Test: Power Electronics- 4
10 Questions MCQ Test GATE Electrical Engineering (EE) 2023 Mock Test Series | Test: Power Electronics- 4
Which of the following are the advantages of freewheeling of load current in phase – controlled converters?
1. It reduces the reactive power demand of the converter
2. It improves the displacement factor
3. It reduces the generated ripple voltage on the DC side of an SCR phase controlled converter
4. It improves the input PF.
Select the correct answer using the codes given below
Advantage of freewheeling diode
1. It prevents the output voltage from becoming negative
2. System efficiency is improved because energy stored in L is transferred to load R through FD.
3. Load current waveform is more smooth.
4. It reduces the reactive power demand of the converter.
5. It improves the displacement factor.
6. It improves distortion factor.
7. It improves the input PF.
A battery is charged by a single phase half wave diode rectifier. The supply voltage is 220 V (rms), 50 Hz and the battery emf is constant at 80 V. then PIV rating of the diode should be___ (in V)
PIV = Vm + E = 220√2 + 80 = 3 91.13 V
A single phase full – wave half controlled bridge converter feeds an inductive load. The two SCRs in the converter are connected to a common DC bus. The converter has to have a freewheeling diode.
Single phase full wave half controlled bridge converter feeds an Inductive load. The two SCRs in the converter are connected to a common dc bus. The converter has to have freewheeling diode because the converter does not provide for freewheeling for high value of triggering angles
If the commutation angle of a diode rectifier (due to source inductive effect) is μ, then the inductive voltage regulation will be
Voltage regulation = 
for single phase full converter bridge
due to source inductance effect
Where μ is overlapping angle and α is firing angle
for α = 0, V0 = 
and
Voltage regulation
A single phase controlled rectifier bridge consists of one SCR and three diode as shown in figure find the waveform of current through T1.
1 ϕ full bridge converter with freewheeling diode feeds an inductive load. Load resistance is 15 Ω and it has a large inductance providing constant and ripple free dc current input to converter from ideal 220 V, 50 Hz single phase source. For a firing angle of 30°, the value of output current is _________A.
the average output voltage for single phase with a freewheeling diode
The average output current 
A single phase full converter is connected to an AC supply of 300 sin 314 t V. It operates at firing angle α = 30° the load current maintained constant at 5A and the load voltage 120 V. Calculate source inductance (in mH).
120 × 3.14 = 600 cos 30° - 3140 Ls
376.8 = 519.61 – 3140 Ls
-142.82 = -3140 Ls
Ls = 45.48 mH
A single-phase full bridge diode rectifier is supplied from 220 V, 50 Hz source the load consist of R = 15 Ω and a large Inductance so as to render the load current constant determine RMS value of diode current and supply P.F.
Average value of output voltage
Average value of output current 
R.M.S value of diode current 
Load power = VoIo = 198.17 × 13.21 = 2617.83 W
Input power = VsIs cos ϕ
220 × 13.21 cos ϕ = 2617.83
cos ϕ = 0.9
A single phase semiconductor, connected to 220 V 50 Hz Is feeding load R = 15 Ω in series with a large inductance that makes the load current ripple free for firing angle of 60°, calculate the Rectification efficiency ______ in %.
Concept
R.M.S value of output voltage is
Calculation
The load current is Ripple free
∴ Ior = 197.32/15 = 13.15 A
Pdc = VoIo = 148.63 × 9.91 = 1472.93 W
Pac = VorIor = 197.32 × 13.15 = 2595.46 W
Rectification efficiency = 
Find out the ratio of the thyristor to diode RMS current rating in the signal phase half controlled converter for firing angle α = 30°. Assume ripple free contains conduction.
Conduction diagram
From the conduction diagram the thyrsistor conduct for (π – α) radian while the diodes conducts for (π + α) radians. Since the load current is constant.
= 0.845
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