JEE Exam  >  JEE Tests  >  Daily Test for JEE Preparation  >  Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) - JEE MCQ

Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) - JEE MCQ


Test Description

10 Questions MCQ Test Daily Test for JEE Preparation - Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep)

Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) for JEE 2024 is part of Daily Test for JEE Preparation preparation. The Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) questions and answers have been prepared according to the JEE exam syllabus.The Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) below.
Solutions of Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) questions in English are available as part of our Daily Test for JEE Preparation for JEE & Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) solutions in Hindi for Daily Test for JEE Preparation course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) | 10 questions in 20 minutes | Mock test for JEE preparation | Free important questions MCQ to study Daily Test for JEE Preparation for JEE Exam | Download free PDF with solutions
Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) - Question 1

Thermal decomposition of limestone produces:

Detailed Solution for Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) - Question 1
The thermal decomposition of limestone produces quicklime (calcium oxide). So, the correct answer is Option A.
Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) - Question 2

A system is in thermal equilibrium with its environment if:

Detailed Solution for Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) - Question 2
A system is in thermal equilibrium with its environment when the temperatures of the system and environment are equal. This is the fundamental definition of thermal equilibrium. So, the correct answer is Option A.
1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) - Question 3

Two bodies in contact are said to be in thermal equilibrium when:

Detailed Solution for Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) - Question 3
Two bodies in contact are said to be in thermal equilibrium when no heat flow occurs between the two bodies. In thermal equilibrium, their temperatures are the same, and there is no net transfer of heat between them. So, the correct answer is Option C.
Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) - Question 4
A solid X is in thermal equilibrium with a solid Y. Solid Y has the same temperature as solid Z. If the three solids have different masses and compositions, which one of the following statements is correct?
Detailed Solution for Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) - Question 4
The correct statement is: There will be no net transfer of energy if X is placed in thermal contact with Z. When two objects are in thermal equilibrium with a third object, they are at the same temperature, and there is no net transfer of energy between them. So, the correct answer is Option D.
Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) - Question 5
If __________ between the system and the surroundings, the process is adiabatic.
Detailed Solution for Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) - Question 5
In an adiabatic process, neither heat nor matter flows between the system and the surroundings. Adiabatic processes involve a change in the internal energy of the system without any heat exchange with the surroundings. So, the correct answer is Option C.
Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) - Question 6

110 joules of heat is added to a gaseous system, whose internal energy is 40 J. Then the amount of external work done is:

Detailed Solution for Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) - Question 6

The first law of thermodynamics states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system on its surroundings. Mathematically:

ΔU = Q - W

Where:
ΔU = Change in internal energy
Q = Heat added
W = Work done

Given:
ΔU = 110 J (heat added)
Q = 40 J (internal energy)
W = ?

Rearranging the equation:
W = Q - ΔU
W = 110 J - 40 J
W = 70 J

So, the amount of external work done is 70 J. Therefore, the correct answer is Option B.

Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) - Question 7

Which among the following is the correct option for adiabatic reversible expansion of an ideal gas?

Detailed Solution for Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) - Question 7

For an adiabatic reversible expansion of an ideal gas, the correct option is:

Option D: Entropy change for surroundings = 0, Total entropy change = 0, ΔT ≠ 0
In an adiabatic process, there is no heat exchange with the surroundings, so the entropy change for the surroundings is zero. However, there is a change in temperature (ΔT) for the system. So, the correct answer is Option D.

Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) - Question 8

The change in internal energy of 2 moles of a gas is -10 J. Find the work done on the gas if the process is adiabatic.

Detailed Solution for Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) - Question 8

In an adiabatic process, the change in internal energy (ΔU) is equal to the work done (W) on the gas. Given that ΔU = -10 J, the work done on the gas is also -10 J. Therefore, the correct answer is Option C.

Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) - Question 9
During the throttling process:
Detailed Solution for Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) - Question 9
During the throttling process, enthalpy does not change. Throttling is an adiabatic and irreversible process in which there is no heat exchange, so the change in enthalpy is negligible. So, the correct answer is Option D.
Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) - Question 10
Consider the following statements.
I. For an isolated system, energy (E) always remains constant.
II. The first law of thermodynamics is based on the conservation of mass.
III. For an ideal gas, the internal energy is a function of temperature only.
Which of the statement(s) given above is/are false?
Detailed Solution for Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) - Question 10
The false statement among the given options is:

II. The first law of thermodynamics is based on the conservation of mass.

The first law of thermodynamics is based on the conservation of energy, not mass. Therefore, Option B is the correct answer.
360 tests
Information about Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) Page
In this test you can find the Exam questions for Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep) solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Thermal equilibrium, zeroth and first law of thermodynamics(4 Sep), EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

Download as PDF

Top Courses for JEE