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Test: Pressure, Streamline flow & Bernoulli's Principle (21 August) - JEE MCQ


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10 Questions MCQ Test Daily Test for JEE Preparation - Test: Pressure, Streamline flow & Bernoulli's Principle (21 August)

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Test: Pressure, Streamline flow & Bernoulli's Principle (21 August) - Question 1

The pressure of 1 atm = ______ Pa

Detailed Solution for Test: Pressure, Streamline flow & Bernoulli's Principle (21 August) - Question 1

Pressure of 1 atm = 1.013 x 105 Pa

Test: Pressure, Streamline flow & Bernoulli's Principle (21 August) - Question 2

Which of the following is not an application of Pascal’s Law?

Detailed Solution for Test: Pressure, Streamline flow & Bernoulli's Principle (21 August) - Question 2

Pascal's law states that the magnitude of pressure within the fluid is equal in all parts.

Option A: Brahma's press is a Hydraulic Press that works on the principle of Pascal's law.

Option B: Submarines don't work on the principle of Pascal's law.

Option C: Hydraulic lifts works on the principle of pascals law i.e. a force applied on a smaller cylinder is transmitted to lift heavy loads using larger cylinders.

Hence, option B is correct.

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Test: Pressure, Streamline flow & Bernoulli's Principle (21 August) - Question 3

The pressure at the bottom of a tank containing a liquid does not depend on:

Detailed Solution for Test: Pressure, Streamline flow & Bernoulli's Principle (21 August) - Question 3

Pressure at the bottom of a tank containing liquid is given as P = hρg which is independent of the surface area bottom of the tank.

Test: Pressure, Streamline flow & Bernoulli's Principle (21 August) - Question 4

Find the density when a liquid 5 m high in a column exerts a pressure of 80 Pa.

Detailed Solution for Test: Pressure, Streamline flow & Bernoulli's Principle (21 August) - Question 4

► Pressure = Density x Gravity x Height = ρgh 
⇒  ρ = P/(g*h) = 80 Pa / (9.8 m/s2 x 5 m)
Density = 1.632 kg/m3

Test: Pressure, Streamline flow & Bernoulli's Principle (21 August) - Question 5

Water is flowing continuously from a tap having an internal diameter 8 x 10-3 m. The water velocity as it leaves the tap is 0.4 ms-1. The diameter of the water stream at a distance 2 x 10-1 m below the tap is close to:

Detailed Solution for Test: Pressure, Streamline flow & Bernoulli's Principle (21 August) - Question 5

Test: Pressure, Streamline flow & Bernoulli's Principle (21 August) - Question 6

Bernoulli’s theorem includes as a special case of:

Detailed Solution for Test: Pressure, Streamline flow & Bernoulli's Principle (21 August) - Question 6

Bernoulli’s theorem, in fluid dynamics, relation among the pressure, velocity, and elevation in a moving fluid (liquid or gas), the compressibility and viscosity (internal friction) of which are negligible and the flow of which is steady, or laminar. First derived (1738) by the Swiss mathematician Daniel Bernoulli, the theorem states, in effect, that the total mechanical energy of the flowing fluid, comprising the energy associated with fluid pressure, the gravitational potential energy of elevation, and the kinetic energy of fluid motion, remains constant. Bernoulli’s theorem is the principle of energy conservation for ideal fluids in steady, or streamline, flow and is the basis for many engineering applications.

Test: Pressure, Streamline flow & Bernoulli's Principle (21 August) - Question 7

Air is streaming past a horizontal airplane wing such that its speed is 120 m/s over the upper surface and 90 m/s at the lower surface. If the density of the air is 1.3 kg/m3and the wing is 10 m long and has an average width of 2 m, then the difference of pressure on the two sides of the wing is

Detailed Solution for Test: Pressure, Streamline flow & Bernoulli's Principle (21 August) - Question 7

Applying Bernoulli's principle, we have
P1+1/2​ρv12=P2+1/2​ρv22 
⇒P2​−P1=1/2ρ (v2/1−v2/2)
⇒ΔP=1/2​×1.3× (1202−902)
⇒ΔP=0.65× (120+90) × (120−90)
⇒ΔP=0.65×210×30=4095Pa

Test: Pressure, Streamline flow & Bernoulli's Principle (21 August) - Question 8

In the houses far away from the municipal water tanks often people find it difficult to get water on the top floor. This happens because

Detailed Solution for Test: Pressure, Streamline flow & Bernoulli's Principle (21 August) - Question 8

Every foot of elevation change causes a 0.433 PSI change in water pressure. If your pipe is going downhill add 0.433 PSI of pressure per vertical foot the pipe goes down. If the pipe is going uphill subtract 0.433 PSI for every vertical foot the pipe goes up.

Test: Pressure, Streamline flow & Bernoulli's Principle (21 August) - Question 9

Water is flowing through a horizontal pipe in streamline flow at the narrowest part of the pipe:

Detailed Solution for Test: Pressure, Streamline flow & Bernoulli's Principle (21 August) - Question 9

In streamline flow, the product of cross section area and velocity remains constant (equation of continuity). So in the narrowest part of the pipe velocity is maximum. 
And from Bernoulli's theorem, we know that the sum of potential energy, kinetic energy and pressure energy remains constant. Since pipe is horizontal potential energy is equal at all the points. So the narrowest part  of pipe pressure (pressure energy) will be minimum because velocity (kinetic energy) is maximum in the narrowest part.

Test: Pressure, Streamline flow & Bernoulli's Principle (21 August) - Question 10

 Bernoulli’s principle is based on the conservation of:

Detailed Solution for Test: Pressure, Streamline flow & Bernoulli's Principle (21 August) - Question 10

Bernoulli's principle can even be derived from the principle of conservation of energy. Bernoulli's principle states that, in a steady flow, the sum of all forms of energy in a fluid along a streamline is the same at all points on that streamline.
Hence D is the correct answer.

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