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# Test: Performance of a System

## 15 Questions MCQ Test Computer Architecture & Organisation (CAO) | Test: Performance of a System

Description
This mock test of Test: Performance of a System for Computer Science Engineering (CSE) helps you for every Computer Science Engineering (CSE) entrance exam. This contains 15 Multiple Choice Questions for Computer Science Engineering (CSE) Test: Performance of a System (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Performance of a System quiz give you a good mix of easy questions and tough questions. Computer Science Engineering (CSE) students definitely take this Test: Performance of a System exercise for a better result in the exam. You can find other Test: Performance of a System extra questions, long questions & short questions for Computer Science Engineering (CSE) on EduRev as well by searching above.
QUESTION: 1

Solution:
QUESTION: 2

### Two processors A and B have clock frequencies of 700 Mhz and 900 Mhz respectively. Suppose A can execute an instruction with an average of 3 steps and B can execute with an average of 5 steps. For the execution of the same instruction which processor is faster ?

Solution:

Explanation: The performance of a system can be found out using the Basic performance formula.

QUESTION: 3

### A processor performing fetch or decoding of different instruction during the execution of another instruction is called ______

Solution:

Explanation: Pipe-lining is the process of improving the performance of the system by processing different instructions at the same time, with only one instruction performing one specific operation.

QUESTION: 4

For a given FINITE number of instructions to be executed, which architecture of the processor provides for a faster execution ?

Solution:

Explanation: In super-scalar architecture, the instructions are set in groups and they’re decoded and executed together reducing the amount of time required to process them.

QUESTION: 5

The clock rate of the processor can be improved by _________

Solution:

Explanation: The clock rate(frequency of the processor) is the hardware dependent quantity it is fixed for a given processor.

QUESTION: 6

An optimizing Compiler does _________

Solution:

Explanation: An optimizing compiler is a compiler designed for the specific purpose of increasing the operation speed of the processor by reducing the time taken to compile the program instructions.

QUESTION: 7

The ultimate goal of a compiler is to ________

Solution:
QUESTION: 8

SPEC stands for _______

Solution:

Explanation: SPEC is a corporation started to standardize the evaluation method of a systems performance.

QUESTION: 9

As of 2000, the reference system to find the performance of a system is _____

Solution:

Explanation: In SPEC system of measuring a systems performance, a system is used as a reference against which other systems are compared and performance is determined.

QUESTION: 10

When Performing a looping operation, the instruction gets stored in the ______

Solution:

Explanation: When a looping or branching operation is carried out the offset value is stored in the cache along with the data

QUESTION: 11

If a processor clock is rated as 1250 million cycles per second, then its clock period is ________

Solution:
QUESTION: 12

The average number of steps taken to execute the set of instructions can be made to be less than one by following _______

Solution:

Explanation: The number of steps required to execute a given set of instructions is sufficiently reduced by using super-scaling. In this method a set of instructions are grouped together and are processed.

QUESTION: 13

CISC stands for _______

Solution:

Explanation: CISC is a type of system architecture where complex instructions are grouped together and executed to improve the system performance.

QUESTION: 14

As of 2000, the reference system to find the SPEC rating are built with _____ Processor.

Solution:
QUESTION: 15

If the instruction, Add R1, R2, R3 is executed in a system which is pipe-lined, then the value of S is (Where S is term of the Basic performance equation)

Solution: