Test: Aldehyde, Ketone & Carboxylic Acids(11 Dec) - JEE MCQ

The correct answer is option D(None of the above)
The given compound is 4-Bromo-3methylheptanal

Alcohols have higher boiling points than aldehydes.

This is 1-phenyl propan-1-one.

Reductive Ozonolysis of alkene forms aldehyde or ketone.

Because conjugate base that form will be stable in case of Ketone.

In this reaction, a CO group is converted to CH_2​ group.

This can be achieved by Wolff-Kishner reduction which uses reagent NH₂​NH₂​, OH⁻ (hydrazine in alkaline medium).

Clemmensen reduction (Zn(Hg)/HCl) cannot be used as in presence of HCl, the alcohol may undergo dehydration.

Conc KMnO₄ will cause oxidation and ring opening forming adipic acid.

Acidic strength of carboxylic acid -

–  More acidic than phenols or alcohols.

–  Acidity increase with the presence of a group with  -I effect in the alkyl group.Whereas it decreases with the presence of  +I group.

–  Acidity increases with increase in the number of halogen atoms on  - position.

–  It decreases with increasing distance of halogen from   

–  It increases with increase in the electronegativity of halogen.

- CF₃COOH > CCl₃COOH > HCOOH > CH₃ COOH

-COOH is carboxyl group.

CH₃CHO will give iodoform test and C₆H₅CH₂CHO will not give iodoform test.

Pentanedioic acid is glutaric acid.

Maleic Acid shows Geometrical Isomerism but does not give optical isomerism.