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Math Olympiad Test: Trigonometry- 1 - Class 10 MCQ


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10 Questions MCQ Test Olympiad Preparation for Class 10 - Math Olympiad Test: Trigonometry- 1

Math Olympiad Test: Trigonometry- 1 for Class 10 2024 is part of Olympiad Preparation for Class 10 preparation. The Math Olympiad Test: Trigonometry- 1 questions and answers have been prepared according to the Class 10 exam syllabus.The Math Olympiad Test: Trigonometry- 1 MCQs are made for Class 10 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Math Olympiad Test: Trigonometry- 1 below.
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Math Olympiad Test: Trigonometry- 1 - Question 1

If in a triangle ABC, A and B are complementary, then tan C is

Detailed Solution for Math Olympiad Test: Trigonometry- 1 - Question 1

Given A and B are complementary angles then ∠A + ∠B = 90 (i)
and in ∆ABC ∠A + ∠B + ∠C = 180 (ii)
From (i) and (ii) ∠C = 90
∴ tan ∠C = tan 90 = ∞

Math Olympiad Test: Trigonometry- 1 - Question 2

sin220 + sin270 is equal to ______.

Detailed Solution for Math Olympiad Test: Trigonometry- 1 - Question 2

Given
sin220 + sin270 = sin220 + [cos(90 - 20)]2
= sin220 + cos220 = 1

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Math Olympiad Test: Trigonometry- 1 - Question 3

A wheel makes 20 revolutions per hour. The radians it turns through 25 minutes is

Detailed Solution for Math Olympiad Test: Trigonometry- 1 - Question 3

1 revolution = 2*π radian
Given that
The number of revolutions in 1 hour = 20
So,
The number of revolution in 25 minutes = 20 x 25/60 = 25/3
The radians it run through in 25 minutes = (25/3)2 * π
⇒ 50πc/3

Math Olympiad Test: Trigonometry- 1 - Question 4

Simplified expression of (sec θ + tan θ) (1 - sin θ) is

Detailed Solution for Math Olympiad Test: Trigonometry- 1 - Question 4

Math Olympiad Test: Trigonometry- 1 - Question 5

If secα + tanα = m, then sec4α - tan4a - 2secα tanα is

Detailed Solution for Math Olympiad Test: Trigonometry- 1 - Question 5

sec α + tan α = m then sec4α - tan4α - 2sec α tanα
= (sec2α - tan2α) (sec2α + tan2α) - 2sec α tan α = sec2a + tan2a - 2sec α tan α
= (sec α + tan α) = m2

Math Olympiad Test: Trigonometry- 1 - Question 6

If tan (A - 30°) = 2 - √3 , then find A.

Detailed Solution for Math Olympiad Test: Trigonometry- 1 - Question 6

Given tan (A - 30°) = 2 - √3


Math Olympiad Test: Trigonometry- 1 - Question 7

Detailed Solution for Math Olympiad Test: Trigonometry- 1 - Question 7

Math Olympiad Test: Trigonometry- 1 - Question 8

(cosecA - sinA) (secA - cosA) (tanA + cotA) =

Detailed Solution for Math Olympiad Test: Trigonometry- 1 - Question 8

Given (cosec A − sinA)(sec A − cosA)(tan A + cotA)

Math Olympiad Test: Trigonometry- 1 - Question 9

The value of 

Detailed Solution for Math Olympiad Test: Trigonometry- 1 - Question 9

Simplify the numerator and denominator by taking common terms appropriately.

Math Olympiad Test: Trigonometry- 1 - Question 10

If tan(α + β) = 12 and tan α = 13, then tan = β

Detailed Solution for Math Olympiad Test: Trigonometry- 1 - Question 10

tan = β is 1/7

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