Test: Polar Plot - 2 - Electrical Engineering (EE) MCQ

# Test: Polar Plot - 2 - Electrical Engineering (EE) MCQ

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## 10 Questions MCQ Test GATE Electrical Engineering (EE) Mock Test Series 2025 - Test: Polar Plot - 2

Test: Polar Plot - 2 for Electrical Engineering (EE) 2024 is part of GATE Electrical Engineering (EE) Mock Test Series 2025 preparation. The Test: Polar Plot - 2 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Polar Plot - 2 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Polar Plot - 2 below.
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Test: Polar Plot - 2 - Question 1

### The polar plot of a transfer function passes through the critical point (-1,0). Gain margin is

Detailed Solution for Test: Polar Plot - 2 - Question 1

Explanation: Gain margin of a polar plot passing through the critical point is zero.

Test: Polar Plot - 2 - Question 2

### The polar plot of the open loop transfer function of a feedback control system intersects the real axis at -2. The gain margin of the system is

Detailed Solution for Test: Polar Plot - 2 - Question 2

The gain margin is found by taking the reciprocal of the magnitude of the open-loop transfer function at the phase crossover frequency. If the polar plot intersects the real axis at −2, this means that the magnitude of the open-loop transfer function is 2 at the phase crossover frequency.

Test: Polar Plot - 2 - Question 3

### The constant M circle for M = 1 is the

Detailed Solution for Test: Polar Plot - 2 - Question 3

For M = 1 the constant M circle is a straight line at x = -1/2.

Test: Polar Plot - 2 - Question 4

The polar plot of a transfer function passes through the critical point (-1,0). Gain margin is

Detailed Solution for Test: Polar Plot - 2 - Question 4

Gain margin of a polar plot passing through the critical point is zero.

Test: Polar Plot - 2 - Question 5

If the gain of the open-loop system is doubled, the gain margin

Detailed Solution for Test: Polar Plot - 2 - Question 5

Gain margin is nothing but the inverse of the gain. Hence if gain of open loop system is doubled, then the gain margin will becomes half.

Test: Polar Plot - 2 - Question 6

The unit circle of the Nyquist plot transforms into 0dB line of the amplitude plot of the Bode diagram at

Detailed Solution for Test: Polar Plot - 2 - Question 6

The unit circle of the Nyquist plot transforms into 0dB line of the amplitude plot of the Bode diagram at any frequency.

Test: Polar Plot - 2 - Question 7

If a system has an open loop transfer function 1-s / 1+s, then the gain of the system at frequency of 1 rad/s will be

Detailed Solution for Test: Polar Plot - 2 - Question 7

The system is all pass system and the gain of the system at frequency of 1 rad/sec.

Test: Polar Plot - 2 - Question 8

The gain margin for the system with open loop transfer function G(s) H(s) = G(s) = 2(1 + s) / s2 is

Detailed Solution for Test: Polar Plot - 2 - Question 8

Gain margin of a system is calculated at the phase cross over frequency and expressed in decibels.

Test: Polar Plot - 2 - Question 9

The open loop transfer function of a system is G(s) H(s) = K / (1 + s)(1 + 2s)(1 + 3s)
The phase cross over frequency ωc is

Detailed Solution for Test: Polar Plot - 2 - Question 9

Phase crossover frequency is calculated as by calculating the magnitude of the transfer function and equating it to 1 and the frequency calculated at this magnitude is phase cross over frequency.

Test: Polar Plot - 2 - Question 10

The gain margin (in dB) of a system having the loop transfer function G(s) H(s) = 2 / s(s + 1) is

Detailed Solution for Test: Polar Plot - 2 - Question 10

Gain margin of a system is calculated at the phase cross-over frequency and expressed in decibels.

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