TS EAMCET Mock Test - 9 - JEE MCQ

From the figure,

T₁ cos30° = T₂ cos30°
∴ T₁ = T₂ = T (Let)
Again, T₁ sin 30° + T₂ sin 30° = 10
2T sin 30° = 10
2T × 1/2 = 10
T = 10 N
∴ Tension in section BC and BF are 10 N and 10 N.

Potential gradient of the potentiometer wire is
 V/cm
Emf of the cell is
, l = 30 cm

Let frequency of second fork =x
We know that beat frequency =|f₁ − f₂|

On loading the fork with wax, its frequency decreases. So beat frequency will increase if,x=335 Hz and decrease if, x=347 Hz. According to the given condition, beat frequency decreases, so x=347 Hz

Velocity and displacement of block will be different from both the observers. But the force of friction observed by both the observes will be same. That is why acceleration of the block will be same.

Here,
P₁ − P₂ is the pressure difference between points A and B,
v₁ is the velocity of the fluid at point A,  
v₂ is the velocity of the fluid at point B and
h₂ − h₁ is the height difference between them.

The sum of energy per unit volume due to pressure (Pressure energy), energy per unit volume due to motion(Kinetic energy) and energy per unit volume due to gravity(Gravitational potential energy) remains constant, i.e., energy per unit volume remains constant, or we can say that in Bernoulli's theorem the energy remains conserved.

Sorption is the common term used for both absorption and adsorption. Absorption is the incorporation of a substance in one state into another of a different state (e.g., liquids being absorbed by a solid or gases being absorbed by water). Adsorption is the physical adherence or bonding of ions and molecules onto the surface of another molecule. The term 'sorption' is preferred when it is suspected that both processes are operative.

Since the complex and irrational roots occure in pairs, therefore, if one root is 2 + √3 + i , then the other roots are

f(x) = [x] - x
= x - {x} - x
= -{x}
Range of {x} = [0, 1)
Range of -{x} = (-1, 0]

∴ Required equation is

Let, S=x²+y²−5x+8y+6=0   ...(1) and points A(4, 2) and B(k, −3)

⇒  If A and B are conjugate points w.r.t equation (1) then,

|x| + |y| = 1
Area enclosed = 4 × (1/2) x 1 x 1 = 2

Let E₁, E₂ and A be the events defined as follows
E₁ = six occurs
E₂= six does not occurs
A = the man reports that it is a six. We have.

Now, P(A/E₁)= Probability that the man reports that there is a six on the die given then 6 has occured on die
= Probability the man speaks truth

=3/4

P(A/E₂) = Probability that the man reports that there is six is on die given that six has not occured on die
= Probability that the man does not speak truth

We have to find P(E₁/A) i.e. the probability that there is six on the die given that the man has reported that there is six. By Baye's rule, we have

So the possible numbers of n(A Δ B) are

10,12,14,16 ....... 40
 ⇒ 16 numbers