MCQ Test: Puzzles based on comparison - 1 - Bank Exams MCQ

Sanya is the youngest.
From the given information, we can derive:

• Comparing Aarti, Sanya and Muskan:
• From point (i) and (iv), we know that Aarti is older than Sanya and Muskan is older than Sanya.
• From point (ii), we can also see that Muskan is older than Aarti.

Thus, the order here is Muskan > Aarti > Sanya.

• Comparing Kashish, Sanya and Muskan:
• From point (iii) and (iv), we know that Kashish is older than Sanya, and Muskan is also older than Sanya.
• From point (ii), we know that Kashish is older than Muskan.

Thus, the order here is Kashish > Muskan > Sanya.

Introduction of Gargi:

• From point (v), we know that Gargi is the eldest of all.
• Thus, including Gargi, the order becomes Gargi > Kashish > Muskan > Aarti > Sanya.

From the above deductions, it is clear that Sanya is the youngest among all. So, the answer is D. Sanya.

Agewise, Muskan is in the middle.
To find out who is in the middle age-wise, we need to arrange the individuals based on the information provided. Let's go step by step:

• Step 1: From statement (v), we know that Gargi is the eldest.
• Step 2: From statement (ii), we know that Muskan is elder than Aarti but younger than Kashish. So, Kashish is younger than Gargi but older than Muskan.
• Step 3: Statement (i) tells us that Aarti is older than Sanya. Since Aarti is younger than Muskan (from step 2), Sanya is the youngest of all.
• Step 4: Now, considering the age of Aarti, she is younger than Muskan but older than Sanya.

So the age order from eldest to youngest is: Gargi, Kashish, Muskan, Aarti, Sanya.
Therefore, Muskan is in the middle age-wise. So, the answer is C: Muskan.

From (i) and (ii), we have : K > M > A > S.
This indicates both K > S and S < M which are given in (iii) and (iv).
Thus, both (iii) and (iv) are superfluous.

We have : E > A > B, A < D < B.
Since C is the tallest,
so we have : E < A < D < B < C.
Clearly, D lies in the middle.

D is not as tall as A = D is shorter than A = D < A D is not as short as C = D is taller than C = D > C. B is shorter than D but taller than C = C < B < D.
Thus, we have : C < B < D < A.
So, A is the tallest.

Following the final solution, and applying the given conditions, we have:

Here, we can say that Rank of Niya is 1.
Hence, the correct answer is option D.
Final Solution:
Order of Ranks:
Jiya > Piya > Riya
Possibilities of 1st and 7th rank:
Possibility 1:
Rank 1 = Shreya
Rank 7 = Diya
Possibility 2:
Rank 1 = Niya
Rank 7 = either Miya or Riya
We will keep this information in mind and solve the questions accordingly.
Common Explanation:
Reference:
Piya teacher made an observation on the basis of the ranks of seven students – Piya, Riya, Shreya, Niya, Diya, Miya and Jiya, in the previous exams taken by them.
Inference:
We will keep this information in mind while solving the puzzle.
Reference:
Jiya always performs better than Piya.
Piya always performs better than Riya.
Inference:
After using the above references we have:
Order of Ranks:
Jiya > Piya > Riya
Reference:
Each time either Shreya tops the class and Diya gets the last rank, or alternatively Niya tops the class and either Miya or Riya gets the last rank.
Inference:
After using the above references we have:
Possibilities of 1st and 7th rank:
Possibility 1:
Rank 1 = Shreya
Rank 7 = Diya
Possibility 2:
Rank 1 = Niya
Rank 7 = either Miya or Riya

Following the final solution, and applying the given conditions, we have:

Here, we can say that Rank of Diya is 2.
Hence, the correct answer is option B.
Final Solution:
Order of Ranks:
Jiya > Piya > Riya
Possibilities of 1st and 7th rank:
Possibility 1:
Rank 1 = Shreya
Rank 7 = Diya
Possibility 2:
Rank 1 = Niya
Rank 7 = either Miya or Riya
We will keep this information in mind and solve the questions accordingly.
Common Explanation:
Reference:
Piya teacher made an observation on the basis of the ranks of seven students – Piya, Riya, Shreya, Niya, Diya, Miya and Jiya, in the previous exams taken by them.
Inference:
We will keep this information in mind while solving the puzzle.
Reference:
Jiya always performs better than Piya.
Piya always performs better than Riya.
Inference:
After using the above references we have:
Order of Ranks:
Jiya > Piya > Riya
Reference:
Each time either Shreya tops the class and Diya gets the last rank, or alternatively Niya tops the class and either Miya or Riya gets the last rank.
Inference:
After using the above references we have:
Possibilities of 1st and 7th rank:
Possibility 1:
Rank 1 = Shreya
Rank 7 = Diya
Possibility 2:
Rank 1 = Niya
Rank 7 = either Miya or Riya

Following the final solution, and applying the given conditions, we have:

Here, we can say that Rank of Miya is 7.
Hence, the correct answer is option D.
Final Solution:
Order of Ranks:
Jiya > Piya > Riya
Possibilities of 1st and 7th rank:
Possibility 1:
Rank 1 = Shreya
Rank 7 = Diya
Possibility 2:
Rank 1 = Niya
Rank 7 = either Miya or Riya
We will keep this information in mind and solve the questions accordingly.
Common Explanation:
Reference:
Piya teacher made an observation on the basis of the ranks of seven students – Piya, Riya, Shreya, Niya, Diya, Miya and Jiya, in the previous exams taken by them.
Inference:
We will keep this information in mind while solving the puzzle.
Reference:
Jiya always performs better than Piya.
Piya always performs better than Riya.
Inference:
After using the above references we have:
Order of Ranks:
Jiya > Piya > Riya
Reference:
Each time either Shreya tops the class and Diya gets the last rank, or alternatively Niya tops the class and either Miya or Riya gets the last rank.
Inference:
After using the above references we have:
Possibilities of 1st and 7th rank:
Possibility 1:
Rank 1 = Shreya
Rank 7 = Diya
Possibility 2:
Rank 1 = Niya
Rank 7 = either Miya or Riya

Following the final solution, and applying the given conditions, we have:

Here, we cannot find Rank of Diya.
Hence, the correct answer is option D.
Final Solution:
Order of Ranks:
Jiya > Piya > Riya
Possibilities of 1st and 7th rank:
Possibility 1:
Rank 1 = Shreya
Rank 7 = Diya
Possibility 2:
Rank 1 = Niya
Rank 7 = either Miya or Riya
We will keep this information in mind and solve the questions accordingly.
Common Explanation:
Reference:
Piya teacher made an observation on the basis of the ranks of seven students – Piya, Riya, Shreya, Niya, Diya, Miya and Jiya, in the previous exams taken by them.
Inference:
We will keep this information in mind while solving the puzzle.
Reference:
Jiya always performs better than Piya.
Piya always performs better than Riya.
Inference:
After using the above references we have:
Order of Ranks:
Jiya > Piya > Riya
Reference:
Each time either Shreya tops the class and Diya gets the last rank, or alternatively Niya tops the class and either Miya or Riya gets the last rank.
Inference:
After using the above references we have:
Possibilities of 1st and 7th rank:
Possibility 1:
Rank 1 = Shreya
Rank 7 = Diya
Possibility 2:
Rank 1 = Niya
Rank 7 = either Miya or Riya

Following the final solution, and applying the given conditions, we have:

Here, we can say that Rank of Shreya is 1st.
Hence, the correct answer is option B.
Final Solution:
Order of Ranks:
Jiya > Piya > Riya
Possibilities of 1st and 7th rank:
Possibility 1:
Rank 1 = Shreya
Rank 7 = Diya
Possibility 2:
Rank 1 = Niya
Rank 7 = either Miya or Riya
We will keep this information in mind and solve the questions accordingly.
Common Explanation:
Reference:
Piya teacher made an observation on the basis of the ranks of seven students – Piya, Riya, Shreya, Niya, Diya, Miya and Jiya, in the previous exams taken by them.
Inference:
We will keep this information in mind while solving the puzzle.
Reference:
Jiya always performs better than Piya.
Piya always performs better than Riya.
Inference:
After using the above references we have:
Order of Ranks:
Jiya > Piya > Riya
Reference:
Each time either Shreya tops the class and Diya gets the last rank, or alternatively Niya tops the class and either Miya or Riya gets the last rank.
Inference:
After using the above references we have:
Possibilities of 1st and 7th rank:
Possibility 1:
Rank 1 = Shreya
Rank 7 = Diya
Possibility 2:
Rank 1 = Niya
Rank 7 = either Miya or Riya

In terms of heights, we have: Rohan > Daksh > Manick, Daksh > Somesh > Farhan.
Thus, the whole sequence may be :
(i) Rohan > Daksh > Manick > Somesh > Farhan; or
(ii) Rohan > Daksh > Somesh > Manick > Farhan; or
(iii) Rohan > Daksh > Somesh > Farhan > Manick.
Thus, either Manick or Farhan may be the shortest.
So, the given information is insufficient.

Let the first letter of the name of each girl represent her height.
Then, Garima is taller than Sarita = G > S.
Garima is not taller than Reeta = R > G.
Reena and Tanya are of the same height = R = T.
Garima is shorter than Anu = A > G.
All the above indicate that Garima is either shorter than or equal in height to each of the girls except Sarita, while Sarita is shorter than Garima.
Thus, Sarita is the shortest.

Clearly, A is shorter than each one of C and E.
Thus, D is taller than each one of A, C, and E.
But, B is taller than D.
So, B is the tallest and D comes next.

From I and V,
we have : Y > X > L or Y > L.

Since III mentions that Z is the youngest,
it clearly indicates that each one of L, M, N and Y is older than Z.

From I, II, IV and V,
we have : M = N > Y > X > L, i.e. M > L.
Thus, L is younger than M.
So, III is not required.

From II, IV and V,
we have : M = N > Y > X, i.e. X < M.

As given, we have : Prerna > Shaloo > Rakhi; Rakhi = Meghna, Rakhi > Komal.
Thus, the sequence of heights becomes; Prerna > Shaloo > Rakhi = Meghna > Komal
Clearly, Meghna is shorter than Shaloo.

Understanding the Weights of the Articles:
From the information given, we can deduce the following:

• Article A: We know that A weights twice as much as B. However, without knowing the weight of B, we cannot determine the exact weight of A.
• Article B: B weighs four and a half times as much as C. Again, without the weight of C, we cannot determine the weight of B.
• Article C: C weighs half as much as D, which means D is twice as heavy as C.
• Article D: D weighs half as much as E, making E twice as heavy as D.
• Article E: E weighs less than A but more than C.

Determining the Lightest Article:
From the above information, we can infer that C is the lightest article. Here's why:

• C weighs half as much as D. This means C is lighter than D.
• Since D weighs half as much as E, E is heavier than both C and D.
• B weighs four and a half times as much as C. This implies B is heavier than C.
• A weighs twice as much as B. Given that B is heavier than C, A is also heavier than C.

Hence, C is the lightest among all the articles.

E is lighter in weight than A and B.
We are given several clues about the weight of the five iron articles. Let's break them down:
Weight Relationships:

• A weighs twice as much as B. So, A > B.
• B weighs four and a half times as much as C. So, B > C.
• C weighs half as much as D. So, D > C.
• D weighs half as much as E. So, E > D.
• E weighs less than A but more than C. So, A > E > C.

From these relationships, we can determine that A is the heaviest, followed by E, then B, then D, and finally C.
Question:E is lighter in weight than which of the other two articles?
From our weight relationships, we can see that E is lighter than A and B. So, the answer is A: A, B.