Which of the following is correct some θ such that 0° ≤ θ < 90°
The sides of a right angled triangle form a geometric progression, find the cosines of the acute angles. (If a,b,c are in G.P. ⇒ b^{2}= ac)
cot 36° cot 72° is equal to :
The value of cos^{2} 15° – cos^{2} 30° + cos^{2} 45° – cos^{2} 60° + cos^{2} 75° is :
If x = sin^{2} θ cos θ and y = cos^{2} θ sin θ, then :
If x = secθ – tanθ and y = cosecθ + cotθ, then xy + 1 is equal to :
If 5 sinθ = 3, then secθ tanθ /secθ – tanθ is equal to :
The value of the expression
Given that sin A=1/2 and cos B=1/√2 then the value of (A + B) is:
If m = tanθ + sinθ and n = tanθ – sinθ, then (m^{2} – n^{2})^{2} is equal to :
If x = a cos θ + b sin θ and y = a sin θ – b cos θ then a^{2} + b^{2} is equal to :
If cosθ + sinθ + 1 = 0 and sinθ – cosθ – 1 = 0 then + is equal to :
ABC is a triangle, right angled at A. If the length of hypotenuse is 2 √2 times the length of perpendicular from A on the hypotenuse, the other angles of the triangle are :
If sin A + cos A = m and sin^{3}A + cos^{3}A = n, then
The quadratic equation whose roots are sin 18° and cos 36° is :
If cosθ + sectθ = 2, then the value of cos^{2}θ + sec^{2}θ is :
If sin (A – B) = cos (A + B) =1/2, then the values of A and B lying between 0° and 90° are respectively:
If m^{2} + m'^{2} + 2mm' cosθ = 1, n^{2} + n'^{2} + 2nn' cos θ = 1, and mn + m'n' + (mn' + m'n) cos θ = 0, then m^{2} + n^{2} is equal to :
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