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Test: Classless Addressing - Computer Science Engineering (CSE) MCQ


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10 Questions MCQ Test Computer Networks - Test: Classless Addressing

Test: Classless Addressing for Computer Science Engineering (CSE) 2024 is part of Computer Networks preparation. The Test: Classless Addressing questions and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus.The Test: Classless Addressing MCQs are made for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Classless Addressing below.
Solutions of Test: Classless Addressing questions in English are available as part of our Computer Networks for Computer Science Engineering (CSE) & Test: Classless Addressing solutions in Hindi for Computer Networks course. Download more important topics, notes, lectures and mock test series for Computer Science Engineering (CSE) Exam by signing up for free. Attempt Test: Classless Addressing | 10 questions in 30 minutes | Mock test for Computer Science Engineering (CSE) preparation | Free important questions MCQ to study Computer Networks for Computer Science Engineering (CSE) Exam | Download free PDF with solutions
Test: Classless Addressing - Question 1

If the first address is First address = 18.14.12.0/22. What is the last address?

Detailed Solution for Test: Classless Addressing - Question 1

Last address = (any address) OR [NOT (network mask)].
The Last Address = 18.14.15.255/22.

Test: Classless Addressing - Question 2

An ISP has requested a block of 1000 addresses. What is its prefix length?

Detailed Solution for Test: Classless Addressing - Question 2

n =32- log_2 (1024) = 22.

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Test: Classless Addressing - Question 3

A classless address is given as 167.199.170.82/27. Find the last address.

Detailed Solution for Test: Classless Addressing - Question 3

Last address = (any address) OR [NOT (network mask)].

Test: Classless Addressing - Question 4

A classless address is given as 167.199.170.82/27. Find the number of addresses.

Detailed Solution for Test: Classless Addressing - Question 4

n =27
Therefore number of addresses is 2(32-n) = 32.

Test: Classless Addressing - Question 5

The slash notation in classless addressing is referred to as –

Detailed Solution for Test: Classless Addressing - Question 5

It is referred to as CIDR.

Test: Classless Addressing - Question 6

The value ‘n’ in classless addressing is referred to as –

Detailed Solution for Test: Classless Addressing - Question 6

‘n’ is referred to as prefix length.

Test: Classless Addressing - Question 7

Classless Addressing overcomes the problem of –

Detailed Solution for Test: Classless Addressing - Question 7

Classless Addressing overcomes the problem of address depletion.

Test: Classless Addressing - Question 8

An ISP has requested a block of 1000 addresses. Can 18.14.12.0 be its first address?

Detailed Solution for Test: Classless Addressing - Question 8

18.14.12.0 is divisible by 1024 hence it can be taken as first address.

Test: Classless Addressing - Question 9

An ISP has requested a block of 1000 addresses. How many blocks are granted to it?

Detailed Solution for Test: Classless Addressing - Question 9

The number of blocks allotted can only be in the powers of 2.

Test: Classless Addressing - Question 10

A classless address is given as 167.199.170.82/27. Find the first address.

Detailed Solution for Test: Classless Addressing - Question 10

First address = (any address) AND (network mask).

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