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Test: Quantitative Aptitude- 2 - GMAT MCQ


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21 Questions MCQ Test Quantitative for GMAT - Test: Quantitative Aptitude- 2

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Test: Quantitative Aptitude- 2 - Question 1

In the “Big-Reds” parking lot there are 56 vehicles, 18 of them are buses and the rest are private cars. The color of 32 vehicles is red, from which 17 are buses. How many private cars can be found in the parking lot, which are not colored red?

Detailed Solution for Test: Quantitative Aptitude- 2 - Question 1

The best answer is B.

Out of 56 vehicles, 32 are colored red, therefore 24 are in different color.

17 of the red vehicles are buses, therefore (18 – 17 = 1) are in different color.

(24 – 1 = 23) private cars are in the parking lot with a different color than red.

Test: Quantitative Aptitude- 2 - Question 2

In Sam’s hanger there are 23 boxes, 16 out of the boxes are filled with toys and the rest are filled with electrical appliances. 8 boxes are for sale, 5 of them are filled with toys.  How many boxes with electrical appliances are in Sam’s hanger that are not for sale?

Detailed Solution for Test: Quantitative Aptitude- 2 - Question 2

The best answer is D.

8 boxes are for sale, 5 of them are with toys, and therefore 3 of them are with electrical appliances.
Out of 23 boxes, 16 are with toys, therefore, and therefore 7 of them are with electrical appliances.
(7 – 3 = 4) is the number of electrical appliances boxes, which are not for sale.

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Test: Quantitative Aptitude- 2 - Question 3

In the fifth grade at Parkway elementary school there are 420 students. 312 students are boys and 250 students are playing soccer. 86% of the students that play soccer are obviously boys. How many girl student are in Parkway that are not playing soccer?

Detailed Solution for Test: Quantitative Aptitude- 2 - Question 3

The best answer is B.

There are (420 – 312 = 108) girls in Parkway.
86% of 250 are boys, therefore 14% of 250 are girls that play soccer, which is 35 girls.
The number of girls that do not play soccer is (108 – 35 = 73).

Test: Quantitative Aptitude- 2 - Question 4

In the quiet town of “Nothintodo” there are 600 inhabitants, 400 are unemployed and 300 are somnambulists. If half of the somnambulists are unemployed, how many are employed and are not somnambulists?

Detailed Solution for Test: Quantitative Aptitude- 2 - Question 4

​The best answer is A.
There are 300 people that are not somnambulists. There are (600 – 400 = 200) people that are employed in the  town, half of the somnambulists are employed (150), therefore (200 – 150 = 50) is the number of people that are employed which are also not somnambulists.

Test: Quantitative Aptitude- 2 - Question 5

In the youth summer village there are 150 people, 75 of them are not working, 50 of them have families and 100 of them like to sing in the shower. What is the largest possible number of people in the village, which are working, that doesn’t have families and that are singing in the shower?

Detailed Solution for Test: Quantitative Aptitude- 2 - Question 5

The best answer is C.
The number of people that work is 75.The number of people that doesn’t have families is (150 – 50 =100).

100 of the people like to sing in the shower.
The largest possible number of people that belong to all three groups is the smallest among them, Meaning 75.

Test: Quantitative Aptitude- 2 - Question 6

In the junior basketball league there are 18 teams, 2/3 of them are bad and ½ are rich. What can’t be the number of teams that are rich and bad?

Detailed Solution for Test: Quantitative Aptitude- 2 - Question 6

(2/3 x 18 = 12) teams are bad and 9 are rich.
The number of teams which are rich and that are bad must be between 9 and  (9+12-18 = 3).
The only answer, which is not in that range, is C.

Test: Quantitative Aptitude- 2 - Question 7

In the third grade of Windblow School there are 108 students, one third of them failed the math test and 1/6 failed that literature test. At least how many students failed both tests?

Detailed Solution for Test: Quantitative Aptitude- 2 - Question 7

The best answer is A.
(1/3 x 108 = 36) failed the math test.
(1/6 x 108 = 18) failed that literature test.
The least amount of people that failed both tests is (18 + 36 –108 = -54), there cant be an negative Overlapping between the groups so the least amount of people who failed both tests is zero.

Test: Quantitative Aptitude- 2 - Question 8

If  1/X = 2.5, then what is the value of  1/(X – 2/3)?

Detailed Solution for Test: Quantitative Aptitude- 2 - Question 8

The best answer is C.
If 1/X is 2.5 or 5/2 then X = 2/5.
1/(2/5 – 2/3) is 1/(6/15 – 10/15) = -15/4 = -3.75.

Test: Quantitative Aptitude- 2 - Question 9

Travis is working as a programmer of IBW. Travis earns $3,500 annually.
If Travis pays 2.5% of that amount quarterly to support groups and he paid $525 so far, for how many years now has Travis been paying?

Detailed Solution for Test: Quantitative Aptitude- 2 - Question 9

Travis pays 2.5% of 3500, which is $87.5 every 3 months (quarterly).
(525/87.5 = 6), therefore Travis has been paying for (6 x 3 = 18) months now, that is 2.5 years.

Test: Quantitative Aptitude- 2 - Question 10

Dana borrows 5500 pounds annually for her college education. If Dana gives her parents 3% of that amount back each month, how much will she still owe her parents after four years of college?

Detailed Solution for Test: Quantitative Aptitude- 2 - Question 10

Dana takes 5500 each year and returns (0.03 x 5500 = 165) each month, which is (165 x 12 = 1980) each passing year. That means that each year Dana owes her parents (5500 – 1980 = 3520) pounds.
After 4 years in college she will owe them (4 x 3520 = 14,080) pounds.

Test: Quantitative Aptitude- 2 - Question 11

Mr. Rusty owes the bank $1,040,000, he returns $40,000 quarterly to the bank. If the tax on the money Rusty owes is compounded quarterly by 0.25% starting before Rusty paid the first payment, how months would it take poor Rusty to reach a point where he owes the bank no more than 1 million dollars?

Detailed Solution for Test: Quantitative Aptitude- 2 - Question 11

The best answer is B.

Every three months Rusty gives the bank $40,000.
After the first quarter the bank took (0.0025 x 1040000 = 2600) and Rusty paid $40,000 so the new Debt is now (1,040,000 - 40,000 + 2,600 = 1,002,600).
After the second quarter the bank took (0.0025 x 1002600 =  2506.5) and Rusty paid again $40,000 so the new Debt is now (1,002,600 – 40,000 + 2506.5 < 1 million dollars).

Test: Quantitative Aptitude- 2 - Question 12

Simba borrowed $12,000 from his brothers so he can buy a new sports car. If Simba returns 4.5% of that amount every 2 weeks, after how many months Simba wouldn’t owe his brothers any more money?

Detailed Solution for Test: Quantitative Aptitude- 2 - Question 12

The best answer is B.
Simba gives (0.045 x 12,000 = 540) to his brothers every 2 weeks, in a month he gives (540 x 2 = 1080). (12,000/1,080 is a little over 11), therefore after 12 months he won’t owe any more money.

 

Test: Quantitative Aptitude- 2 - Question 13

If A and B are two roots of the equation X2 –6.5X – 17, then what is the value of A x B?

Detailed Solution for Test: Quantitative Aptitude- 2 - Question 13

The best answer is D.
The roots of the equation are 8.5 and (-2).
The multiplication of the roots is equal to (-17).

Test: Quantitative Aptitude- 2 - Question 14

If A,B and C are roots of the equation  X3 – 16X2 +48X, what is the sum of the roots?

Detailed Solution for Test: Quantitative Aptitude- 2 - Question 14

The best answer is A.
The equation can be written as: X(X2 – 16X +48) = X(X – 12)(X – 4).
The roots of the equation are: 0,4 and 12. The sum of the roots is 16.

Test: Quantitative Aptitude- 2 - Question 15

If R is a root of the equation X2 +3X – 54, than which of the following equations have also the root R ?

Detailed Solution for Test: Quantitative Aptitude- 2 - Question 15

The best answer is D.
The original equation is X2 + 3X – 54, it can be written as (X – 6)(X + 9). The roots are 6 and (-9).
We are looking for an equation that has one of the same roots.
Answer D: X2 – 15X +54 = (X – 6)(X – 9) à This equation has the root 6.
All the other answers have different roots than the original equation

Test: Quantitative Aptitude- 2 - Question 16

If  P  is a root of the equation X3 +10X2 + 16X, than which of the following equations have also the root P ?

Detailed Solution for Test: Quantitative Aptitude- 2 - Question 16

The best answer is B.
The original equation is X3 +10X2 + 16X, it can be written as X(X + 8)(X + 2). The roots are (-8),0 and (-2).

We are looking for an equation that has one of the same roots.

Answer B: X + 8 à This equation has the root (-8).

All the other answers have different roots than the original equation.

Test: Quantitative Aptitude- 2 - Question 17

If X is a root of the equation a3 +8a2 – 20a, than which of the following equations Don’t have the root X as one of their roots?

Detailed Solution for Test: Quantitative Aptitude- 2 - Question 17

The best answer is E.

The original equation is a3 +8a2 – 20a, it can be written as a(a – 2)(X + 10). The roots are 2,0 and (-10).
We are looking for an equation that has none of the same roots.
Answer E: X2 – 10X +16 = (X + 2)(X + 8) à This equation has none of the original roots. All the other answers have one or more of the same original roots.

Test: Quantitative Aptitude- 2 - Question 18

Robin earns 30% more than Erica. Charles earns 60% more than Erica. How much % is the wages earned by Charles more than that earned by Robin?

Detailed Solution for Test: Quantitative Aptitude- 2 - Question 18

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Test: Quantitative Aptitude- 2 - Question 19

Marla is 20 years older than Angelina. In 5 years, Marla will be 3 times as old as Angelina. What will Marla’s age be in 3 years?

Detailed Solution for Test: Quantitative Aptitude- 2 - Question 19

First, let’s define our two variables:

M = Marla’s age today

A = Angelina’s age today

Next, we can write two equations from the information presented in the problem stem.

Since Marla is 20 years older than Angelina, we have:

M = A + 20 (equation 1)

Since in 5 years, Marla will be 3 times as old as Angelina, we have:

M + 5 = 3(A + 5)

M + 5 = 3A + 15

M = 3A + 10 (equation 2)

Next, from equation 1, we can substitute A + 20 for M in equation 2, and then solve for A:

A + 20 = 3A + 10

10 = 2A

5 = A

Finally, we see that Angelina is 5 years old. Thus, Marla is currently 5 + 20 = 25 years old. So, in 3 years, Marla will be 28 years old.

Test: Quantitative Aptitude- 2 - Question 20

Paul walks from home to work at a rate of 5 mph and bikes home from work along the same route at 12 mph. What is his average speed for the round trip?

Detailed Solution for Test: Quantitative Aptitude- 2 - Question 20

Since we have an average rate question we can use the following formula:

average rate = total distance / total time

Since the distance is the same in both directions, we can use a smart number to represent the one-way distance. A good number to use would be one that is divisible by both 5 and 12, so we can let the distance each way = 60.

So, the time going to work is 60/5 = 12, and the time going home from work is 60/12 = 5.

Finally we can determine the average rate:

average rate = total distance / total time

average rate = (60 + 60)/(12 + 5)

average rate = 120/17

Test: Quantitative Aptitude- 2 - Question 21

(x, y) are the coordinates of the intersection of the following lines:
(3x – 2y = 8) and (3y + x = 10). What is the value of (x/y)?

Detailed Solution for Test: Quantitative Aptitude- 2 - Question 21

The best answer is B.

There is no need to draw the lines. There are two equations with two variable that you have to solve.
Take the second equation and multiply it by (-3) to get: -9y –3x = -30 add this equation to the first and You’ll get: -11y = -22 à y=2 and x=4. (x/y) is 2

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