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Test: Bio Inorganic- 2 - Chemistry MCQ

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30 Questions MCQ Test Inorganic Chemistry - Test: Bio Inorganic- 2

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Test: Bio Inorganic- 2 - Question 1

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Oxidized form of enzyme Catalase (structure A); prepared by the reaction of [Fe(P)]⁺ (P = porphyrin) with H₂O₂ has a green color because of:

A (substituents on ring are removed for clarity)

A.
Oxidat ion state of iron changed fro m Fe^III to Fe^IV.
B.
Porphyrin ring is oxidized by one electron.
C.
π–π* transit ion appears in the visible region.
D.
Fe^IV is coordinated with anionic tyrosinnate ligand in axial position.

Test: Bio Inorganic- 2 - Question 2

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At pH 7, the zinc(II) ion in carbonic anhydrase reacts with CO₂ to give:

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Test: Bio Inorganic- 2 - Question 3

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The cooperative binding Of O₂ in hemoglobin is due to:

A.
A decrease in size of iron followed by changes in the protein conformation.
B.
An increase in size of iron followed by changes in the protein conformat ion.
C.
A decrease in size of iron that is not accompanied by the protein comformational changes.
D.
An increase in size of iron that is not accompanied by the protein comformational changes.

Test: Bio Inorganic- 2 - Question 4

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Molybdoenzymes can both oxidize as well as reduce the substrates, because:

A.
Mo(VI) is more stable than Mo(IV).
B.
Mo(IV) can transfer oxygen atom to the substrate and Mo(VI) can abstract oxygen atom from the substrate.
C.
Conversion of Mo(VI) to Mo(IV) is not favoured.
D.
Mo(VI) can transfer oxygen atom to the substrate and Mo(IV) can abstract oxygen atom from the substrate.

Test: Bio Inorganic- 2 - Question 5

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Under physiological condition, oxygen is binding to deoxyhemoglobin and deoxymyoglobin, the binding curve and its pH dependence, respectively, are:

A.
Sigmoidal and pH dependent; hyperbolic and pH independent.
B.
Hyperbolic and pH independent; Sigmoidal and pH dependent.
C.
Sigmoidal and pH independent; hyperbolic and pH independent.
D.
Hyperbolic and pH dependent; Sigmoidal and pH dependent.

Test: Bio Inorganic- 2 - Question 6

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Match the metalloproteins in column A with their function in column B

The correct answer is

A.
I-(F); II-(C); III-(D); IV-(A)
B.
I-(E); II-(C); III-(A); IV-(F)
C.
I-(F); II-(B); III-(C); IV-(A)
D.
I-(E); II-(D); III-(C); IV-(A)

Test: Bio Inorganic- 2 - Question 7

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The total number of metal ion and the number of coordinated imidazole units of histidine in the active site of oxy-hemocyanin, respectively, are:

A.
2Cu²⁺ and 6
B.
2Fe²⁺ and 5
C.
2Cu⁺ and 6
D.
Fe²⁺ and 3

Detailed Solution for Test: Bio Inorganic- 2 - Question 7

Test: Bio Inorganic- 2 - Question 8

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The changes (from A-D given below) which occur when O₂binds to hemerythrin are

(A) One iron atom is oxidized

(B) Both the iron atoms are oxidized

(D) O₂ binds to both the iron atoms and is also hydrogen-bonded.

A.
B and C
B.
B and D
C.
A and D
D.
A and C

Test: Bio Inorganic- 2 - Question 9

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A.
3000
B.
2600
C.
1800
D.
900

Detailed Solution for Test: Bio Inorganic- 2 - Question 9

Test: Bio Inorganic- 2 - Question 10

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The metal present at the active site of the protein Carboxypept idase A is:

A.
Zinc
B.
Molybdenum
C.
Magnesium
D.
Cobalt

Test: Bio Inorganic- 2 - Question 11

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Match the following items of column I with the appropriate items in column II

A.
P-I, Q-II, R-III, S-IV
B.
P-II, Q-III, R-IV, S-V
C.
P-V, Q-IV, R-VI, S-II
D.
P-V, Q-VI, R-III, S-IV

Test: Bio Inorganic- 2 - Question 12

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In biological systems, the metal ion involved in the dioxygen transport besides Fe is:

A.
Co
B.
Zn
C.
Mg
D.
Cu

Test: Bio Inorganic- 2 - Question 13

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Iron–sulphur clusters in bio logical systems are involved in:

A.
Proton transfer
B.
Atom transfer
C.
Group transfer
D.
Electron transfer

Test: Bio Inorganic- 2 - Question 14

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The amino acid side chain high affinity for Ca²⁺ and Cu²⁺ in metallo–proteins is:

A.
Carboxylate in both the cases.
B.
Imidazole in both the cases.
C.
Carboxylate for Ca²⁺ and imidazo le for Cu²⁺.
D.
Imidazole for Ca²⁺ and carboxylate for Cu²⁺.

Test: Bio Inorganic- 2 - Question 15

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When a reduced cytochrome transfers an electron from its Fe(II) to the bound O₂:

A.
The bond order or O₂ is reduced by one and ν₀₂ decreases.
B.
A metal bound superoxide is formed and ν₀₂ decrease.
C.
A metal bound superoxide is formed and ν₀₂ increase.
D.
The bond order or O₂ is reduced by one and ν₀₂ increases.

Test: Bio Inorganic- 2 - Question 16

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In photosynthesis, the predominant metal present in the reaction centre of photo –system II is:

A.
Zn
B.
Cu
C.
Mn
D.
Fe

Detailed Solution for Test: Bio Inorganic- 2 - Question 16

manganese(Mn)

Metals exert important functions in the chloroplast of plants, where they act as cofactors and catalysts in the photosynthetic electron transport chain. In particular, manganese (Mn) has a key function because of its indispensable role in the water-splitting reaction of photosystem II (PSII).

Test: Bio Inorganic- 2 - Question 17

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Zn in carbonic anhydrase is coordinated by three histidine and one water molecule. The reaction of CO₂ with this enzyme is an example of:

A.
Nucleophilic addition.
B.
Electron transfer.
C.
Electrophilic addition.
D.
Electrophilic subst itution.

Detailed Solution for Test: Bio Inorganic- 2 - Question 17

CO₂acts as an electrophile and H₂O as a nucleophile which attacks CO_2.Hence, electrophilic addition takes place.

Test: Bio Inorganic- 2 - Question 18

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In biological systems, the metal ions involved in electron transport are:

A.
Na⁺ and K⁺
B.
Zn²⁺ and Mg²⁺
C.
Ca²⁺ and Mg²⁺
D.
Cu²⁺ and Fe²⁺

Test: Bio Inorganic- 2 - Question 19

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In the transformation of oxyhaemoglobin to deoxyhaemoglobin:

A.
Fe³⁺ in the low spin state changes to Fe²⁺ in the high spin state.
B.
Fe²⁺ in the low spin state changes to Fe³⁺ in the low spin state.
C.
Fe²⁺ in the high spin state changes to Fe²⁺ in the low spin state.
D.
Fe²⁺ in the high spin state changes to Fe³⁺ in the high spin state.

Test: Bio Inorganic- 2 - Question 20

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Among the following pair of metal ions present in Nature. The first one functions as an electron transfer agent and the second one catalyzes the hydrolysis reactions. The correct pair is:

A.
Fe and Zn
B.
Mg and Fe
C.
Co and Mo
D.
Ca and Cu

Test: Bio Inorganic- 2 - Question 21

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A well known naturally occurring organometallic compound is:

A.
Vitamin B₁₂ coenzyme.
B.
Chlorophyll.
C.
Cytochrome P–450.
D.
Myoglobin.

Test: Bio Inorganic- 2 - Question 22

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The red color of oxyhaemoglobin is mainly due to the:

A.
d–d transition
B.
Metal to ligand charge transfer transition
C.
Ligand to metal charge transfer transit ion
D.
Intra ligand π–π* transition.

Detailed Solution for Test: Bio Inorganic- 2 - Question 22

Each hemoglobin protein is made up subunits called hemes, which are what give blood its red color. More specifically, the hemes can bind iron molecules, and these iron molecules bind oxygen. The blood cells are red because of the interaction between iron and oxygen i.e. intra ligand π–π* transition.

When the iron is oxygenated(Fe+3), it becomes red. When the iron is deoxygenated(Fe+2), it becomes blue. This is why your veins are blue.

Test: Bio Inorganic- 2 - Question 23

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Hemoglobin is an oxygen carrying. The correct statement about oxy–hemoglobin is that:

A.
The metal is low–spin in +3 oxidation state while dioxygen is in O₂^- form.
B.
The metal is high–spin in +3 oxidat ion state while dioxygen is in O₂^- form.
C.
The metal is low–spin in +3 oxidation state while dioxygen is in neutral form.
D.
The metal is high–spin in +3 oxidation state while dioxygen is in neutral form.

Detailed Solution for Test: Bio Inorganic- 2 - Question 23

Hemoglobin is a protein found in red blood cells that carries oxygen from the lungs to the body's tissues and

returns carbon dioxide from the tissues to the lungs. Hemoglobin contains a heme group, which is a complex of iron

and porphyrin. When oxygen binds to the iron in heme, it forms oxyhemoglobin.

The correct statement about oxyhemoglobin is that the metal is lowspin in 3 oxidation state while dioxygen is in

02- form. Let's break this down:

Metal is lowspin in 3 oxidation state:

- The iron in heme is in the +2 oxidation state when it is not bound to oxygen.

- When oxygen binds to iron, it becomes oxidized to the +3 oxidation state.

- In the lowspin state, the electrons in the iron atom pair up in the d-orbitals, resulting in a lower magnetic moment.

Dioxygen is in 02- form:

- When oxygen binds to iron, it accepts two electrons from iron to form a peroxide bond.

- This results in the formation of 02-.

So, the correct statement is that the metal (iron) in oxyhemoglobin is lowspin in the +3 oxidation state, while

dioxygen is in the 02- form.

In summary, the correct answer to the question is option 'A'.

Test: Bio Inorganic- 2 - Question 24

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Oxymyoglobin Mb(O₂) and oxyhaemoglobin Hb(O₂)₄, respectively, are:

A.
Paramagnetic and paramagnetic.
B.
Diamagnetic and diamagnetic.
C.
Paramagnetic and diamagnetic.
D.
Diamagnetic and paramagnetic.

Test: Bio Inorganic- 2 - Question 25

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The number of oxygen molecule(s) that a molecule of hemerythrin can transport is:

A.
One
B.
Two
C.
Three
D.
Four

Test: Bio Inorganic- 2 - Question 26

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Mg²⁺ is preferred in photosynthesis by chlorophyll because:

A.
It has strong spin–orbit coupling.
B.
It has weak spin–orbit coupling.
C.
It is a heave metal.
D.
It binds strongly with chlorophyll.

Test: Bio Inorganic- 2 - Question 27

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Among the given pH values, the O₂ binding efficiency of hemoglobin is maximum at:

A.
6.8
B.
7.0
C.
7.2
D.
7.4

Test: Bio Inorganic- 2 - Question 28

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Identify the function of hemocyanin and the metal responsible for it:

A.
O₂ transport and Fe
B.
O₂ transport and Cu
C.
Electron transport and Fe
D.
Electron transport and Cu

Test: Bio Inorganic- 2 - Question 29

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During oxygen transport by hemerythrin, oxygen is bound as:

A.
O₂^– to one Fe(III) only
B.
HO₂^– to one Fe(III) only
C.
O₂^2– to one Fe(II) and one Fe(III)
D.
O₂^2– to two Fe(II)

Detailed Solution for Test: Bio Inorganic- 2 - Question 29

The mechanism of dioxygen binding is unusual. Most O₂ carriers operate via formation of dioxygen complexes, but hemerythrin holds the O₂ as a hydroperoxide (HO₂, or -OOH⁻). The site that binds O₂ consists of a pair of iron centres. The iron atoms are bound to the protein through the carboxylate side chains of a glutamate and aspartates as well as through five histidine residues. Hemerythrin and myohemerythrin are often described according to oxidation and ligation states of the iron center:

Fe²⁺—OH—Fe²⁺deoxy (reduced)

Fe²⁺—OH—Fe³⁺semi-met

Fe³⁺—O—Fe³⁺—OOH⁻oxy (oxidized)

Fe³⁺—OH—Fe³⁺— (any other ligand)met (oxidized)

The uptake of O₂ by hemerythrin is accompanied by two-electron oxidation of the diferrous centre to produce a hydroperoxide (OOH⁻) complex. The binding of O₂ is roughly described in this diagram:

Test: Bio Inorganic- 2 - Question 30

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At pH 7.2 and 10 Torr oxygen partial pressure, the extent of O₂ binding is:

A.
High for both hemoglobin and myoglobin
B.
High for hemoglobin and low for myoglobin
C.
High for myoglobin and low for hemoglobin
D.
Low for both hemoglobin and myoglobin

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