JEE Exam  >  JEE Tests  >  AP EAMCET Mock Test Series  >  AP EAMCET Mock Test - 1 - JEE MCQ

AP EAMCET Mock Test - 1 - JEE MCQ


Test Description

30 Questions MCQ Test AP EAMCET Mock Test Series - AP EAMCET Mock Test - 1

AP EAMCET Mock Test - 1 for JEE 2024 is part of AP EAMCET Mock Test Series preparation. The AP EAMCET Mock Test - 1 questions and answers have been prepared according to the JEE exam syllabus.The AP EAMCET Mock Test - 1 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for AP EAMCET Mock Test - 1 below.
Solutions of AP EAMCET Mock Test - 1 questions in English are available as part of our AP EAMCET Mock Test Series for JEE & AP EAMCET Mock Test - 1 solutions in Hindi for AP EAMCET Mock Test Series course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt AP EAMCET Mock Test - 1 | 160 questions in 180 minutes | Mock test for JEE preparation | Free important questions MCQ to study AP EAMCET Mock Test Series for JEE Exam | Download free PDF with solutions
AP EAMCET Mock Test - 1 - Question 1

A heater is designed to operate with a power of 1000 W in a 100 V line. It is connected in combination with a resistance of 10 Ω  and a resistance R to a 100 V line as shown in the figure. What should be the value of R so that the heater operates with a power of 62.5 W?

Detailed Solution for AP EAMCET Mock Test - 1 - Question 1

AP EAMCET Mock Test - 1 - Question 2

A rectangular loop carrying a current i is situated near a long straight wire such that the wire is parallel to one of the sides of the loop. If a steady current is established in the wire, as shown in the figure, the loop will

Detailed Solution for AP EAMCET Mock Test - 1 - Question 2

Referring to the figure, the forces acting on arms BC and AD are equal and opposite. The force on arm AB is given by

which is directed towards the wire. The force on arm CD is given by

which is directed away from the wire. Since F1 > F2, the loop will move towards the wire. Hence the correct choice is (3).

1 Crore+ students have signed up on EduRev. Have you? Download the App
AP EAMCET Mock Test - 1 - Question 3

A ray of light travels from a medium of refractive index n1 to a medium of refractive index n2. If angle of incidence is i and the angle of refraction is r. Then sini/sinr is equal to

Detailed Solution for AP EAMCET Mock Test - 1 - Question 3

According to Snell's law,

AP EAMCET Mock Test - 1 - Question 4

Transverse wave of amplitude 10 cm is generated at one end (x = 0) of a long string by a tuning fork of frequency 500 Hz. At a certain instant of time, the displacement of a particle A at x = 100 cm is -5 cm and of particle B at x = 200 cm is +5 cm. What is the wavelength of the wave?

Detailed Solution for AP EAMCET Mock Test - 1 - Question 4

AP EAMCET Mock Test - 1 - Question 5

Two masses of M and 4M are moving with equal kinetic energy. The ratio of their linear momentum is

Detailed Solution for AP EAMCET Mock Test - 1 - Question 5

Two masses are moving with equal kinetic energy.

The ratio of linear momentum is

AP EAMCET Mock Test - 1 - Question 6

A smooth sphere 'A' is moving on a frictionless horizontal surface with angular speed ω and centre of mass velocity v. It collides elastically and head-on with an identical sphere B at rest. Neglect friction everywhere. After the collision, their angular speeds are ωA and ωB, respectively. Then,

Detailed Solution for AP EAMCET Mock Test - 1 - Question 6

Since there is no friction between the sphere and the horizontal surface and also between the spheres themselves, there will be no transfer of angular momentum from sphere A to sphere B due to the collision. Since the collision is elastic and the spheres have the same mass, the sphere A only transfers its linear velocity v to sphere B. Sphere A will continue to rotate with the same angular speed ω at a fixed location. Hence the correct choice is (3).

AP EAMCET Mock Test - 1 - Question 7

Two particles of masses ma and mb and and same charge are projected in a perpendicular magnetic field. They travel along circular paths of radius ra and rand such that r> rb. Then which is true?

Detailed Solution for AP EAMCET Mock Test - 1 - Question 7

AP EAMCET Mock Test - 1 - Question 8

Two progressive waves having equation x1=3 sin ωt sin and x2=4 sin (ωt + 90o) are super imposed. The amplitude of the resultant wave is :

Detailed Solution for AP EAMCET Mock Test - 1 - Question 8

x1 = 3 sin ωt

x2=4 sin (ωt + 90o)

The phase difference between the two waves is 90o.

So,resultant amplitude

AP EAMCET Mock Test - 1 - Question 9

The correct order of boiling points of alkyl halides is

Detailed Solution for AP EAMCET Mock Test - 1 - Question 9
The correct order of boiling point of alkyl halides is Rl > RBr > RCl > RF. This is because with the increase in size and mass of the halogen atom, the magnitude of van der Waals' forces increases.
AP EAMCET Mock Test - 1 - Question 10

Which among the following is a neutral complex?

Detailed Solution for AP EAMCET Mock Test - 1 - Question 10
A neutral complex is a complex ion which have no charge on it. Among the given options [Pt(NH3)2Cl2] is a neutral complex. The type of complexes in other options are as follows

(a) [Fe(H2O)6]Cl3- cationic complexes

(b) [Ni(NH3)6]Cl2 - cationic complexes

(d) K[Ag(CN)2] - anionic complexes

AP EAMCET Mock Test - 1 - Question 11

If C(s) + O2(g) → CO2(g), ΔH = -X,

CO(g) + (1/2)O2(g) → CO2(g), ΔH = -Y,

Calculate ΔrH for CO(g) formation

Detailed Solution for AP EAMCET Mock Test - 1 - Question 11
C(s) + O2(g) → CO2(g), ΔH1 = -X, …(i)

CO(g) + (1/2)O2(g) → CO2(g), ΔH2 = -Y, ….(ii)

For the formation of CO subtract Eqs. (ii) from (i), i.e,

∴ ΔrH for formation of CO = ΔH1 - ΔH2

= -x+y or y-x

AP EAMCET Mock Test - 1 - Question 12

Which of the following sets of solutions of urea (mol, mass 60 g mol-1) and sucrose (mol. mass 342 g mol-1) is isotonic?

Detailed Solution for AP EAMCET Mock Test - 1 - Question 12
Key idea: Isotonic solutions are those solutions which have the same osmotic pressure at a given temperature.

Formula for osmotic pressure, π = CRT

considering the set given in option (d), i.e. 30 gL-1 urea and 17.1 gL-1 sucrose.

Given, the molecular mass of urea 60 g mol-1 and molecular mass of sucrose 342 g mol-1.

For urea.

conc, C = 3/60 = 1/20

Osmotic pressure π1 = (1/20) x R x T

For sucrose conc, C = 17.1/342 = 1/20

∴ Osmotic pressure, π2 = (1/20) RT

Thus, the set of solutions of urea and sucrose given in option (d) is isotonic.

AP EAMCET Mock Test - 1 - Question 13

Relationship between van't Hoff's factor (i) and degree of dissociation (α) is

Detailed Solution for AP EAMCET Mock Test - 1 - Question 13
Relationship between van't Hoff factor(i) and degree of dissociation (α) is given by

α = 1-i/n'-1

where, n is the number of ions formed alter dissociation.

The relationship can be obtained as follows;

For the reaction, A ⇌ n'B

Initially 1 mole 0

After dissociation (1 - α) mole n' α

Total number of moles present in the solution

= (1 - α) + n'α = 1 + (n'-1)α

van't Hoff factor, i = 1 + (n' - 1), α > 1 if n' ≥ 2

∴ α = i-1/n'-1

AP EAMCET Mock Test - 1 - Question 14

then K = …...

Detailed Solution for AP EAMCET Mock Test - 1 - Question 14
We have

Let

put x = a sin2 θ

⇒ dx = a(2 sinθ cos θ)dθ

when, x = 0, θ = 0 and x = a , θ = π/2

∴ k = πa

AP EAMCET Mock Test - 1 - Question 15

The solution of the differential equation dθ/dt = - k(θ - θ0) where k is constant, is …….

Detailed Solution for AP EAMCET Mock Test - 1 - Question 15
We have a differential equation

dθ/dt = -k(θ - θ0), where k is constant

⇒ (dθ/dt) + kθ = kθ0

Which is linear differential equation in the form of

(dy/dx) + Py = Q

IF = e∫kt = ekt

before the required solution,

(θ)(ekt) = ∫(ekt x kθ0)dt

⇒ θekt = ekt θ0 + a

⇒ θ = θ0 + ae-kt

AP EAMCET Mock Test - 1 - Question 16

= ……….

Detailed Solution for AP EAMCET Mock Test - 1 - Question 16

On adding Eqs. (i) and (ii), we get

AP EAMCET Mock Test - 1 - Question 17

The equation of the circle concentric with the circle x2 + y2 - 6x - 4y -12 = 0 and touching the Y-axis is ..........

Detailed Solution for AP EAMCET Mock Test - 1 - Question 17
Given equation of circle x2 + y2 - 6x + 4y -12 = 0 ...(i)

Centre of circle (i) te (3, 2)

Equation of circle concentric with the circle (i) and touching the Y- axis is

(x - 3)2 + (y - 2)2 = (3)2

⇒ x2 + 9 - 6x + y2 + 4 - 4y = 9

⇒ x2 + y2 - 6x - 4y + 4 = 0

AP EAMCET Mock Test - 1 - Question 18

The pdf of a random variable X is f(x) = 3(1 - 2x2), 0 < x="" />< 1="0" />

Detailed Solution for AP EAMCET Mock Test - 1 - Question 18
We have, p.d.f of a random variable

X is f (x) = 3(1- 2x2), 0 < x="" />< />

= 0, otherwise

= 179/864

AP EAMCET Mock Test - 1 - Question 19

A player tosses 2 fair coins. He wins Rs. 5 if 2 heads appear, Rs. 2 If 1 head appear and Rs. 1 if no head appears, then the variance of his winning amount is

Detailed Solution for AP EAMCET Mock Test - 1 - Question 19
When a player tosses 2 fair coins, then S = [HT, TH, TT, HH)

Let X be a random variable that denotes the amount received by the player.

Then.X can take values 5, 2, and 1.

Now, P(X = 5) = 1/4, P(X = 2) = 2/4 = 1/2 and P(X = 1) = 1/4

Thus, the probability distribution of X is

AP EAMCET Mock Test - 1 - Question 20

Detailed Solution for AP EAMCET Mock Test - 1 - Question 20

On adding Eqs. (i) and (ii). we get

⇒ I = 7π/18

AP EAMCET Mock Test - 1 - Question 21

Derivative of with respect to

Detailed Solution for AP EAMCET Mock Test - 1 - Question 21
Let y =

Put t = tan θ ⇒ θ = tan-1 t

sin-1 (sin θ) = θ = tan-1 t

= cos-1(cos θ)

= θ = tan-1t

AP EAMCET Mock Test - 1 - Question 22

For a sequence (tn), if Sn = 5(2n -1) then tn = …….

Detailed Solution for AP EAMCET Mock Test - 1 - Question 22
We have, Sn = 5(2n - 1)

We know that, an = Sn - Sn-1

= 5(2n - 1) - 5(2n-1 - 1)

= 5(2n - 2n-1)

= 5(2n-1)

AP EAMCET Mock Test - 1 - Question 23

The particular solution of the differential equation log(dy/dx) = x, when x = 0, y = 1 is ...

Detailed Solution for AP EAMCET Mock Test - 1 - Question 23
Wo have, differential equations,

dy = exdx

Integrating on both sides, we get ∫dy = ∫exdx

⇒ y = ex + C …(i)

On putting x = 0, y = 1 is Eq. (i), we get

1 = e0 + C ⇒ C = 0

Now, particular solution of the given differential is y = ex

AP EAMCET Mock Test - 1 - Question 24

If A, B, C and D are (3, 7, 4), (5, -2, 3), (-4, 5, 6) and (1, 2, 3) respectively, then the volume of the parallelepiped with AB, AC and AD as the coterminous edges, is ....... cubic units.

Detailed Solution for AP EAMCET Mock Test - 1 - Question 24

We have

∴ The volume of the parallelepiped with AB, AC, and AD on the coterminous edges

= |2 (2 + 10) + 9(7 + 4) -1(35 - 4)|

= |2 (12) + 9(11) - 1(31)|

= |(24 + 99 - 31)|

= |92| = 92 cubic units

AP EAMCET Mock Test - 1 - Question 25

The set of all values of k for which (tan-1x)3 + (cot-1x)3 = kπ3, x ∈ R, is the interval:

Detailed Solution for AP EAMCET Mock Test - 1 - Question 25

Let tan-1x = t 
cot-1x = π/2 - t


Max will occur around t = π/2
Range of f(t) = 

AP EAMCET Mock Test - 1 - Question 26

Consider the line L given by the equation . Let Q be the mirror image of the point (2, 3, -1) with respect to L. Let a plane P be such that it passes through Q, and the line L is perpendicular to P. Then which of the following points is on the plane P?

Detailed Solution for AP EAMCET Mock Test - 1 - Question 26

Plane p is ⊥ to line.

It passes through point (2, 3, -1).
Equation of plane p:
2(x - 2) + 1(y - 3) + 1(z + 1) = 0
2x + y + z - 6 = 0
Point (1, 2, 2) satisfies the above equation.

AP EAMCET Mock Test - 1 - Question 27

Let f(x) be a polynomial function such that f(x) + f'(x) + f''(x) = x5 + 64 and fv(x) = 120. Then, the value of 

Detailed Solution for AP EAMCET Mock Test - 1 - Question 27


f(x) + f'(x) + f'' (x) = x5 + 64
f'(x) + f''(x) + f'''(x) = 5x4
f''(x) + f'''(x) + fiv(x) = 20x3
f'''(x) + fiv(x) + fv(x) = 60x2
∴ fv(x) - f''(x) = 60x2 - 20x3
⇒ 120 - f''(1) = 40
⇒ f''(1) = 80
Also, f(1) + f'(1) + f''(1) = 65
⇒ f'(1) = -15

AP EAMCET Mock Test - 1 - Question 28

Area of the region bounded by y = cosx, x = 0, x = π and X-axis is ...sq. units.

Detailed Solution for AP EAMCET Mock Test - 1 - Question 28
Required area =

= 2(sinx)x/20= 2(1 - 0)

= 2sq. Units

AP EAMCET Mock Test - 1 - Question 29

∫logx[log(ex)]-2 dx = ?

Detailed Solution for AP EAMCET Mock Test - 1 - Question 29

Let I = ∫logx[log(ex)]-2 dx

Put logx = t ⇒ x = ef

⇒ dx = efdt

= (ef/1+t) + C

= (x/1+logx)+C

AP EAMCET Mock Test - 1 - Question 30

If f(x) is continuous at x = 3, where

f(x) = ax +1, for x 3

= bx + 3, for x > 3 then

Detailed Solution for AP EAMCET Mock Test - 1 - Question 30

⇒ a - b = 2/3

View more questions
10 tests
Information about AP EAMCET Mock Test - 1 Page
In this test you can find the Exam questions for AP EAMCET Mock Test - 1 solved & explained in the simplest way possible. Besides giving Questions and answers for AP EAMCET Mock Test - 1, EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

Download as PDF

Top Courses for JEE