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Which of the following should be done in order to convert a continuoustime signal to a discretetime signal?
Explanation: The process of converting a continuoustime signal into a discretetime signal by taking samples of continuous time signal at discrete time instants is known as ‘sampling’.
The process of converting discretetime continuous valued signal into discretetime discrete valued(digital) signal is known as:
Explanation: In this process, the value of each signal sample is represented by a value selected from a finite set of possible values. Hence this process is known as ‘quantization’
The difference between the unquantized x(n) and quantized xq(n) is known as:
Explanation: Quantization error is the difference in the signal obtained after sampling i.e., x(n) and the signal obtained after quantization i.e., xq(n) at any instant of time.
Which of the following is a digitaltoanalog conversion process?
Explanation: The process of joining in terms of steps is known as staircase approximation, connecting two samples by a straight line is known as Linear interpolation, connecting three samples by fitting a quadratic curve is called as Quadratic interpolation.
The relation between analog frequency ‘F’ and digital frequency ‘f’ is:
Explanation: Consider an analog signal of frequency ‘F’, which when sampled periodically at a rate Fs=1/T samples per second yields a frequency of f=F/Fs=>f=F*T.
What is output signal when a signal x(t)=cos(2*pi*40*t) is sampled with a sampling frequency of 20Hz?
Explanation: From the question F=40Hz, Fs=20Hz
=>f=F/Fs
=>f=40/20
=>f=2Hz
=>x(n)=cos(4*pi*n).
If ‘F’ is the frequency of the analog signal, then what is the minimum sampling rate required to avoid aliasing?
Explanation: According to Nyquist rate, to avoid aliasing the sampling frequency should be equal to twice of the analog frequency.
What is the nyquist rate of the signal x(t)=3cos(50*pi*t)+10sin(300*pi*t)cos(100*pi*t)?
Explanation: The frequencies present in the given signal are F1=25Hz, F2=150Hz, F3=50Hz
Thus Fmax=150Hz and from the sampling theorem,
nyquist rate=2*Fmax
Therefore, Fs=2*150=300Hz.
If the sampling rate Fs satisfies the sampling theorem, then the relation between quantization errors of analog signal(eq(t)) and discretetime signal(eq(n)) is:
Explanation: If it obeys sampling theorem, then the only error in A/D conversion is quantization error. So, the error is same for both analog and discretetime signal.
The quality of output signal from a A/D converter is measured in terms of:
Explanation: The quality is measured by taking the ratio of noises of input signal and the quantized signal i.e., SQNR and is measured in terms of dB.
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