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Test: Homogeneous Equilibria & Heterogeneous Equilibria (4 July) - JEE MCQ


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10 Questions MCQ Test Daily Test for JEE Preparation - Test: Homogeneous Equilibria & Heterogeneous Equilibria (4 July)

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Test: Homogeneous Equilibria & Heterogeneous Equilibria (4 July) - Question 1

One of the reactions that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and carbon dioxide.
FeO (s) + CO (g)  Fe (s) + CO2(g); Kp = 0.265 atm at 1050 K
Initial partial pressure
CO(g) = 1.40 atm
CO2(g) = 0.80 atm

Q. When equilibrium is attained,

Detailed Solution for Test: Homogeneous Equilibria & Heterogeneous Equilibria (4 July) - Question 1

Initially 1.4 atm  0.80 atm
Qp = pCO2/pCO 0.8/1.4 = 0.571
SInce Q> Kp ; reaction proceeds in the backward direction. So pressure of CO2 decreases and that of CO increases.
At eqm.  1.4+p atm  0.80-p atm
Kp = pCO2/pCO = 0.80-p/1.4+p
0.265 = 0.80-p/1.4+p
Or p = 0.339 atm
Therefore, partial pressure at eqm, pCO2 = 0.80-0.339 = 0.461 atm
And pCO = 1.4+0.339 = 1.739 atm

Test: Homogeneous Equilibria & Heterogeneous Equilibria (4 July) - Question 2

A sample of N2O4(g)with a pressure of 1.00 atm is placed in a flask. When equilibrium is reached, 20% of N2O4(g)has been converted to NO2(g)

If the original pressure is made 10% of the earlier pressure, then per cent dissociation will be

Detailed Solution for Test: Homogeneous Equilibria & Heterogeneous Equilibria (4 July) - Question 2

Correct answer is A.

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Test: Homogeneous Equilibria & Heterogeneous Equilibria (4 July) - Question 3

Direction (Q. Nos. 1-13) This section contains 13 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

Q. Given the reactions, If one mole each of A and B are take in 5 L flask at 300 K, 0.7 mole of C are formed. Molar concentration of each species at equilibrium, when one mole of each are taken initially is

Test: Homogeneous Equilibria & Heterogeneous Equilibria (4 July) - Question 4

Ammonium carbamate dissociates as,

In a closed vessel containing ammonium carbamate in equilibrium with its vapour, ammonia is added such that partial pressure of NH3 now equals the original total pressure. Thus, ratio of the total pressure to the original pressure is

Detailed Solution for Test: Homogeneous Equilibria & Heterogeneous Equilibria (4 July) - Question 4

Test: Homogeneous Equilibria & Heterogeneous Equilibria (4 July) - Question 5

A gaseous phase reaction taking place in 1L flask at 400 K is given, 

Starting with 1 mole N2 and 3 moles H2, equilibrium mixture required 250 mL of 1M H2SO4 . Thus, Kc is 

Test: Homogeneous Equilibria & Heterogeneous Equilibria (4 July) - Question 6

Following equilibrium is set up at 298 K in a 1 L flask.

If one starts with 2 moles of A and 1 mole of B, it is found that moles of B and D are equal. Thus Kc is 

Detailed Solution for Test: Homogeneous Equilibria & Heterogeneous Equilibria (4 July) - Question 6

Test: Homogeneous Equilibria & Heterogeneous Equilibria (4 July) - Question 7

The equilibrium constant for the following reaction, is 1.6 x 105 at 1024 K.
H2(g) + Br2(g) ⇌ 2HBr(g)
HBr (g)at 10.0 bar is introduced into a sealed container at 1024 K. Thus, partial pressure of H2(g) and Br2(g), together is

Detailed Solution for Test: Homogeneous Equilibria & Heterogeneous Equilibria (4 July) - Question 7






Squaring on both sides 






⇒ 10 bar approximately

Test: Homogeneous Equilibria & Heterogeneous Equilibria (4 July) - Question 8

For the following equilibrium,

Test: Homogeneous Equilibria & Heterogeneous Equilibria (4 July) - Question 9

Ca(HCO3)2 is strongly heated and after equilibrium is attained, temperature changed to 25° C.

Ca(HCO3)2(s)⇌CaO(s) + 2CO2 (g) + H2O(g)
Kp = 36 (pressure taken in atm)
Thus, pressure set up due to CO2 is

Detailed Solution for Test: Homogeneous Equilibria & Heterogeneous Equilibria (4 July) - Question 9

The reaction is as follow:-
Ca(HCO3)2(s)⇌CaO(s) + 2CO2 (g) + H2O(g)
At 25° C H2O goes in liquid state
Kp = (PCaO)1×(PCO2)2
(PCa(HCO3)2)
Since, Ca(HCO3)2, CaO and H2O are not in gaseous state, so their partial pressure is taken 1.
Putting all values, we have
36 = (PCO2)2 
Or PCO2 = 6 atm

Test: Homogeneous Equilibria & Heterogeneous Equilibria (4 July) - Question 10

Solid ammonium chloride is in equilibrium with ammonia and hydrogen chloride gases

0.980 g of solid NH4CI is taken in a closed vessel of 1 L capacity and heated to 275° C.

Q. Percentage decomposition of the original sample is

Detailed Solution for Test: Homogeneous Equilibria & Heterogeneous Equilibria (4 July) - Question 10

The state of HCl is given wrong. It will be in gaseous state.
So, the reaction be like;-
NH4Cl(s)  ⇌ NH3(g) + HCl(g)   kp = 1.00×10-2 at 275° C
Kp = kc(RT)2
1.00 × 10-2 = kc(0.0821 × 548)2
Or kc = 4.94×10-6
  
Kc = x2
x = √(4.94×10-6)
=  2.22×10-3
Therefore, NH4Cl dissociated at eqm = 2.22×10-3 × 53.5 = 0.118
%age decomposition = 0.118/0.980×100 = 12.13%

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