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Practice Test - NEET MCQ


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30 Questions MCQ Test 4 Months Preparation for NEET - Practice Test

Practice Test for NEET 2024 is part of 4 Months Preparation for NEET preparation. The Practice Test questions and answers have been prepared according to the NEET exam syllabus.The Practice Test MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Practice Test below.
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Practice Test - Question 1

Which one of the following is not an example of projectile?

Detailed Solution for Practice Test - Question 1

Projectile motion is a natural phenomenon it is due to the gravity in earth surface .it doesn't need any external force .The flight seems to be same as an projectile motion but it differs as an external force is applied which is the aircraft engine which pulls the craft forward and hence oppose the force of gravity.

Practice Test - Question 2

A battle ship simultaneously fires two shells at enemy ships. Both are fired with the same speed but with different directions as shown. If the shells follow the parabolic trajectories shown, which ship gets hit first?

Detailed Solution for Practice Test - Question 2

Ship 2 gets hit first. The time of flight only depends on the y-component of motion, not the x-component.  The higher you throw something up in the air, the more time it spends in the air.  It can also be shown from equation-

y=v0y t – ½ g t2=0  

    v0y for projectile μ1 is greater than for μ2.

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Practice Test - Question 3

 How many directions are possible for the same horizontal range?

Detailed Solution for Practice Test - Question 3

We know that the horizontal range for any projectile motion let say R = 2u2.sin 2a /g
Where u is initial speed, and a is the angle at which the particle is thrown, which is responsible for direction. So in between the possible range of a that is 0 - 90, there are maximum two equal values of sin 2a, thus the maximum number of directions for the same or equal range are 2.

Practice Test - Question 4

Give the magnitude and direction of the net force acting on a stone of mass 0.1 kg lying on the floor of a train which is moving with 1 ms−2 accleration , the stone being at rest relative to the train. Neglect air resistance.

Detailed Solution for Practice Test - Question 4

Key points:

  • The stone has a mass of 0.1 kg.
  • The train is moving at a constant velocity (1 m/s).
  • The stone is at rest relative to the train.
  • We are neglecting air resistance.

Since the stone is at rest relative to the train and the train is moving with a constant accleration, the net force acting on mass .
F= ma 
F =0.1 x 1 N
F = 0.1 N

Practice Test - Question 5

Force is required

Detailed Solution for Practice Test - Question 5
  • Force is required to start a stationary object and to stop a moving object due to inertia. 
  • Inertia is a property of matter by which it continues in its existing state of rest or uniform motion in a straight line, unless that state is changed by an external force.
  • This is also called law of inertia or newton's first law of motion.
  • Newton's first Law:
Practice Test - Question 6

Which of the following is true for a steady flow system?

Detailed Solution for Practice Test - Question 6

The amount of mass or energy entering a control volume does not have to be equal to the amount of mass or energy leaving during an unsteady-flow process.It is mostly converted to internal energy as shown by a rise in the fluid temperature.

Practice Test - Question 7

One kg of carbon produces __________ kg of carbon dioxide.

Detailed Solution for Practice Test - Question 7

2CO + O2 ------------> 2CO2
Atomic wt of C =12 kg or gms, Atomic wt of O = 16 kg or gms
2(12 + 16) kg of CO + 32 kg of O2 -----------> 2(12+32) kg of CO2
56 kg of CO + 32 kg of O2 -------> 88 kg of CO2
For, 1kg of CO + 32/56 kg of O2 ---------> 88/56 kg of CO2
Therefore, 1kg of CO requires 32/56 or 4/7 kg of oxygen to produce 88/56kg or 11/7 kg of CO2

Practice Test - Question 8

A gas absorbs 200 J of heat and expands by 500 cm3 against a constant pressure of 2 x 105 Nm-2. Change in internal energy is 

Detailed Solution for Practice Test - Question 8

The expression for the change in internal energy is given by,
ΔU=q+w
q = heat absorbed = 200 J
w = work done = −P x V
=−2×10⁵ × 500×10−6
= −100 N - m
ΔU=200−100J= 100 J
Hence, the correct option is C.

Practice Test - Question 9

Direction (Q. Nos. 1-15) This section contains 15 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

Q. Which of the following is least likely to behave as Lewis base?

Detailed Solution for Practice Test - Question 9

Electron rich species are called lewis base. Among the given, BF3 is an electron deficient species, so have a capacity of electrons accepting instead of donating that's why it is least likely to act as a lewis base. It is a lewis acid. 

Practice Test - Question 10

Which of the following is not acid-base conjugate pair?

Detailed Solution for Practice Test - Question 10

Acid ⇋ Conjugate Base  +  H+
By this definition,
HNO2 ⇋ NO2- + H+
CH3NH3+ ⇋ CH3NH2 + H+
C6H5COOH ⇋ C6H5COO- + H+
H3O+ ⇋ H2O + H+
We can see that the conjugate base of H3O+ is H2O. But it is given that OH- is the C.B. So option d is incorrect.

Practice Test - Question 11

Which one of the following molecular hydrides acts as a Lewis acid?

Detailed Solution for Practice Test - Question 11

B2H6 is an electron deficient species. Soit will act as Lewis acid.

Practice Test - Question 12

The species present in solution when CO2 dissolved in water, are

[IIT JEE 2006]

Detailed Solution for Practice Test - Question 12

H2CO3 is formed by dissolution of CO2 into water. This dissociates into H+ and HCO3-. This is the first dissociation of H2CO3. Since HCO3- has another H, it again dissociates to H+ and CO32-. H+ obtained attacks the lone pair of H2O to form H3O+. So H3O+, HCO3-, CO32-, H2CO3 are present in water when CO2 is dissolved in  water.

Practice Test - Question 13

The part of the fruit that develops from the ovary wall is called__________.

Detailed Solution for Practice Test - Question 13

The pericarp is the part of the fruit that develops from the ovary wall. After fertilization, the ovary undergoes changes and develops into a mature fruit. The pericarp consists of three layers: the exocarp, mesocarp, and endocarp.
So the correct answer is A

Practice Test - Question 14

A scar on the seed coat through which the developing seeds attached to the fruit is called as ________.

Detailed Solution for Practice Test - Question 14

The outer layer is called testa and the inner layer is called tegmen. There is a scar on the seed coat through which the developing seed was attached to the fruit. This scar is called hilum.
So the correct answer is C

Practice Test - Question 15

A Flower which can be divided into equal vertical halves by more than one plane of division is__________.

Detailed Solution for Practice Test - Question 15

Actinomorphic flowers are radially symmetrical, they are able to be divided into similar halves in more than one vertical plane.
Zygomorphic flowers are bilaterally symmetrical,they can be divided into similar halves in only one plane.
Cyclic is a type of floral organ arrangement, the floral organs are arranged in regular whorls at the node of the thalamus.
Heteromorphic is a type of incompatibilty, same species produce more than one morphological type of flower.
So the correct answer is C

Practice Test - Question 16

Flowers in which only one set of essential organs is present are said to be__________.

Detailed Solution for Practice Test - Question 16

POLYGAMY ⇒ The condition of bearing some flowers with stamens only, some with pistils only, and some with both, on the same or different plants. 

BISEXUAL ⇒ The flower having both male and female reproductive organ on the same plant. 

DIOECIOUS ⇒ Both male and female plants may have flowers, but one will have "male" flowers and the other "female" flowers.

UNISEXTUAL ⇒ The flower which has only one essential worl either male or female.
So the answer is D

Practice Test - Question 17

Another name for multicostate venation is________.

Detailed Solution for Practice Test - Question 17

In palmately reticulate venation there is more number of main veins arising from the base of the leaf. So it is otherwise called as multicostate type. Palmately reticulate or multicostate venation is again divided into two they are:

(i) Palmately reticulate (Divergent)

(ii) Pinnately reticulate (Convergent).
So the correct answer is C

Practice Test - Question 18

Which of the following represents the floral characters of Liliaceae?

Detailed Solution for Practice Test - Question 18

Liliaceae is the characteristics representative of monocotyledonous plants. Floral characters of this family are: tricarpellary, actinomorphic, polyandrous, superior ovary, axile placentation.
So the correct answer is D

Practice Test - Question 19

Aerating pores in the bark of plants is known as

Detailed Solution for Practice Test - Question 19

In plants respiratory organs in stem is called lenticels. They are located as pores in the bark of plants.

Practice Test - Question 20

Separate xylem and phloem bundles are known as

Detailed Solution for Practice Test - Question 20

Separate xylem and phloem bundles are found in dicotyledonous roots. This kind of vascular bundle is called radial vascular bundle.

Practice Test - Question 21

The secondary growth of woody angiosperm stem occurs by

Detailed Solution for Practice Test - Question 21

The tissues involved in secondary growth are the two lateral meristems namely, vascular cambium and cork cambium.

Practice Test - Question 22

Conjoint type of vascular bundles are common in

Detailed Solution for Practice Test - Question 22

In conjoint type of vascular bundles,the xylem and phloem are situated at the sameradius of vascular bundles. Such vascularbundles are common in stems and leaves. Theconjoint vascular bundles usually have thephloem located only on the outer side of xylem.

Practice Test - Question 23

Which part of epidermis of leaf contains more stomata?

Detailed Solution for Practice Test - Question 23

The abaxial epidermis generally bears more stomata than the adaxial epidermis.

Practice Test - Question 24

Quiescentcentre is found in the plant at

Detailed Solution for Practice Test - Question 24

Quiescent centre is a small group of cells with low mitotic activity. It is found at the tips of growing roots in the root meristem.

Practice Test - Question 25

The wood is actually a

Detailed Solution for Practice Test - Question 25

The wood is actually a secondary xylem. There are different types of wood on the basis of their composition and time of production.

Practice Test - Question 26

Which one is not a xylem cell?

Detailed Solution for Practice Test - Question 26

Xylem is a complex tissue, which consists of four kinds of cells. These cells are tracheid, vessels, xylem parenchyma and xylem fibers. Companion cell is part of phloem tissue.

Practice Test - Question 27

What is the primary respiratory organ used by frogs when they are in water?

Detailed Solution for Practice Test - Question 27

Frogs use their skin for cutaneous respiration when they are in water, absorbing oxygen directly from the dissolved oxygen in the water through their moist skin.

Practice Test - Question 28

Which of the following is NOT a characteristic feature of frog's morphology?

Detailed Solution for Practice Test - Question 28

Frogs do not have a tail; they have a head and trunk directly connected, without a distinct neck or tail.

 

Practice Test - Question 29

Where does digestion primarily occur in frogs?

Detailed Solution for Practice Test - Question 29

Digestion in frogs primarily occurs in the intestine, where final digestion and absorption of nutrients take place after initial processing in the stomach.

 

Practice Test - Question 30

Which of these describes the skin of frog?

Detailed Solution for Practice Test - Question 30

The skin of a frog is smooth and slippery due to the presence of mucus. The skin has a moist characteristic which is maintained. A frog does not drink water but has the ability to absorb water through its skin.

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