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JEE Advanced Test- 11 - JEE MCQ


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30 Questions MCQ Test Mock Tests for JEE Main and Advanced 2025 - JEE Advanced Test- 11

JEE Advanced Test- 11 for JEE 2024 is part of Mock Tests for JEE Main and Advanced 2025 preparation. The JEE Advanced Test- 11 questions and answers have been prepared according to the JEE exam syllabus.The JEE Advanced Test- 11 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Advanced Test- 11 below.
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JEE Advanced Test- 11 - Question 1

A piston can freely move inside a horizontal cylinder closed from both ends. Initially, the piston separates the inside space of the cylinder into two equal parts each of  volume V0 , in which an ideal gas is contained under the same pressure p0 and at the same temperature. What work has to be performed  in order to increase isothermally the volume of one part of gas 2 times compared to that of the other by slowly moving the piston ?

Detailed Solution for JEE Advanced Test- 11 - Question 1

JEE Advanced Test- 11 - Question 2

A uniform pressure P is exerted by an external agent on all sides of a solid cube at temperature t ºC. By what amount should the temperature of the cube be raised in order to bring its volume back to its original volume before the pressure was applied if the bulk modulus is B and co-efficient of volumetric expansion is ?

Detailed Solution for JEE Advanced Test- 11 - Question 2

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JEE Advanced Test- 11 - Question 3

Two rods of same dimensions, but made of different materials are joined end to end with their free ends being maintained at 100ºC and 0ºC respectively. The temperature of the junction is 70ºC. Then the temperature of the junction if the rods are interchanged will be equal to : 

Detailed Solution for JEE Advanced Test- 11 - Question 3

JEE Advanced Test- 11 - Question 4

Assume a sample of an ideal gas in a vessel. Where velocity of molecules are between 2 m/sec to 5 m/sec and velocity of molecules (v) and number of molecules (n) are related as n = 7v – v2 – 10. The most probable velocity in sample is. Where v is measured in m/sec.

Detailed Solution for JEE Advanced Test- 11 - Question 4

JEE Advanced Test- 11 - Question 5

If specific heat capacity of a substance in solid and liquid state is proportional to temperature of the substance, then if heat is supplied to the solid initially at – 20°C (having melting point 0°C) at constant rate. Then the temperature dependence of substance with time will be best represented by :

Detailed Solution for JEE Advanced Test- 11 - Question 5

JEE Advanced Test- 11 - Question 6

In the figure shown the pressure of the gas in state B is:

Detailed Solution for JEE Advanced Test- 11 - Question 6

JEE Advanced Test- 11 - Question 7

A hot black body emits the energy at the rate of 16 J m–2 s–1 and its most intense radiation corresponds to 20,000 Å. When the temperature of this body is further increased and its most intense radiation corresponds to 10,000 Å, then the energy radiated in Jm–2 s–1 will be :

Detailed Solution for JEE Advanced Test- 11 - Question 7

JEE Advanced Test- 11 - Question 8

Two identical rectangular rods of metal are welded end to end in series between temperature 0°C and 100°C and 10 J of heat is conducted (in steady state process) through the rod in 2.00 min. If 5 such rods are taken and joined as shown in figure maintaining the same temperature difference between A and B,  then the time in which 20 J heat will flow through the rods  is :     

Detailed Solution for JEE Advanced Test- 11 - Question 8

*Multiple options can be correct
JEE Advanced Test- 11 - Question 9

An ideal gas undergoes a cyclic process abcda which is shown by pressure- density curve.

Detailed Solution for JEE Advanced Test- 11 - Question 9

*Multiple options can be correct
JEE Advanced Test- 11 - Question 10

The emissive power of a black body at T = 300 K is 100 Watt/m2. Consider a body B of area A = 10 m2 coefficient of reflectivity r = 0.3 and coefficient of transmission t = 0.5 and at temperature 300 K. Then which of the following is correct : 

Detailed Solution for JEE Advanced Test- 11 - Question 10

*Multiple options can be correct
JEE Advanced Test- 11 - Question 11

The ends of a rod of uniform thermal conductivity are maintained at different (constant) temperatures. After the steady state is achieved : 

Detailed Solution for JEE Advanced Test- 11 - Question 11

Heat obviously flows from higher temperature to lower temperature in steady state. ⇒ A is true.

Thermal current through each cross section area is same. ⇒ C is true.
Temperature decreases along the length of the rod from higher temperature end to lower temperature end. ⇒ D
is false.

*Multiple options can be correct
JEE Advanced Test- 11 - Question 12

Number of collisions of molecules of a gas on the wall of a container per m2 will : 

Detailed Solution for JEE Advanced Test- 11 - Question 12

JEE Advanced Test- 11 - Question 13

Statement -1 : It is possible for both the pressure and volume of a monoatomic ideal gas of a given amount to change simultaneously without causing the internal energy of the gas to change.

Statement-2: The internal energy of an ideal gas of a given amount remains constant if temperature does not change. It is possible to have a process in which pressure and volume are changed such that temperature remains constant.

Detailed Solution for JEE Advanced Test- 11 - Question 13

An isothermal process is an example to show the possibility "for both the pressure and volume of a monoatomic ideal gas to change simultaneously without causing the internal energy of the gas to change".
Hence Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.

JEE Advanced Test- 11 - Question 14

Statement-1 : Molar heat capacity of an ideal monoatomic gas at constant volume is a constant at all temperatures.

Statement-2 : As the temperature of an monoatomic ideal gas is increased, number of degrees of freedom of gas molecules remains constant.
 

Detailed Solution for JEE Advanced Test- 11 - Question 14

For monoatomic gas the degrees of freedom are only translational and hence do not depend on temperature. Therefore molar heat capacity of an ideal monoatomic gas at constant volume is a constant at all temperatures.

JEE Advanced Test- 11 - Question 15

Statement-1 : Burns sustained from steam at 100ºC are usually more serious than those sustained by boiling water (at 100ºC)

Statement-2 : To convert 1gm of water at 100ºC to 1 gm of steam at 100ºC, 540 calories of heat is to be supplied. Hence 1gm of steam at 100ºC has more heat content than 1 gm of water at 100ºC

Detailed Solution for JEE Advanced Test- 11 - Question 15

Heat energy stored in 1 g of steam at 100°C is more in comparison to 1 g of water at 100°C. Hence burns caused by steam are more severe.

JEE Advanced Test- 11 - Question 16

Statement-1 : If the absolute temperature of a gas is doubled, the final rms-velocity of the gas particles becomes √2 times the initial value.
    Statement-2: The average translational kinetic energy of molecules in a gas is equal to both  and 3/2KT.( where vrms, k and T have usual meanings)

Detailed Solution for JEE Advanced Test- 11 - Question 16

 if the absolute temperature T doubles, vrms must increase by √2 (m and k are constants).

JEE Advanced Test- 11 - Question 17

A 0.60 kg sample of water and a sample of ice are placed in two compartments A and B that are separated by a conducting wall, in a thermally insulated container. The rate of heat transfer from the water to the ice through the conducting wall is constant P, until thermal equilibrium is reached. The temperature T of the liquid water and the ice are given in graph as functions of time t. Temperature of the each compartment remain homogeneous during whole heat transfer process.   
    Given specific heat of ice = 2100 J/kg-K
    Given specific heat of water = 4200 J/kg-K
    Latent heat of fusion of ice = 3.3 × 105 J/kg

Q. The value of rate P is

Detailed Solution for JEE Advanced Test- 11 - Question 17

JEE Advanced Test- 11 - Question 18

A 0.60 kg sample of water and a sample of ice are placed in two compartments A and B that are separated by a conducting wall, in a thermally insulated container. The rate of heat transfer from the water to the ice through the conducting wall is constant P, until thermal equilibrium is reached. The temperature T of the liquid water and the ice are given in graph as functions of time t. Temperature of the each compartment remain homogeneous during whole heat transfer process.   
    Given specific heat of ice = 2100 J/kg-K
    Given specific heat of water = 4200 J/kg-K
    Latent heat of fusion of ice = 3.3 × 105 J/kg

Q. The initial mass of the ice in the container is equal to 

Detailed Solution for JEE Advanced Test- 11 - Question 18

Sample of ice has been receiving heat at constant rate P from water. Its temperature has increased by 30°C in time 60 min.

JEE Advanced Test- 11 - Question 19

A 0.60 kg sample of water and a sample of ice are placed in two compartments A and B that are separated by a conducting wall, in a thermally insulated container. The rate of heat transfer from the water to the ice through the conducting wall is constant P, until thermal equilibrium is reached. The temperature T of the liquid water and the ice are given in graph as functions of time t. Temperature of the each compartment remain homogeneous during whole heat transfer process.   
    Given specific heat of ice = 2100 J/kg-K
    Given specific heat of water = 4200 J/kg-K
    Latent heat of fusion of ice = 3.3 × 105 J/kg

Q. The mass of the ice formed due to conversion from the water till thermal equilibrium is reached, is equal to 

Detailed Solution for JEE Advanced Test- 11 - Question 19

Thermal equilibrium reaches after 60 min. Ice conversion takes place for 20 min. During this time water at 0°C continues to give heat at rate P.

= 0.15 kg

JEE Advanced Test- 11 - Question 20

A quantity of an ideal monoatomic gas consists of n moles initially at temperature T1. The pressure and volume both are then slowly doubled in such a manner so as to trace out a straight line on a P-V diagram.

Q. For this process, the ratio  is equal to (where W is work done by the gas) :

Detailed Solution for JEE Advanced Test- 11 - Question 20

JEE Advanced Test- 11 - Question 21

A quantity of an ideal monoatomic gas consists of n moles initially at temperature T1. The pressure and volume both are then slowly doubled in such a manner so as to trace out a straight line on a P-V diagram.

Q. For the same process, the ratio  is equal to (where Q is heat supplied to the gas) :

Detailed Solution for JEE Advanced Test- 11 - Question 21

JEE Advanced Test- 11 - Question 22

A quantity of an ideal monoatomic gas consists of n moles initially at temperature T1. The pressure and volume both are then slowly doubled in such a manner so as to trace out a straight line on a P-V diagram.

Q. If C is defined as the average molar specific heat for the process then C/R has value 

Detailed Solution for JEE Advanced Test- 11 - Question 22

JEE Advanced Test- 11 - Question 23

A sample of gas goes from state A to state B in four different manners, as shown by the graphs. Let W be the work done by the gas and DU be change in internal energy along the path AB. Correctly match the graphs with the statements provided.
        Column I 

    Column II 

(p) W is positive    (q) ΔU is negative    (r) W is negative    (s) ΔU is positive    (t) heat rejected ΔQ < 0

 

Detailed Solution for JEE Advanced Test- 11 - Question 23

In (A), V is on vertical axis.

As negative work in part-II is greater than positive work in part-I, net work during the process is negative.
Using PV = nRT and as Vremains same for initial and final points of the process, it is obvious that final temp.is greater than initial temperature as pressure has increased. Therefore dU is positive. Hence option (S) is
connected with (A).
Similar arguments can be applied to other graphs.

JEE Advanced Test- 11 - Question 24

A copper rod (initially at room temperature 20°C) of non-uniform cross section is placed between a steam chamber at 100°C and ice-water chamber at 0°C. 

Detailed Solution for JEE Advanced Test- 11 - Question 24

(A) Initially more heat will enter through section A but the metal will absorb some heat and less heat will
leave from C.
(B) At steady state heat accumulatron = )

maximum at B and minimum at C
(D) At steady state heat accumulation = 0
So =0 for any section.

JEE Advanced Test- 11 - Question 25

Which of the following orders is correct for the size ?

(1) Mg2+ < Na+ < F < Al     (2) Al3+ < Mg2+ < Li+ < K+    (3) Fe4+ < Fe3+ < Fe2+ < Fe    (4) Mg > Al > Si > P

Detailed Solution for JEE Advanced Test- 11 - Question 25

(1) Mg2+, Na+ and Fare isoelectronic and thus follows the order 12Mg2+ < 11Na+ < 9F .
Al belongs to third period and has no charge so it is largest.
Na+ = 102 pm; Mg2+ = 72 pm ; Al = 143 pm, F= 133 pm.
(2) K+ has more number of shells than Mg2+ and AI3+ . AI3+ and Mg2+ are isoelectronic but AI3+ has higher nuclear
charge so AI3+ < Mg2+. Mg2+ and Li+ has diagonal relationship. But due to +2 charge in Mg2+, the Mg2+ is smaller
than Li+. Hence Al3+ is the smallest one. K+ = 1.38 Å, Li2+ = 0.76 Å, Mg2+ = 0.72 Å and Al3+ = 0.535 Å.
(3) As the number of electrons are lost, the attraction between valence shell electrons and nucleus increases. As a
consequence of this the electrons are pulled closer to the nucleus leading to the contraction in size of ions.
(4) Across the period the nuclear charge increases and thus the size of atoms decreases. Mg = 160 pm;
Al = 143 pm; Si = 118 ; P = 110 pm.

JEE Advanced Test- 11 - Question 26

Which reactions involves a change in the electron–pair geometry for the under lined atoms ?

Detailed Solution for JEE Advanced Test- 11 - Question 26

JEE Advanced Test- 11 - Question 27

Anhydrous AlCl3 is covalent. From the data given below 
            Lattice Energy = 5137 KJ/mol. 
            ΔH hydration for Al3+ = – 4665 KJ/mol
            ΔH hydration for Cl = – 381 KJ/mol
Identify the correct statement.

Detailed Solution for JEE Advanced Test- 11 - Question 27

Hence AlCl3 will dissolve and solution consists of hydrated Al3+ and Cl ions. In other words higher hydration
energy compensates the higher ionisation energy. As a result, it will exist as hydrated Al3+ and hydrated Cl in aqueous solution.

JEE Advanced Test- 11 - Question 28

In which of the following molecules / ions are all the bond angles not equal ?

Detailed Solution for JEE Advanced Test- 11 - Question 28

Remaining molecules / ions have symmetrical structures ; so have all bonds equal.

JEE Advanced Test- 11 - Question 29

When sodium nitrate is heated at 800ºC :

Detailed Solution for JEE Advanced Test- 11 - Question 29

JEE Advanced Test- 11 - Question 30

In which of the following  reaction carbon monoxide is obtained as one of the products ?

Detailed Solution for JEE Advanced Test- 11 - Question 30

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