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If the arithmetic mean of two numbers is 10 and their geometric mean is 8, the numbers are
Let the numbers be a and b Then
Solving a + b = 20 and a  b = 12 we get a = 16 and b = 4.
The median of
0, 2, 2, 2, 3, 5, 1, 5, 5, 3, 6, 6, 5, 6 is
Observations in ascending order are 3, 3, 1, 0, 2, 2, 2, 5, 5, 5, 5 6, 6, 6
Number of observations is 14, which is even.
Consider the following table
The median of the above frequency distribution is
The given Table may be presented as
The mode of the following frequency distribution, is
Maximum frequency is 23. So, modal class is 12–15.
The meandeviation of the data 3, 5, 6, 7, 8, 10, 11, 14 is
The mean deviation of the following distribution is
The standard deviation for the data 7, 9, 11, 13, 15 is
The probability that an event A occurs in one trial of an experiment is 0.4. Three independent trials of experiment are performed. The probability that A occurs at least once is
Here p = 0.4, q = 0.6 and n = 3.
Eight coins are tossed simultaneously. The probability of getting at least 6 heads is
p = 1/2, q = 1/2, n = 8. Required probability = P (6 heads or 7 heads or 8 heads)
The ranks obtained by 10 students in Mathematics and Physics in a class test are as follows
The coefficient of correlation between their ranks is
D_{i} = 2, 8, 2, 3, 3, 3, 3, 0, 2, 4.
If ∑x_{i} = 24, ∑y_{i} = 44, ∑x_{i}y_{i} = 306, ∑x_{i}^{2} =164 ,∑y_{i}^{2} = 574 and n = 4 then the regression coefficient b_{xy } is equal to
If ∑x_{i} = 30, ∑y_{i} = 42, ∑x_{i}y_{i} = 199 , ∑x_{i}^{2} =184 ,∑y_{i}^{2} = 318 and n = 6 then the regression coefficient b_{xy } is equal to
Let r be the correlation coefficient between x and y and b_{xy} ,b_{yx} be the regression coefficients of y on x and x on y respectively then
If b_{yx }= 1.6 and b_{xy} = 0.4 and θ is the angle between two regression lines, then tan θ is equal to
The equations of the two lines of regression are : 4x + 3y + 7 = 0 and 3x + 4y + 8 = 0. The correlation coefficient between x and y is
If cov(X, Y) = 10, var (X) = 6.25 and var(Y) = 31.36, then ρ(X,Y) is
If ∑x = ∑y = 15, ∑x^{2} = ∑y^{2} = 49, ∑xy = 44 and n = 5, then b_{xy} = ?
If ∑x = 125, ∑y = 100 , ∑x^{2} = 1650, ∑y^{2} = 1500 , ∑xy = 50 and n = 25, then the line of regression of x on y is
22 docs274 tests

22 docs274 tests
