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Test: Method of Analysis - Electrical Engineering (EE) MCQ


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15 Questions MCQ Test GATE Electrical Engineering (EE) Mock Test Series 2025 - Test: Method of Analysis

Test: Method of Analysis for Electrical Engineering (EE) 2024 is part of GATE Electrical Engineering (EE) Mock Test Series 2025 preparation. The Test: Method of Analysis questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Method of Analysis MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Method of Analysis below.
Solutions of Test: Method of Analysis questions in English are available as part of our GATE Electrical Engineering (EE) Mock Test Series 2025 for Electrical Engineering (EE) & Test: Method of Analysis solutions in Hindi for GATE Electrical Engineering (EE) Mock Test Series 2025 course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt Test: Method of Analysis | 15 questions in 45 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study GATE Electrical Engineering (EE) Mock Test Series 2025 for Electrical Engineering (EE) Exam | Download free PDF with solutions
Test: Method of Analysis - Question 1

v1 = ?

Detailed Solution for Test: Method of Analysis - Question 1

Applying the nodal analysis

Test: Method of Analysis - Question 2

va = ?

Detailed Solution for Test: Method of Analysis - Question 2

v= 2(3+1) + 3(1) =11V

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Test: Method of Analysis - Question 3

v1 = ?

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Test: Method of Analysis - Question 4

va = ?

Detailed Solution for Test: Method of Analysis - Question 4

Test: Method of Analysis - Question 5

v2 = ?

Detailed Solution for Test: Method of Analysis - Question 5

Test: Method of Analysis - Question 6

ib = ?

Detailed Solution for Test: Method of Analysis - Question 6

Test: Method of Analysis - Question 7

i1 = ?

Detailed Solution for Test: Method of Analysis - Question 7

sing Thevenin equivalent and source transform

Test: Method of Analysis - Question 8

i1 = ?

Detailed Solution for Test: Method of Analysis - Question 8

75 = 90ki1+ 10k(i1 - 7.5m)

150 = 100ki1 = i1 = 1.5 mA

Test: Method of Analysis - Question 9

i1 = ?

Detailed Solution for Test: Method of Analysis - Question 9

3 = 2i1 + 3(i1 - 4) 

i1 = 3 A

Test: Method of Analysis - Question 10

i1 = ?

Detailed Solution for Test: Method of Analysis - Question 10

45 = 2ki1 + 500(i1 + 15m)

= i1 = 15 mA

Test: Method of Analysis - Question 11

i1 = ?

Detailed Solution for Test: Method of Analysis - Question 11

6.6 = 50i1 + 100(i1 + 0.1) + 40(i1 - 0.06) + 60(i1 - 0.1) i1 = 0.02 A

Test: Method of Analysis - Question 12

For the circuit of Fig. the value of vs , that will result in v1 = 0, is

Detailed Solution for Test: Method of Analysis - Question 12

If v1 = 0, the dependent source is a short circuit
 

Test: Method of Analysis - Question 13

i1 , i2 = ?

Detailed Solution for Test: Method of Analysis - Question 13

ix = i1 - i2
15 = 4i1 -2(i1 - i2) + 6(i1 - i2)
⇒ 8i1 - 4i2 = 15   ..........(i)
-18 = 2i2 + 6(i2 -i1)
⇒ 3i1 -4i2 = 9    ..........(ii)
i1 =1.2 A, i2 = -1.35 A 

Test: Method of Analysis - Question 14

v1 = ?

Detailed Solution for Test: Method of Analysis - Question 14

14 = 3i1 + vy + 6 (i1 - 2 - 7) + 2vy + 2(i1 -7)
vy = 3(i1 - 2)
14 = 3i1 +9(i1 - 2)+ 6(i1 - 9)+2(i1 -7)
14 = 20i1 -18 - 54 - 14 ⇒ i1 = 5 A
v1 = 6(5 - 2 - 7) + 2 x 3(5 - 2)+2(5 - 7) = -10 V 

Test: Method of Analysis - Question 15

vx = ?

Detailed Solution for Test: Method of Analysis - Question 15

Let i1 and i2 be two loop current

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