Test: Power Systems- 1 - Electrical Engineering (EE) MCQ

# Test: Power Systems- 1 - Electrical Engineering (EE) MCQ

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## 10 Questions MCQ Test - Test: Power Systems- 1

Test: Power Systems- 1 for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Test: Power Systems- 1 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Power Systems- 1 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Power Systems- 1 below.
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Test: Power Systems- 1 - Question 1

### For a 50 Hz 300 km long transmission line VS = 145∠4.9° kV, IS = 0.164∠-36.9° kA. What is the sending end power?

Detailed Solution for Test: Power Systems- 1 - Question 1

Sending end power factor = cos(4.9deg  + 36.9 deg)

= cos (41.8 deg) = 0.745 lagging

Vs = 145√3

Sending end power = √(Vs x Ix cosΦ)= √3 x 145√3 x 0.164 x 0.745 = 53.2 MW.

Test: Power Systems- 1 - Question 2

### The ABCD constants of a 3-phase transmission line are A = D = 0.8 ∠1° B = 170 ∠85° Ω C = 0.002 ∠90.4° mho The sending end voltage is 400 kV. The receiving end voltage under no-load condition is

Detailed Solution for Test: Power Systems- 1 - Question 2

At no -load Vs = AVr as Ir = 0

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Test: Power Systems- 1 - Question 3

### If a 250 MVA, 11/400 kV three-phase power transformer has leakage reactance of 0.05 per unit on the base of 250 MVA and the primary voltage of 11kV, then the actual leakage reactance of the transformer referred to the secondary side of 400 kV is

Detailed Solution for Test: Power Systems- 1 - Question 3

Z1(actual) = Zpu . Zbase

Test: Power Systems- 1 - Question 4

The surge impedance of a 3-phase, 400 kV transmission line is 400 Ω. The surge impedance loading (SIL) is

Detailed Solution for Test: Power Systems- 1 - Question 4

Test: Power Systems- 1 - Question 5

The 50 Hz generating units operate in parallel with in the same power plant and have the following ratings:
Unit 1: 500 MVA, 0.85 power factor, 20 kV, 3000 rpm,
H1 = 5 MJ/MVA

Unit 2: 200 MVA, 0.9 power factor, 20 kV, 1500 rpm,
H2 = 5 MJ/MVA.

The equivalent inertia constant H in MJ/MVA on 100 MVA base is

Detailed Solution for Test: Power Systems- 1 - Question 5

SHe = S1 H1 + S2 H2

= 500 × 5 + 200 × 5 = 3500

∴ He (100 MVA base  = 3500/100
= 35.0 MJ/MVA

Test: Power Systems- 1 - Question 6

If a travelling-wave travelling along a loss-free overhead line does not result in any reflection after it has reached the far end, then the far end of the line is

Detailed Solution for Test: Power Systems- 1 - Question 6

That’s why line terminated into a resistance equal to surge impedance of the line is called as infinite line.

Test: Power Systems- 1 - Question 7

The active and the reactive power delivered at the receiving end of a short transmission line of impedance Z∠Ψ are respectively given by

VS and VR being the magnitude of voltage at the sending and receiving ends, δ is the power-angle. At the power-limit condition i.e., for maximum PR

Detailed Solution for Test: Power Systems- 1 - Question 7

At maximum PR , Ψ = δ and corresponding

QR is given By QR

Test: Power Systems- 1 - Question 8

If a 500 MVA, 11 kV three-phase generator at 50 Hz feeds, through a transfer impedance of (0.0 + J 0.605) Ω per phase, an infinite bus also at 11 kV; then the maximum steady state power transfer on the base of 500 MVA and 11 kV is

Detailed Solution for Test: Power Systems- 1 - Question 8

Test: Power Systems- 1 - Question 9

In a three unit insulator string, voltage across the lowest unit is 17.5 kV and string efficiency is 84.28%. The total voltage across the string will be equal to

Detailed Solution for Test: Power Systems- 1 - Question 9

Total voltage across the string

= 0.8428 × 17.5 × 3 = 44.25 kV

Test: Power Systems- 1 - Question 10

Bundled conductors are used for EHV transmission lines primarily for reducing the

Detailed Solution for Test: Power Systems- 1 - Question 10

The bundle acts as far as the electric field is concerned, like a conductor of diameter much larger than that of the component conductors. This reduces the voltage gradient. In other words a higher voltage can be used for permissible levels of Radio interference.

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