 krad/s.The value of C is
Solution:


 = 10 μF

QUESTION: 6

A parallel RLC circuit has R =1 kΩ and C = 1 μF. Thequality factor at resonance is 200. The value of inductor is
Solution:

 
⇒ L = 25 μH

QUESTION: 7

A parallel circuit has R =1 k , C = 50 μF and L = 10mH. The quality factor at resonance is
Solution:

QUESTION: 8

A series resonant circuit has an inductor L = 10 mH.The resonant frequency ωo = 106 rad/s and bandwidth is BW = 103 rad/s. The value of R and C will be
Solution:


 = 100pF

QUESTION: 9

A series resonant circuit has L = 1 mH and C = 10μF. The required R for the BW 15 9 . Hz is
Solution:

⇒ 

QUESTION: 10

For the RLC parallel resonant circuit when R = 8 kΩ , L = 40 mH and C = 0.25 μF, the quality factor Q is
Solution:

QUESTION: 11

The maximum voltage across capacitor would be
Solution:

Thevenin equivalent seen by L - C combination


Open Circuit : v1 = 0, v∝ = 3V


 

QUESTION: 12

For the circuit shown in fig. resonant frequency fo is
Solution:

Applying 1 A at input port V1 = 10 V
voltage across 1 A source

Zin = Vtest
At resonance Im {Zin} = 0
⇒ ⇒

QUESTION: 13

For the circuit shown in fig. the resonant frequency fo is 
Solution:



At resonance Im {Y} = 0


QUESTION: 14

The network function of circuit shown in fig. is
Solution:





QUESTION: 15

Solution:

QUESTION: 16

Solution:

QUESTION: 17

The value of input frequency is required to cause again equal to 1.5. The value is
Solution:

For any value of ω, R,C gain ≤ 1.
Thus (D) is correct option.

QUESTION: 18

In the circuit of fig. phase shift equal to -450 is required at frequency ω =20 rad/s . The value of R is
Solution:


phase shift = - tan-1 ωCR = -450°
ωCR = 1,

20 x 1 x 10-6 R = 1 ⇒ R = 50KΩ

QUESTION: 19

For the circuit of fig., Vs is the source voltage and the response is the resistance voltage Vo, R = 30Ω and L = 2H. Suppose the input frequency is adjusted until the gain is equal to 0.6. The value of the frequency is
Solution:



QUESTION: 20

Bode diagram of the network function Vo /Vs for the circuit of fig.  is
Solution:


-20 dB/decade line starting from ω = 5.56 rad/s
20 dB/decade line starting from ω = 16.67 rad/s
Hence -20 dB/decade line for 5.56 < ω < 16.67 parallel to ω axis to ω >16.67 

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