Permutations And Combinations - MCQ 1


20 Questions MCQ Test Quantitative Aptitude for Competitive Examinations | Permutations And Combinations - MCQ 1


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This mock test of Permutations And Combinations - MCQ 1 for Quant helps you for every Quant entrance exam. This contains 20 Multiple Choice Questions for Quant Permutations And Combinations - MCQ 1 (mcq) to study with solutions a complete question bank. The solved questions answers in this Permutations And Combinations - MCQ 1 quiz give you a good mix of easy questions and tough questions. Quant students definitely take this Permutations And Combinations - MCQ 1 exercise for a better result in the exam. You can find other Permutations And Combinations - MCQ 1 extra questions, long questions & short questions for Quant on EduRev as well by searching above.
QUESTION: 1

 How many 3 digit number can be formed with the digits 5, 6, 2, 3, 7 and 9 which are divisible by 5 and none of its digit is repeated?

Solution:

Answer – c) 20 Explanation : _ _ 5
first two places can be filled in 5 and 4 ways respectively so, total number of 3 digit number = 5*4*1 = 20

QUESTION: 2

 In how many different ways can the letter of the word ELEPHANT be arranged so that vowels always occur together?

Solution:

Answer – b) 2160 Explanation : Vowels = E, E and A. They can be arranged in 3!/2! Ways so total ways = 6!*(3!/2!) = 2160

QUESTION: 3

There are 4 bananas, 7 apples and 6 mangoes in a fruit basket. In how many ways can a person make a selection of fruits from the basket.

Solution:

Answer – c) 279 Explanation : Zero or more bananas can be selected in 4 + 1 = 5 ways (0 orange, 1 orange, 2 orange, 3 orange and 4 orange) similarly apples can be selected in 7 +1 = 8 ways and mangoes in 6 +1 = 7 ways so total number of ways = 5*8*7 = 280 but we included a case of 0 orange, 0 apple and 0 mangoes, so we have to subtract this, so 280 – 1 = 279 ways

QUESTION: 4

There are 15 points in a plane out of which 6 are collinear. Find the number of lines that can be formed from 15 points.

Solution:

Answer – c) 91 Explanation : From 15 points number of lines formed = 15c2 6 points are collinear, number of lines formed by these = 6c2 So total lines = 15c2 – 6c2 + 1 = 91

QUESTION: 5

In how many ways 4 Indians, 5 Africans and 7 Japanese be seated in a row so that all person of same nationality sits together

Solution:

Answer – a) 4! 5! 7! 3!
Explanation : 4 Indians can be seated together in 4! Ways, similarly for Africans and Japanese in 5! and 7! respectively. So total ways = 4! 5! 7! 3!

QUESTION: 6

In how many ways 5 Americans and 5 Indians be seated along a circular table, so that they are seated in alternative positions

Solution:

Answer – c) 4! 5!
Explanation : First Indians can be seated along the circular table in 4! Ways and now Americans can be seated in 5! Ways. So 4! 5! Ways

QUESTION: 7

4 matches are to be played in a chess tournament. In how many ways can result be decided?

Solution:

Answer – c) 81 Explanation : Every chess match can have three result i.e. win, loss and draw so now of ways = 3*3*3*3 = 81 ways

QUESTION: 8

There are 6 players in a cricket which is to be sent to Australian tour. The total number of members is 12.

Q. If 2 particular member is always included

Solution:

Answer – a) 210 Explanation : only 4 players to select, so it can be done in 10c4 = 210

QUESTION: 9

There are 6 players in a cricket which is to be sent to Australian tour. The total number of members is 12.

Q. If 3 particular player is always excluded

Solution:

Answer – c) 84 Explanation : 6 players to be selected from remaining 9 players in 9c6 = 84 ways

QUESTION: 10

In a group of 6 boys and 5 girls, 5 students have to be selected. In how many ways it can be done so that at least 2 boys are included

Solution:

Answer – b) 426 Explanation : 6c2*5c3 + 6c3*5c2 + 6c4*5c1 + 6c5

QUESTION: 11

In how many ways can 5 boys and 4 girls can be seated in a row so that they are in alternate position.

Solution:

Answer – b) 2880 Explanation : First boys are seated in 5 position in 5! Ways, now remaining 4 places can be filled by 4 girls in 4! Ways, so number of ways = 5! 4! = 2880

QUESTION: 12

In how many ways 5 African and five Indian can be seated along a circular table, so that they occupy alternate position.

Solution:

Answer – b) 4! 5!
Explanation : First 5 African are seated along the circular table in (5-1)! Ways = 4!. Now Indian can be seated in 5! Ways, so 4! 5!

QUESTION: 13

There is meeting of 20 delegates is to be held in a hotel. In how many ways these delegates can be seated along a round table, if three particular delegates always seat together.

Solution:

Answer – a) 17! 3!
Explanation : Total 20 persons, 3 always seat together, 17 + 1 =18 delegates can be seated in (18 -1)! Ways = 17! And now that three can be arranged in 3! Ways. So, 17! 3!

QUESTION: 14

In how many 8 prizes can be given to 3 boys, if all boys are equally eligible of getting the prize.

Solution:

Answer – a) 512 Explanation : Prizes cab be given in 8*8*8 ways = 512 ways

QUESTION: 15

There are 15 points in a plane out of which 6 are collinear. Find the number of lines that can be formed from 15 points.

Solution:

Answer – c) 91 Explanation : From 15 points number of lines formed = 15c2 6 points are collinear, number of lines formed by these = 6c2 So total lines = 15c2 – 6c2 + 1 = 91

QUESTION: 16

In party there is a total of 120 handshakes. If all the persons shakes hand with every other person. Then find the number of person present in the party.

Solution:

Answer – b) 16 Explanation : Nc2 = 120 (N is the number of persons)

QUESTION: 17

There are 8 boys and 12 girls in a class. 5 students have to be chosen for an educational trip. Find the number of ways in which this can be done if 2 particular girls are always included

Solution:

Answer – b) 816 Explanation : 18c3 = 816 (2 girls already selected)

QUESTION: 18

 In how many different ways the letters of the world INSIDE be arranged in such a way that all vowels always come together

Solution:

Answer – b) 72 Explanation : Three vowels I, I and E can be arranged in 3!/2! Ways, remaining letters and group of vowels can be arranged in 4! Ways. So 4!*3!/2!

QUESTION: 19

How many 3 digit number can be formed by 0, 2, 5, 3, 7 which is divisible by 5 and none of the digit is repeated.

Solution:

Answer – a) 24 Explanation : Let three digits be abc, a can be filled in 4 ways (2,3, 5 and 7) c can be filled in 2 ways (0 or 5) and b can be filled in 3 ways. So, 4*3*2 = 24 ways

QUESTION: 20

In a group of 6 boys and 8 girls, 5 students have to be selected. In how many ways it can be done so that at least 2 boys are included

Solution:

Answer – b) 1526 Explanation : 6c2*5c3 + 6c3*5c2 + 6c4*5c1 + 6c5

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