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# Percentage - MCQ 3

## 20 Questions MCQ Test Quantitative Aptitude for Competitive Examinations | Percentage - MCQ 3

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This mock test of Percentage - MCQ 3 for Quant helps you for every Quant entrance exam. This contains 20 Multiple Choice Questions for Quant Percentage - MCQ 3 (mcq) to study with solutions a complete question bank. The solved questions answers in this Percentage - MCQ 3 quiz give you a good mix of easy questions and tough questions. Quant students definitely take this Percentage - MCQ 3 exercise for a better result in the exam. You can find other Percentage - MCQ 3 extra questions, long questions & short questions for Quant on EduRev as well by searching above.
QUESTION: 1

### A reduction of 20% percent in the price of rice enables a housewife to buy 5 kg more for rupees 1200. The reduced price per kg of rice

Solution:

Answer – c) 48 Explanation : let original price is x rupees per kg 1200/(4x/5) – 1200/x = 5 We will get x = 60, so reduced price = (4*60)/5 = 48

QUESTION: 2

### The population of a village has increased annually at the rate of 20%. If at the end of 3 years it is 21600, the population in the beginning of the first year?

Solution:

Answer – b) 12500 Explanation : 21600 = P*(1 + 20/100)^3

QUESTION: 3

### 12 percent of the voters in an election did not cast their votes. In this election there are only two candidates. The winner by obtaining 45% of the total votes and defeated his rival by 2000 votes. The total number of votes in the election

Solution:

Answer – c) 100000 Explanation : 12% percent didn’t cast their vote. 45% of total votes get by the winning candidates, so remaining 43% will be scored by his rival. So, (45/100 -43/100)*P = 2000
P = 100000

QUESTION: 4

A number is first decreased by 25%. The decreased number is then increased by 20%. The resulting number is less than the original number by 40. Then the original number is –

Solution:

Answer – d) 400 Explanation : Let the number is a a – (75/100)*a*(120/100) = 40 we will get a = 400

QUESTION: 5

The number of seats in a cinema hall is decreased by 8% and also the price of the ticket is increased by 4 percent. What is the effect on the revenue collected?

Solution:

Answer – b) decrease 4.32% Explanation : Let initially seats are 100 and price of each seat is 100, so total initial revenue = 10000
now, seats are 92 and price of each seat = 104, so total revenue = 92*104 = 9568 so percent change in revenue = (432/10000)*100 = 4.32 decrease

QUESTION: 6

A man spends 60% of his income. His income is increased by 20% and his expenditure also increases by 10%. Find the percentage decrease in his saving?

Solution:

Answer – a) 10% Explanation : Let initially income is 100. So, expenditure = 60 and saving = 40 now income is increased by 20% i.e. 120. So, expenditure = (70/100)*120 = 84 and saving = 36 so % percent decrease in saving = (4/40)*100 = 10%

QUESTION: 7

Weights of two friends A and B are in the ratio of 1:2. A’s weight increases by 20% and the total weight of A and B together becomes 60 kg, with an increase of 30%. By what percent the weight of B increase?

Solution:

Answer – b) 35% Explanation : weight of A is x and weight of B is 2x given that 60 kg weight is the 30% percent increase of the original weight, so (130/100)*W = 60, W = 600/13 kg (W = original weight) X + 2x = 600/13, x = 200/13 So weight of A = 200/13 and of B = 400/13 (120/100)*(200/13) + [(100 + a)/100]*(400/13) = 60 Solve for a. We will get a = 35%

QUESTION: 8

The marked price of an article is 20% higher than the cost price. A discount of 20% is given on the marked price. In this transaction the seller

Solution:

Answer – b) losses 4% Explanation : let cost price = 100 so, marked price = 120 now discount of 20% is given, so sp = 120*80/100 = 96 so % loss = (4/100)*100 = 4 percent

QUESTION: 9

When the price of rice is increased by 30 percent, a family reduces its consumption such that the expenditure is only 20 percent more than before. If 50 kg of rice is consumed by family before, then find the new consumption of family (approx.)

Solution:

Answer – d) 46kg Explanation : Suppose initially price per kg of rice is 100 then their expenditure is 5000.
Now their expenditure is only increased by only 20% i.e – 6000.
Increased price of rice = 130.
So new consumption = 6000/130 = 46

QUESTION: 10

A man has 4000 rupees in his account two years ago. In the first year he deposited 20 percent of the amount in his account. In the next year he deposited 10 percent of the increased amount in the account. Find the total amount in the account of the person after 2 years.

Solution:

Answer – b) 5280 Explanation : 4000 + 800 + 480 = 5280

QUESTION: 11

In an election contested by two parties A and B, party A secured 25 percent of the total votes more than Party B. If party B gets 15000 votes. By how much votes does party B loses the election?

Solution:

Answer – b) 10000 Explanation : Let total votes = T and party B gets 15000 votes then party A will get T -15000 votes T – 15000 – 15000 = 25T/100
T = 40000, so A get 25000 and B gets 15000 votes, so difference = 10000

QUESTION: 12

A vendor sells 50 percent of apples he had and throws away 20 percent of the remainder. Next day he sells 60 percent of the remainder and throws away the rest. What percent of his apples does the vendor throw?

Solution:

Answer – d) 26% Explanation : Let total apples be 100 first day he throws = 50*20/100 = 10 apples next day he throws = 40*40/100 = 16 apples so total = 26

QUESTION: 13

40% of the women are above 30 years of age and 80 percent of the women are less than or equal to 50 years of age. 20 percent of all women play basketball.If 30 percent of the women above the age of 50 plays basketball, what percent of players are less than or equal to 50 years?

Solution:

Answer – c) 70% Explanation : take total women =100 Women less than or equal to 50 years = 80 and women above 50 years = 20 20 = women plays basketball 30% of the women above 50 plays basketball = 6 So remaining 14 women who plays basketball are less than or equal to 50 years So (14/20)*100 = 70%

QUESTION: 14

Alisha goes to a supermarket and bought things worth rupees 60, out of which 40 paise went on sales tax. If the tax rate is 10 percent, then what was the cost of tax free items?

Solution:

Answer – b) 55.60 Explanation : tax = 40/100 = (10/100)*T, T = 4 so cost of tax free items = 60 – 4 – 0.40 = 55.60

QUESTION: 15

60 percent of the employees of a company are women and 75% of the women earn 20000 or more in a month. Total number of employees who earns more than 20000 per month in the company is 60 percent of the total employees.What fraction of men earns less than 20000 per month?

Solution:

Answer – a) 5/8 Explanation : let total employees are 100 males = 40 and females = 60 (45 women earns more than 20000) total 60 employee earns more than 20000 per month, so number of males earns more than 20000 is 15 so fraction = 25/40 = 5/8

QUESTION: 16

In a library, 30% of the books are in History. 50% of the remaining are in English and 40% of the remaining are in German. The remaining 4200 books are in regional languages. What is the total number of books in library?

Solution:

Answer – c) 20000 Explanation : (70/100)*T*(50/100)*(60/100) = 4200

QUESTION: 17

A got 30% of the maximum marks in an examination and failed by 10 marks.However, B who took the same examination got 40% of the total marks and got 15 marks more than the passing marks. What were the passing marks in the examination?

Solution:

Answer – e) None of these Explanation : (30/100)*T = P -10
(40/100)*T = P + 15
U will get P = 85

QUESTION: 18

The population of a town is 15000. It increases by 10 percent in the first year and 20 percent in the second year. But in the third year it decreases by 10 percent. What will be the population after 3 years.

Solution:

Answer – c) 17820 Explanation : 15000*(11/10)*(12/10)*(9/10) = 17820

QUESTION: 19

30 litre of solution contains alcohol and water in the ratio 2:3. How much alcohol must be added to the solution to make a solution containing 60% of alcohol?

Solution:

Answer – d) 15 Explanation : alcohol = 30*2/5 = 12 and water = 18 litres (12 + x)/(30 +x) = 60/100, we will get x = 15

QUESTION: 20

2000 sweets need to be distributed equally among the school students in such a way that each student gets sweet equal to 20% of total students. Then the number of sweets, each student gets.

Solution:

Answer – b) 100 Explanation : (20/100)*t*t = 2000 (total students = t)