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MET Mock Test - 1 - JEE MCQ


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30 Questions MCQ Test MET Mock Test Series - MET Mock Test - 1

MET Mock Test - 1 for JEE 2024 is part of MET Mock Test Series preparation. The MET Mock Test - 1 questions and answers have been prepared according to the JEE exam syllabus.The MET Mock Test - 1 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MET Mock Test - 1 below.
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MET Mock Test - 1 - Question 1

If the source of light used in a Young's double slit experiment is changed from red to violet,

Detailed Solution for MET Mock Test - 1 - Question 1

where, D=distance between slit and screen,
d = distance of separation between the slits.
λ = wavelength of light used.
Let λR = wavelength of red light
and λ= wavelength of violet light.

We know, 
λR > λV
So, if we use violet light, fringe width decrease and fringes will come close to each other.

MET Mock Test - 1 - Question 2

The second overtone of an open pipe A and a closed pipe B have the same frequencies at a given temperature. Both the pipes contain air. The ratio of fundamental frequency of A to that of B is,

Detailed Solution for MET Mock Test - 1 - Question 2

Let, v be the velocity of a wave.
Length of open pipe A be l1.
 Length of closed pipe B be l2.

Formula used:

nth overtone of an open pipe f= (n+1)f0, where for open pipe fundamental frequency f= v/2l
nth overtone of a closed pipe fn = (2n+1)f0, where for closed pipe fundamental frequency f= v/4l.

Now, solving the problem


Since, it is given that frequencies are same,

Now, the ratio of fundamental frequencies,

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MET Mock Test - 1 - Question 3

A body in laboratory takes 4 minutes to cool from 61℃ to 59℃. If the laboratory temperature is 30℃, then the time taken by it to cool from 51℃  to 49℃ is

Detailed Solution for MET Mock Test - 1 - Question 3

According to Newton's law of cooling,

By newton's law of cooling,

On calculating,

MET Mock Test - 1 - Question 4

In Bernoulli's theorem, which of the following is conserved?

Detailed Solution for MET Mock Test - 1 - Question 4

Here,
P− P2 is the pressure difference between points A and B,
v1 is the velocity of the fluid at point A,  
vis the velocity of the fluid at point B and
h− h1 is the height difference between them.

The sum of energy per unit volume due to pressure (Pressure energy), energy per unit volume due to motion(Kinetic energy) and energy per unit volume due to gravity(Gravitational potential energy) remains constant, i.e., energy per unit volume remains constant, or we can say that in Bernoulli's theorem the energy remains conserved.

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MET Mock Test - 1 - Question 5

The new white belt of a long horizontal conveyor is moving with a constant speed v = 3.0 m/s. A small block of carbon is placed on the belt with zero initial velocity relative to the ground. The block will slip a bit before moving with the belt, leaving a black mark on the belt (figure). How long is that mark (in m) if the coefficient of kinetic friction between the carbon block and the belt is 0.20 and the coefficient of static friction is 0.30?


Detailed Solution for MET Mock Test - 1 - Question 5

02 = v2 – 2µkgSrel

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MET Mock Test - 1 - Question 6

In Y.D.S.E. using light of wavelength 6000Å angular fringe width of fringe formed on the screen is 1°. Find the distance between the slits :-


Detailed Solution for MET Mock Test - 1 - Question 6

MET Mock Test - 1 - Question 7

Amongst the following, the major product of the given chemical reaction is

Detailed Solution for MET Mock Test - 1 - Question 7

MET Mock Test - 1 - Question 8


Major product P of above reaction is:

Detailed Solution for MET Mock Test - 1 - Question 8

MET Mock Test - 1 - Question 9

Which of the following statements are correct?
(A) Both LiCl and MgCl2 are soluble in ethanol.
(B) The oxides Li2O and MgO combine with excess of oxygen to give superoxide.
(C) LiF is less soluble in water than other alkali metal fluorides.
(D) Li2O is more soluble in water than other alkali metal oxides.
Choose the most appropriate answer from the options given below:

Detailed Solution for MET Mock Test - 1 - Question 9

(A) Both LiCl and MgCl2 are covalent in nature due to high polarising power of Li+ and Mg+2 ions. Hence, they are soluble in ethanol.
(A) Oxides of Li2O and MgO do not form superoxide.
(B) LiF is least soluble among all other alkali metal fluorides due to high lattice energy of LiF.
(C) Li2O is least soluble among all other alkali metal oxides.
Hence, statements (A) and (C) are correct.

MET Mock Test - 1 - Question 10

The conversion of propan-1-ol to n-butylamine involves the sequential addition of reagents. The correct sequential order of reagents is

Detailed Solution for MET Mock Test - 1 - Question 10

MET Mock Test - 1 - Question 11

For the Balmer series in the spectrum of H atom,  the correct statements among (l) to (IV) are:
(I) As wavelength decreases, the lines in the series converge.
(II) The integer n1 is equal to 2.
(III) The lines of longest wavelength correspond to n2 = 3.
(IV) The ionisation energy of hydrogen can be calculated from wave number of these lines.

Detailed Solution for MET Mock Test - 1 - Question 11

In the Balmer series of H-atom, electronic transitions take place from higher orbits to 2nd orbit, and the longest wavelength will correspond to the transition from 3rd orbit to 2nd orbit.
∴ n1 = 2 and n2 = 3 for longest wavelength.
As wavelength decreases, the lines in the Balmer series converge. The correct statements are (I), (II) and (III).
The ionisation energy of hydrogen can be calculated from wave number of the last line of the Lyman series:
n1 = 1 and n2 = ∞
Hence, statement IV is incorrect.

MET Mock Test - 1 - Question 12

The number of bridged oxygen atoms present in compound B formed from the following reactions is

Detailed Solution for MET Mock Test - 1 - Question 12


Hence, no bridged oxygen atom is present in N2O4.

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MET Mock Test - 1 - Question 13

Sum of number of ions in aqueous solution of CrCl3.5NH3 and CrCl3 . 4NH3.


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MET Mock Test - 1 - Question 14

 

Find the planner species out of the following species
SF2, SF4, SF6 , SO2, SO3


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MET Mock Test - 1 - Question 15


if ‘x’ is total number of benzene ring in compound(C) and ‘y’ is the total number of degree of unsaturation in compound (D) then the value of (x + y) is


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MET Mock Test - 1 - Question 16

Identify total number of compound (s) which are unstable at room temperature ?


MET Mock Test - 1 - Question 17

If one of the roots of the quadratic question x2 − x = k be square of the other, then k =

Detailed Solution for MET Mock Test - 1 - Question 17

Let the roots be a, a2

Also a ⋅ a2 = −k ⇒ k = −a3 = 2 ± √5

MET Mock Test - 1 - Question 18

If n = 1 ⋅ 2 ⋅ 3 ....m (m is a fixed positive integer > 2), then   is equal to

Detailed Solution for MET Mock Test - 1 - Question 18

MET Mock Test - 1 - Question 19

The line y = mx intersects the circle x2 + y2 − 2x − 2y = 0 and x2 + y2 + 6x − 8y = 0 at points A and B (points being other than origin). The range of m such that origin divides AB internally is

Detailed Solution for MET Mock Test - 1 - Question 19

   

Let C1: (x − 1)2 + (y − 1)2 = 2

C2: (x + 3)2 + (y − 4)2 = 52
Both the circle pass through the origin.

Hence, tangents at the origin (using T = 0) to C1 and C2 are x + y = 0 and 3x − 4y = 0, respectively.

The slope of the tangents are −1 and 3/4 respectively.

Thus, if  −1 < m < 3/4, then origin divides AB internally.

MET Mock Test - 1 - Question 20

Detailed Solution for MET Mock Test - 1 - Question 20

Since, we know that cos2θ + sin2θ = 1

Put cosx = t, −sinx dx = dtcos,

MET Mock Test - 1 - Question 21

 

The area bounded by the region inside the ellipse, x2 + 2y2 = 2 and outside the graph of the function y = f(x), if the function f: R → Rsatisfies the relation x2f(x) + f(1−x) = 2x − x4

Detailed Solution for MET Mock Test - 1 - Question 21

Let f(x) = ax2 + bx + c, substitute in the given condition and obtain the function f(x) = 1 − x2.

MET Mock Test - 1 - Question 22

The orthocentre of triangle formed by lines 4x − 7y + 10 = 0, x + y = 54 and 7x + 4y = 15 is

Detailed Solution for MET Mock Test - 1 - Question 22

Since sides 4x − 7y + 10 = 0 and 7x + 4y − 15 = 0 are perpendicular, hence triangle is a right angle triangle.
Therefore, point of intersection of 7x + 4y − 15 = 0 and 4x − 7y + 10 = 0 which is (1, 2) represent the ortho-center.

MET Mock Test - 1 - Question 23

 then Re(p) equals -

Detailed Solution for MET Mock Test - 1 - Question 23

We have,

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MET Mock Test - 1 - Question 24

Let    then the value of a + b is: 


Detailed Solution for MET Mock Test - 1 - Question 24

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MET Mock Test - 1 - Question 25

Let f(x) = [2x3 – 5]; then number of points in (1, 2) where the function is discontinuous are where [.] → G.I.F.


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MET Mock Test - 1 - Question 26

The equation of the perpendicular bisectors of the sides AB and AC of a triangle ABC are y = x and y = –x, respectively. If the point A is (1, 2), then the area of ΔABC is :-


MET Mock Test - 1 - Question 27

Every sentence (given below) is divided into three section marked A, B and C. Read the sentence carefully and mark the section that contains an error. If there is no error in the sentence, mark (D).

Due to carelessness, (A)/he failed (B)/in the examination. (C)/No error. (D)

Detailed Solution for MET Mock Test - 1 - Question 27

(A) Write Owing to in place of Due to in section (A). Due to is generally used after the verb. It means, caused by somebody/something.
The correct sentence will be :
"Owing to carelessness he failed in the examination."
However, modern grammarians do not object to using due to and owing to in the same sense.

MET Mock Test - 1 - Question 28

If a meaningful word can be formed from APSG, by using each letter only once, then the third letter of that word is your answer. If more than one such word can be formed, your answer is 'Y' and if no such word is formed then answer is 'Z'.

Detailed Solution for MET Mock Test - 1 - Question 28

We can form two words from the given letters: "GAPS" and "GASP". Hence, the answer is Y.

MET Mock Test - 1 - Question 29

Choose the correct option to fill in the blank in the following sentence:
The soldiers wanted to _____ over their victory.

Detailed Solution for MET Mock Test - 1 - Question 29

There is a difference between Exalt and Exult.
Exalt- To exalt means to glorify or to elevate something.
Exult- To exult means to feel or show triumphant elation or jubilation.
Hence, the correct answer is “The soldiers wanted to exult their victory in the battle”.

MET Mock Test - 1 - Question 30

Three persons A, B and C wore shirts of black, blue and orange colours (not necessarily in that order) and pants of green, yellow and orange colour (not necessarily in that order). No person wore a shirt and pant of the same colour. Further, it is given that

1. A did not wear shirt of black colour.

2. B did not wear shirt of blue colour.

3. C did not wear shirt of orange colour.

4. A did not wear pant of green colour.

5. B wore pant of orange colour.

What were the colours of the pant and shirt worn by C respectively?

Detailed Solution for MET Mock Test - 1 - Question 30

From the information given in the question, we can say that B wore pant of orange colour. A did not wear pants of green colour. So, A wear yellow pant and C wear green pant.

B did not wear the shirt of blue colour and orange colour. So, B wears a black shirt.

C did not wear a shirt of orange colour. So, C wears a blue shirt and A wears an orange shirt.

Let's draw a matching table according to the given statements-

Hence, we can conclude that C wears a Blue shirt and Green pants.

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