Math Olympiad Test: Probability- 1 - Class 10 MCQ

P (getting neither a king nor a queen)
= 1 - P (getting a king or a queen)

In a leap year there are 366 days
We have, 366 days =52 weeks and 2 days. 
Thus, a leap year will have 52 Tuesdays.
The remaining 2 days can be
(i) Sunday and Monday
(ii) Monday and Tuesday
(iii) Tuesday and Wednesday
(iv) Wednesday and Thursday
(v) Thursday and Friday
(vi) Friday and Saturday
(vii) Saturday and Sunday
Total number of possible cases =7
Total number of favourable cases =2
Hence, required probability = 2/7

1, 2, 3, . . . . 35
The numbers which are divisible by 4. 4, 8, 12, 16, 20, 24
P (Number divisible by 4) = 6/25
P (Number not divisible by 4) =

Total no. of tickets = 20
Let E = The ticket drawn has an even digit at 10’s place
E = 180, 127, 122, 143, 222, 162, 182,
P(E) = 7/20

Total no. of bulbs = 24
No. of defective bulbs = 25% of 24

Now a bulb is drawn at random from the 10%. It is found to be not defective and it is not put back. Now one bulb is drawn at random from the rest. Hence the probability that this bulb is not defective = 17/23

No. of possible outcomes = 5 + 7 + 3 = 15
Probability of black marble = 7/15
Probability of white marble = 3/15
Probability that the marble taken out will be black or white =

Total no. of balls = 6 + 8 + 5 + 3 = 22 Probability that ball drawn is not white

In a leap year, there are 366 days.
There are 52 weeks and 2 days.
There are 52 Sundays.
There may be five possibilities of being not a Sunday, which are (Monday, Tuesday) (Tuesday, Wednesday), (Wednesday, Thursday), (Thursday, Friday), (Friday, Saturday).
Probability for 52 Sunday = 5/7

Let the no. of black balls = x
Total no. of balls = x + 5
Probability of drawing a black ball = 
Probability of drawing a red ball =
According to question,

Total no. of outcomes = 52
No. of ace cards = 4
No. of Non ace cards = 52 - 4 = 48
P (getting a non-ace card) = 48/52 = 12/13